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Rain on The Roof Summary Analysis and Explanation By Coates Kinney

August 26, 2023August 26, 2023 by Raju

Students can also check English Summary to revise with them during exam preparation.

Rain On The Roof Summary Line By Line Explanation

About the Poet Coates Kinney
The poet, Coates Kinney (1826-1904), is trying to relate the rain to his past memories both sweet and bitter. By listening to the patter of the rain, the poet, lies on his bed, holds his pillow tightly, and then gets lost in the thoughts of his caring and loving mother.

Rain on The Roof Poet Name	Coates Kinney
Born	24 November 1826, Penn Yan, New York, United States
Died	25 January 1904, Ohio, United States
Nationality	American
Education	Antioch College

Rain on the Roof Introduction

This poem tells us about the poet’s sweet memory of his childhood. At night, when dark clouds cover the sky and it rains gently then the poet lies in his cosy bed and listens to the sound of the raindrops falling overhead on the roof of his cottage. The poet remembers the loving look of his mother who used to shower love and affection on her children.

Short Summary of The Poem Rain on The Roof Explanation

In this poem, the poet expresses his love for nature and praises the healing power of rain, especially when heard from a cosy bed in a lovely cottage. The poet is thrilled when he observes the starry sky being overcast with rain-bearing clouds. But he does not like the darkness that spreads all around. It is something like mourning the melancholic spirit of indescribable sadness. Soon it starts raining to compensate it with the spirit of peace for the lonely night at hand.

The poet feels immense pleasure to lie in his cottage-chamber bed with his head pressed against a soft pillow and listen to the sound of the raindrops falling on the tin roof overhead. Every drop of rain falling on the roof makes a tinkling sound that produces an echo in the poet’s heart.

These sounds arouse a thousand imaginations in the poet’s busy mind. The pattering sound of the raindrops also revives a thousand memories of his childhood. One of these memories is related to his dear mother who is not in this world. The poet remembers how she used to give a lovely look at her dear children when she put them to sleep and wished them to have sweet dreams before leaving them to meet again the next morning.

The poet, while listening to the repetitive rhythms of the raindrops falling on the roof of his cottage, can feel the presence of his mother around him. He visualizes her affectionate look bending over him. Thus, he presents rain as a bridging force between his present and past.

FAQs on Rain on the Roof Summary

Question 1.
What is the summary of the rain on the roof?

Answer:
The poem ‘Rain on the Roof’ talks about the poet’s varied reactions to the sound of raindrops falling on the roof of his house. He says that the raindrops at night are like tears shed by the sad, dark night.

Question 2.
What is the main theme of the poem rain on the roof?

Answer:
The theme of the poem is the healing power of rain. The musical sound of raindrops falling on the rooftop at night has the ability to revive sweet memories and rouse fancies in an otherwise busy mind. The rain thus soothes and comforts an overworked mind by taking it back to its lovely past.

Question 3.
What appears when the rain falls on the shingles?

Answer:
When the drops of rainfall on shingles, they make a tinkling sound. The tinkling sound echoes his heart. A thousand old memories weave their air-threads into pattering sounds.

Question 4.
Who comes in the memory of the poet in the poem rain on the roof?

Answer:
The single major memory that comes to the poet is that of his mother and her fond look. The “darling dreamers” are the poet and his siblings in their childhood when they were lovingly put to sleep by their mother.

Question 5.
what do we learn from the poem rain on the roof?

Answer:
The poem ‘The Rain on the Roof’ teaches us that like the rain we should find joy and contentment in making people around us happy.

Question 6.
What Is The Theme of Poem Rain on The Roof?

ਦਾਦੀ ਮਾਂ ਦੀਆਂ ਬਾਤਾਂ Summary in punjabi

Wind Summary Analysis and Explanation By Subramania Bharati

August 26, 2023August 26, 2023 by Raju

Students can also check the English Summary to revise with them during exam preparation.

Wind Summary Analysis and Explanation in English

About the Poet Subramania Bharati
Chinnaswami Subramania Bharathi, also known as Bharathiyar, was a Tamil writer, poet, journalist, Indian independence activist, a social reformer and a polyglot. Popularly known as “Mahakavi Bharathi”, he was a pioneer of modern Tamil poetry.

Poet Name	Subramania Bharati
Born	11 December 1882, Ettaiyapuram
Died	12 September 1921, Chennai
Spouse	Chellamal (m. 1897–1921)
Movies	Bharathi
Parents	Chinnaswami Subramanya Iyer, Elakkumi Ammaal

Summary of The Poem Wind By Subramania Bharati

The poem Wind by Subramania Bharati is originally in Tamil. It was translated in English by A. K. Ramanujan. The poem describes the power of the wind on nature and human life. It focuses on the violent aspect of the wind that causes heavy destruction. The poet tells us that the wind makes fun of the weak people and things, but favors the strong. He, therefore, suggests the reader be strong, both physically and mentally. The wind here is the symbol of hardships and obstacles which human beings have to face in their life. If we remain strong, we can overcome any obstacles.

Wind Summary of the Poem

The poet requests the wind to blow gently. He asks the wind not to break the shutters of the windows, scatter the papers and throw down the books from the shelf. But the wind does not listen to him and turns violent and destructive. It throws down everything and tears the pages of the books. The poet accuses the wind of bringing rain once again. He tells the wind that it always makes fun of weak people and things. It crumbles down weak houses, weak doors, and weak rafters. It tears down weak bodies and fragile hearts. But does no harm to the strong.

The poet says that it is up to the wind god whether it brings destruction or shows mercy on humanity. The poet suggests the reader that to make friends with the wind we need to build strong homes with firm doors. He also suggests people be strong, both physically and mentally to combat and resist the ill effects of the wind. The last four lines of the poem tell us about the nature of the wind.

It blows out those fires which burn with a weak force, but the strong fires turn stronger by the wind. It means that the wind is supportive of those who are already strong and powerful but crushes the weak. A very significant message is hidden in these four lines-strong people are not affected by adversities but the weak do. So, it is good to be a friend of the wind, which is a symbol of hardships and obstacles, because only then we will be able to face tough times.

FAQs on Short Summary of Wind

Q1. What is the summary of the poem’s wind?
Ans: The wind blows out the weak fires but makes the strong fires roar and flourish. Thus, the poem conveys the idea that nobody cares for the weak. Even the wind is on the side of the strong people. We must make ourselves strong to become successful and overcome the challenges in life.

Q2. Which is the best summary of the poem’s wind?
Ans: The poet describes the power of wind in this poem. The wind is compared with force in this poem. The wind can easily break window panes when it blows strongly. The books from the shelf fell down and wind tears apart the pages. It feels like wind enjoys its power and laughs at weaker things.

Q3. Who is the poet of the poem wind?
Ans: “The Wind” (Welsh: Y Gwynt) is a 64-line love poem in the form of a cywydd by the 14th-century Welsh poet Dafydd ap Gwilym. Dafydd is widely seen as the greatest of the Welsh poets, and this is one of his most highly praised works.

Q4. What does the wind god do?
Ans: The wind god breaks the shutters of the windows, scatters the papers, throws the books and tears them. The wind is also responsible for poking weaklings and crashing down houses and doors by winnowing them away.

ਗਾਂਧੀ ਜੀ ਦਾ ਬਚਪਨ Summary in punjabi

The Necklace Summary Analysis and Explanation By Guy De Maupassant

August 26, 2023August 26, 2023 by Raju

Students can also check English Summary to revise with them during exam preparation.

The Necklace Summary Analysis and Explanation By Guy De Maupassant

About the Author
Henri René Albert Guy de Maupassant (5 August 1850 – 6 July 1893) was a French writer, remembered as a master of the short story form, and as a representative of the naturalist school of writers, who depicted human lives and destinies and social forces in disillusioned and often pessimistic terms. He wrote some 300 short stories, six novels, three travel books, and one volume of verse.

Author Name	Guy De Maupassant
Born	5 August 1850, Château de Miromesnil, Tourville-sur-Arques, France
Died	6 July 1893, Passy, Paris, France
Short stories	The Necklace, Boule de Suif, The Horla, Two Friends
Movies	Bel Ami, Masculin Féminin, A Woman’s Life

Short Summary of The Necklace in English

Matilda was a young and pretty lady. She was born into a family of clerks. She was simple and had married a pretty office clerk. She dared not to visit his friendly schoolmate’s house which was richly furnished. One day Mr Loisel and Mme. Loisel get an invitation to dinner from the Minister of Public Instruction.

The husband got elected to get the select invitation but the wife got irritated because she didn’t have proper clothes and jewelry to wear. Her husband gave her money to buy a dress.

At her husband’s suggestion, Mme. Loisel went to Mme Forestier’s house and she got ready to lend her entire jewelry. However, she borrowed only a diamond necklace.

Mme Loisel danced at the; ball with enthusiasm. She looked pretty. It made her swell with joy. Her husband wrapped her shoulders in poor wraps. They hired a carriage and reached home and instantly she noticed that the necklace was missing.

They had looked all around but they didn’t find it, then Loisel found a chaplet of r diamonds in a shop. It looked exactly like the lost necklace and they bought it for thirty-six thousand francs.

They handed the jewel to Mme Forestier but she did not open it. But it took them ten years to repay the borrowed amount from which they bought the necklace.

The Loisels sent away the maid and lived in a rented room in an attic. They led quite a humble and poor life for few years. Thus they repaid their loan. One day Mrs. Loisel happened to meet Mme Forestier while they were taking a walk. Mme Forestier revealed that her false necklace was only worth five hundred francs.

What is the main theme of the necklace?

The main themes in “The Necklace” are greed, deceptive appearances, and beauty and vanity. Greed: Mathilde Loisel’s overwhelming desire to live a life of luxury blinds her to the comforts she already possesses and ultimately leads to her losing what wealth and status she initially has.

What happened in the short story the necklace?

In “The Necklace,” Mathilde Loisel yearns to live a rich and extravagant life. … She loses the necklace, feels compelled to replace it, and spends the next ten years working herself to the bone to pay it off. Ultimately, she learns that the necklace was costume jewelry and not worth a tenth of what the replacement cost.

What message does the story necklace teach us?

The story of ‘The Necklace’ is a satire that gives a strong message on human values. The very first thing that this lesson teaches us is that everyone should be content in life with whatever little that he has. One should live within one’s means or else he invites unnecessary problems, anxieties, and confusion in life.

What lesson does the story The Necklace teach us?

The moral lesson of the story, “the necklace” is that we shouldn’t live a materialistic life as it can make our life’s filled with sorrow and grief.

ਬਾਲਕ ਬੀਬੇ-ਰਾਣੇ Summary in Punjabi

The Road Not Taken Summary Analysis and Explanation

August 26, 2023August 26, 2023 by Raju

Students can also check English Summary to revise with them during exam preparation.

The Road Not Taken Poem Summary Analysis and Explanation

About the Poet Robert Frost
Robert Frost (1874-1963) was an American poet. His work was initially published in England before it was published in the United States. Known for his realistic depictions of rural life and his command of American. He became one of the United States rare “public literary figures, almost an artistic institution.”

Poet Name	Robert Frost
Born	26 March 1874, San Francisco, California, United States
Died	29 January 1963, Boston, Massachusetts, United States
Poems	The Road Not Taken, Fire and Ice Summary
Awards	Robert Frost Medal, Pulitzer Prize for Poetry
Quotes	Two roads diverged in a wood, and I — I took the one less traveled by, and that has made all the difference.

The Road Not Taken Introduction

The Road Not Taken, a poem by Robert Frost is about making choices, and choices that shape our life. “The road’ is the symbol of the choice made by us. Many times, we regret the choice made by us but once the choice has been made, it cannot be altered. Only the future will make it clear whether the decision or choice was right or wrong. What we need is to make a right choice.

The Road Not Taken Summary of the Poem

The poet, while travelling on foot in the woods, comes across a junction where his path diverges into two roads, and he has to choose one of them. Now the poet is in dilemma which road he should take to continue his journey. He stands there for a long time looking at one of the roads. He finds this road as a beaten track. Many people had travelled on it. It was carved into the undergrowth and nothing was visible beyond it.

The poet then looks at the other road which was grassy and seemed less travelled. Being adventurous by nature, he chooses the other road and leaves the first one for some other day, knowing fully well that he will not get a chance to go back to it. The poet feels that this choice will make all the difference to his future life. Later the poet wishes that he had taken the road he left. This is the irony of life. We cannot go through all the roads available to us, no matter whosoever we may wish to.

The poet now feels that after ages from now he would be looking back at this decision with a ‘sigh’. He would be telling that since he had taken the less travelled road, it made all the difference in his life.

Thus, the poet talks about one of the basic problems of human life the problem of making the right choice out of many. We come across many alternatives or choices in life. But we cannot take up all the choices at a time. Neither can we alter the decision once made by us. Therefore, it is important to make a right choice because our future is heavily dependent on it. If we fail to make a right decision, our life would be full of miseries. But if we are fortunate enough to make a right choice, we would be successful.

FAQs on The Road Not Taken Summary

Q1. What is the summary of the road not taken?

Ans: In the poem – ‘The Road Not Taken’, the road symbolizes our life. The poet says that the path that we don’t choose in our life is ‘the road not taken’. He describes his feelings about that choice that he had left in the past. The path which we have chosen, decides our future, our destination.

Q2. What is the meaning of road not taken?

Ans: In “The Road Not Taken,” the meaning of the poem is about a person having to choose between two roads. “Two roads diverged in a yellow wood” and the speaker is torn between which road is the best choice. It is in the autumn of the speaker’s life. He has to choose which road to travel.

Q3. What is the main idea of the road not taken?

Ans: Robert Frost’s central idea is his poem “Road Not Taken” is that by choosing a path that most people don’t, a man can make a big difference in his life. In this poem, a man came to a place where he had to make a choice between two roads.

Q4. What is the form of the road not taken?

Ans: Form. “The Road Not Taken” consists of four stanzas of five lines. The rhyme scheme is ABAAB; the rhymes are strict and masculine, with the notable exception of the last line (we do not usually stress the -ence of difference). There are four stressed syllables per line, varying on an iambic tetrameter base.

What is the summary of road not taken?

The Road Not Taken Summary is a poem that describes the dilemma of a person standing at a road with diversion. This diversion symbolizes real-life situations. Sometimes, in life too there come times when we have to take tough decisions. We could not decide what is right or wrong for us.

What is the main theme of The Road Not Taken?

The major theme in Robert Frost’s “The Road Not Taken,” is about making choices. The speaker in the poem in traveling and comes upon a cross roads or a fork-in-the-road. Here he or she much decide which way to continue traveling.

What is the summary of road not taken Class 9?

The Summary

‘The Road Not Taken’ is an autobiographical poem.; Once, the poet come across a junction when his path diverged into two and he had to take a decision of which road to take. He stood there for a Long time and gave a serious thought to each road. Then he decided to take the road which was less travelled.

What is central idea of the poem?

A poem’s core concept is the subject of the poem, or ‘what it’s about’ if you like. While many shy away from poetry being ‘about’ something, at the end of the day, as it was written, the poet had something in mind, and that something, whatever it was or may have been, is the central concept.

ਆਲੇ-ਭੋਲੇ Summary in punjabi

Bholi Summary Analysis and Explanation

August 26, 2023August 26, 2023 by Raju

Students can also check English Summary to revise with them during exam preparation.

Bholi Summary Analysis and Explanation By Khwaja Ahmad Abbas

About the Author Khwaja Ahmad Abbas

Author Name	Khwaja Ahmad Abbas
Born	7 June 1914, Panipat
Died	1 June 1987, Mumbai
Books	The world is my village, The Thirteenth Victim, Distant Dream 2Nd/ Ed.
Awards	National Film Award for Best Feature Film

Khwaja Ahmad Abbas - bholi summary analysis and explanation class 10 — Khwaja Ahmad Abbas

Bholi Summary of the Lesson

This story is all about a simple village girl named Bholi. Her real name was Sulekha. But fate deceived her and when she was ten months old, she fell off the cot damaging some part of her brain. As a result, she could pick up speech only after she was five years old, but she stammered.

Later on, when she was two years old, she had an attack of small pox that left her with blank spots all over the body. The other children often made fun of her and mimicked her. Therefore, she talked very little.

Numberdar Ramlal has seven children in all—three sons and four daughters. Bholi was the youngest. All other were healthy and strong except Bholi. Bholi was seven years old when a primary school opened in their village.

The tehsildar came to perform the opening ceremony of the school. He told Ramlal that as a revenue official and as a representative of the government in the village, he should send his daughter to the school and set an example before the villagers.

When he consulted his wife about the issue, his wife did not agree with him. Yet she decided to send Bholi to the school.

The next day, Bholi was given a bath, and a new dress to wear. Her mother makes her hair and then she was sent to the school. When her father left her in the school, she sat in a comer in the class. When her teacher asked her name, she stammered and the children started laughing.

At this Bholi started weeping. But the teacher’s voice was soft and soothing. It encouraged her a lot and finally she could tell her full name. Then the teacher told her that if she would come daily to school, she would speak without a stammer and one day she would become the most educated girl in the village.

Then no one will dare to laugh at her. Then they will listen to her carefully.

Years passed and the village now turned into a small town. One night Ramlal consulted his wife about the proposal made by Bishamber, a grocer in the neighboring village. His wife readily agreed to it. Bholi was also listening this conversation. The day of her marriage came.

When the bridegroom was about to garland her, some lady pulled her veil down showing her face to him. The bridegroom had a quick glance at her face and noticed pox marks on her face. At this, he asked Ramlal to give him five thousand rupees as dowry in order to marry that ugly girl.

After some arguments, Ramlal handed over the money to Bishamber. But Bholi asked his father to take money back from him as she did not want to marry that old lame and greedy person. Everybody was surprised because Bholi was not stammering at all. The bridegroom went back with his baraat.

Ramala could not lift his head due to shame and grief. He told Bholi that no one will marry her now. But Bholi said to him that she would serve his parents in their old age and teach in the same school where she had learnt so much.

ਦੇਖੋ, ਠਹਿਰੋ ਤੇ ਜਾਉ Summary in punjabi

DAV Class 6 Maths Chapter 7 Brain Teasers Solutions

August 26, 2023August 26, 2023 by Raju

The DAV Class 6 Maths Solutions and DAV Class 6 Maths Chapter 7 Brain Teasers Solutions of Linear Equations offer comprehensive answers to textbook questions.

DAV Class 6 Maths Ch 7 Brain Teasers Solutions

Question 1.
A. Tick (✓) the correct answer.
Twelve less than four times a number is 20, is represented by:
(i) 12 – 4x = 20
(ii) 20 = – 12 – 4x
(iii) 4x + 12 = 20
(iv) 4x – 12 = 20
Answer:
4x – 12 = 20
Hence, (iv) is the correct option.

(b) Which of the following equations has x = 3 as a solution?
(i) x – 2 = 5
(ii) x + 2 = 5
(iii) 2x + 1 = 0
(iv) x + 4 = 6
Answer:
On putting x = 3inx + 2 = 5,
we get 3 + 2 = 5, which is true.
Hence, (ii) is the correct option.

(c) The linear equation for 2 more than the sum of a and 4 is 8 will be:
(i) 2a + 4 = 8
(ii) 2(a + 4) = 8
(iii) (a + 4) + 2 = 8
(iv) a + 4 = 8
Answer:
(iii) (a + 4) + 2 = 8
Hence, (iii) is the correct option.

(d) Which of the following is an equation of the given sentence?
Anjali is 5 years older than Nanjani.
(i) 5 + A = N
(ii) A + N = 5
(iii) N – 5 = A
(iv) A = N + 5
Answer:
(iv) A = N + 5
Hence, (iv) is the correct option.

(e) Which of the following equations does not have a solution in integers?
(i) x + 1 = 1
(ii) x – 1 = 3
(iii) 2x + 1 = 6
(iv) 1 – x = 5
Answer:
2x + 1 = 6
2x = 6 – 1
⇒ 2x = 5
x = \(\frac{5}{2}\), which is not an integer.
Hence, (iii) is the correct option.

B. Answer the following questions.
(a) If x + 5 = 7, then 2x – 3 = ?
Answer:
x + 5 = 7 (given)
∴ x = 7 – 5 = 2
Then, 2x – 3 = 2(2) – 3 = 4- 3 = 1

(b) What is the solution of the equation 5x + 5 = – 40?
Answer:
5x + 5 = -40
5x = -40 – 5
5x = -45
x = \(\frac{-15}{5}\) = -9

(d) Check if p = 4 is the solution of \(\frac{1}{2}\)(p + 3) = 7.
Answer:
On putting p = 4, we get
\(\frac{1}{2}\)(4 + 3) = \(\frac{1}{2}\) × 7 = \(\frac{7}{2}\)
\(\frac{7}{2}\) ≠ 7

(e) If \(\frac{x+2.4}{2}\) = 3, then find x.
Answer:
\(\frac{x+2.4}{2}\) = 3
x + 2.4 = 6
x = 6 – 2.4
or x = 3.6

Question 2.
Write any five linear equations:
Answer:
(i) x + 5 = 3
(ii) 2x + 3 = 7
(iii) 5x – 1 = 2x + 3
(iv) x + 1 = 2x – 3
(v) 2x + 5 = -4

Question 3.
Which side of the following equations is binomial?
(a) 2x + 1 = 7
(b) \(\frac{4}{5}\)y + 2 = 4
(c) 2(x + 3) = 8
Answer:
(a) LHS (2x + 1) is binomial
(b) LHS (\(\frac{4}{5}\)y + 2) is binomial
(c) LHS 2(x + 3) is binomial

Question 4.
Convert into linear equations:
(a) Thrice a number decreased by 5 is 9
(b) A number multiplied by two is 3 more than the number itself
(c) Twice a number subtracted from 13 is 5
(d) One-ninth of a number added to one is 11.
Answer:
(a) 3x – 5 = 9
(b) 2x = x + 3
(c) 13 – 2x = 5
(d) \(\frac{x}{9}\) + 1 = 11

Question 5.
Solve the following equations
(a) 4x – 3 = 2x + 1
Answer:
4x – 3 = 2x + 1
⇒ 4x -3 + 3 = 2x + l + 3 (Adding 3 to both sides)
⇒ 4x = 2x + 4
⇒ 4x – 2x = 4 (Shifting 2x to LHS)
⇒ 2x = 4
⇒ \(\frac{2 x}{2}=\frac{4}{2}\) (Dividing both sides by 2)
∴ x = 2

(b) 2(x – 5) = 10
Answer:
⇒ 2(x – 5) = 10
⇒ \(\frac{2(x-5)}{2}=\frac{10}{2}\) (Dividing both sides by 2)
⇒ x – 5 = 5
⇒ x – 5 + 5 = 5 + 5 (Adding 5 to both sides)
∴ x = 10

(c) \(\frac{x+8}{2}\) + 8 = 4
Answer:
⇒ \(\frac{x+8}{2}\) × 2 = 4 × 2 (Multiplying both sides by 2)
⇒ x + 8 = 8
⇒ x + 8 – 8 = 8 – 8 (Adding -8 to both sides)
∴ x = 0

(d) 0.5x = 25
Answer:
⇒ \(\frac{0.5 x}{0.5}=\frac{25}{0.5}\) (Dividing both sides by 0.5)
DAV Class 6 Maths Chapter 7 Brain Teasers Solutions 1
∴ x = 50

Question 5.
Solve the following equations and check the solutions:
(a) 1 – 4 x = -11
Answer:
1 – 4x = -11
⇒ -1 + 1- 4x = -11- 1 (Adding —1 to both sides)
⇒ -4x = -12
⇒ \(\frac{-4 x}{-4}=\frac{-12}{-4}\)(Dividing both sides by -4)
∴ x = 3

Check: 1 – 4x = -11
Putting x = 3
1 – 4 × 3 = -11
⇒ 1 – 12 = -11
∴ -11 = -11 (Hence Verified)

(b) y + \(\frac{3}{2}\) = 5
Answer:
DAV Class 6 Maths Chapter 7 Brain Teasers Solutions 2
∴ 5 = 5 (Hence Verified)

Question 6.
Complete the following statements with correct terms and signs:
(a) To solve the equation x + 3 = 8, we first add _____ to both sides.
Answer:
-3

(b) To solve the equation 9y = 72, we _____ LHS and RHS by 9.
Answer:
divide

(d) To solve the equation 2x – 3 = 6, we first add ______ to both sides and then divide both sides by _____.
Answer:
3, 2

(e) The degree of variable in a linear equation is _____
Answer:
1

Additional Questions

Question 1.
Solve the following equations and check.
(a) \(\frac{x-1}{2}\) = 3 = 3
Answer:
\(\frac{x-1}{2}\) = 3 = 3
\(\frac{x-1}{2}\) x 2 = 3 x 2 (Multiplying both sides by 2)
⇒ x – 1 = 6
⇒ x – 1 + 1 = 6 + 1 (Adding 1 to both sides)
x = 7
Check: \(\frac{x-1}{2}\) = 3
Put x = 7
\(\frac{7-1}{2}\) = 3
⇒ \(\frac{6}{2}\) = 3
∴ 3 = 3 (Hence Verified)

(b) \(\frac{2 x+5}{3}\) = 7
\(\frac{2 x+5}{3}\) × 3 = 7 × 3
(Multiplying both sides by 3)
⇒ 2x + 5 = 21
⇒ 2x + 5 – 5 = 21- 5 (Adding -5 to both sides)
⇒ 2x = 16
⇒ \(\frac{2 x}{2}=\frac{16}{2}\) (Dividing both sides by 2)
x = 8
Check: \(\frac{2 \times 8+5}{3}\) = 7
Put x = 8
\(\frac{2 \times 8+5}{3}\) = 7
\(\frac{16+5}{3}\) = 7
\(\frac{21}{3}\) = 7

Question 2.
Find the numerical coefficients in the following terms:
(a) –\(\frac{2}{3}\)xy
(b) –\(\frac{1}{2}\)x<sup>2</sup>y
(c) -5pq
(d) -p
(e) 0
Answer:
(a) –\(\frac{2}{3}\)
(b) –\(\frac{1}{2}\)
(c) -5
(d) -1
(e) 0

Question 3.
Convert into linear equations:
(a) 5 is added to twice a number gives 17.
(b) Two-third of a number is added to itself gives 15.
(c) Twice a number subtracted from 13 is 5.
(d) One-eighth of a number is 2.
Answer:
(a) 2x + 5 = 17
(b) \(\frac{2}{3}\)x + x = 15
(c) 13 – 2x = 5
(d) \(\frac{1}{8}\)x = 2

Question 4.
Convert the following equations in statements:
(a) 2x + 5 = 11
(b) x + 5 = 15
(c) \(\frac{x}{2}\) – 5 = 7
(d) \(\frac{x}{2}\) – \(\frac{x}{3}\) = 1
(e) \(\frac{2y}{3}\) = 4
(f) 7y = 21
Answer:
(a) 5 is added to twice a number is 11.
(b) A number more than 5 is 15.
(c) 5 less than half of a number is 7.
(d) Difference between half and one-third of a number is 1.
(e) Two-third of a number is 4.
(f) Seven times a number is 21.

Question 5.
Fill in the blanks:
(a) To solve 3x + 5 = 10, we first add to both sides and then divide by _____
Answer:
– 5, 3

(b) The solution of = 6 is _____
Answer:
9

(d) The number which satisfy the equation 3x + \(\frac{1}{2}=\frac{7}{2}\) is _____
Answer:
1

(e) The degree of the variable in a linear equation is __________.
Answer:
1

DAV Class 5 Maths Chapter 13 Worksheet 2 Solutions

August 25, 2023 by Raju

The DAV Books Solutions Class 5 Maths and DAV Class 5 Maths Chapter 13 Worksheet 2 Solutions of Simple Interest offer comprehensive answers to textbook questions.

DAV Class 5 Maths Ch 13 Worksheet 2 Solutions

Question 1.
Find the simple interest at the end of one year for the following:
(a) ₹ 400 at 5% interest per annum.
Solution:
5% = \(\frac{5}{100}\) means ₹ 5 interest for every ₹ 100 deposited.
Simple interest on ₹ 1 for one year = ₹ \(\frac{5}{100}\)
Simple interest on ₹ 400 for one year = \(\frac{5}{100}\) × 400 = ₹ 20

(b) ₹ 1,800 at 12% interest per annum.
Solution:
12% = \(\frac{12}{100}\) means ₹ 12 interest for every ₹ 100 deposited
Simple interest on ₹ 1 for one year = ₹ \(\frac{12}{100}\)
Simple interest on ₹ 1,800 for one year = \(\frac{12}{100}\) × 1800 = ₹ 216

(c) ₹ 2,500 at 4\(\frac{1}{2}\)% interest per annum.
Solution:
4\(\frac{1}{2}\)% = \(\frac{9}{2}\)% = \(\frac{9}{200}\) means ₹ 9 interest for every ₹ 200 deposited
Simple interest on ₹ 1 for one year = ₹ \(\frac{9}{200}\)
Simple interest on ₹ 2,500 for one year = ₹ \(\frac{9}{200}\) × 2500
= ₹ \(\frac{225}{2}\)
= ₹ 112.5

(d) ₹ 3,200 at 6\(\frac{1}{2}\)% interest per annum.
Solution:
6\(\frac{1}{2}\)% = \(\frac{13}{2}\)% = \(\frac{13}{200}\) means ₹ 13 interest for every ₹ 200 deposited
Simple interest on ₹ 1 for one year = ₹ \(\frac{13}{200}\)
Simple interest on ₹ 3,200 for one year = ₹ \(\frac{13}{200}\) × 3200 = ₹ 208

Question 2.
Complete the table by calculating the simple interest.
DAV Class 5 Maths Chapter 13 Worksheet 2 Solutions Q2
Solution:
(a) P = ₹ 600, R = 7% per annum, T = 2 years
Simple Interest = P × R × T
= 600 × \(\frac{7}{100}\) × 2
= ₹ 84

(b) P = ₹ 500, R = 8\(\frac{1}{2}\)% = \(\frac{17}{2}\)% = \(\frac{17}{200}\) per annum, T = 2 years
Simple Interest = P × R × T
= 500 × \(\frac{17}{200}\) × 2
= ₹ 85

(c) P = ₹ 3,000, R = 12% = \(\frac{12}{100}\) per annum, T = 3\(\frac{1}{2}\) years = \(\frac{7}{2}\) years
Simple interest = P × R × T
= 3,000 × \(\frac{12}{100} \times \frac{7}{2}\)
= ₹ 1,260

(d) P = ₹ 2,500, R = 7\(\frac{1}{2}\)% = \(\frac{15}{2}\)% = \(\frac{15}{200}\) per annum, T = 2\(\frac{1}{2}\) years = \(\frac{5}{2}\) years
Simple interest = P × R × T
= 2,500 × \(\frac{15}{200} \times \frac{5}{2}\)
= \(\frac{1875}{4}\)
= ₹ 468.75

Question 3.
Solve the following questions:
(a) A man deposited ₹ 4,500 in a bank which paid him an interest of 11% per annum. How much simple interest will he get at the end of five years?
Solution:
Principal = ₹ 4,500
Rate of interest = 11% per annum = \(\frac{11}{100}\) per annum
Time = 5 years
SI = P × R × T
= \(\frac{4500 \times 11 \times 5}{100}\)
= ₹ 2475
He will get a simple interest of ₹ 2475 at the end of five years.

(b) Rahul borrowed ₹ 650 from Sohan at 8% interest per annum. Find the simple interest Rahul has to pay Sohan after 4\(\frac{1}{2}\) years.
Solution:
Principal = ₹ 650
Rate of interest = 8% per annum = \(\frac{8}{100}\) per annum
Time = 4\(\frac{1}{2}\) years = \(\frac{9}{2}\) years
SI = P × R × T
= 650 × \(\frac{8}{100} \times \frac{9}{2}\)
= \(\frac{13 \times 4 \times 9}{2}\)
= ₹ 234
Rahul has to pay simple interest of ₹ 234 to Sohan after 4\(\frac{1}{2}\) years.

(c) Ramlal borrowed ₹ 3,000 from Arun to purchase a tractor. Arun charged him an interest of 4\(\frac{1}{2}\)% per annum. How much simple interest will Ramlal pay to Arun after three years?
Solution:
Principal = ₹ 3,000
Rate of interest = 4\(\frac{1}{2}\)% = \(\frac{9}{2}\)% = \(\frac{9}{200}\) per annum
Time = 3 years
SI = P × R × T
= 3,000 × \(\frac{9}{200}\) × 3
= 15 × 27
= ₹ 405
Ramlal has to pay a simple interest of ₹ 405 to Arun after three years.

DAV Class 5 Maths Chapter 13 Worksheet 2 Notes

Simple Interest
The calculation of simple interest depends on three factors:

Principal
Rate of Interest
Time

Example 1.
Calculate the simple interest on ₹ 600 at 12% interest per year.
Solution:
Simple interest on ₹ 100 for one year = ₹ 12
Simple interest on ₹ 1 for one year = ₹ \(\frac{12}{100}\)
Simple interest on ₹ 600 for one year = ₹ \(\frac{12}{100}\) × 600 = ₹ 72
So, the interest at the end of one year will be ₹ 72.

Simple Interest = Principal × Rate of Interest × Time
SI = P × R × T

Example 2.
Mr. Sushil deposited ₹ 900 in a bank at 3\(\frac{1}{2}\)% rate of interest per annum. Calculate the simple interest he will get after 2\(\frac{1}{2}\) years.
Solution:
Principal = ₹ 900
Rate of interest = 3\(\frac{1}{2}\)% per annum
= \(\frac{7}{2}\)% per annum 2
= \(\frac{7}{200}\) per annum
Time = 2\(\frac{1}{2}\) years = \(\frac{5}{2}\) years
Simple Interest = P × R × T
= 900 × \(\frac{7}{200} \times \frac{5}{2}\)
= \(\frac{315}{4}\)
= ₹ 78.75

DAV Class 4 Maths Book Solutions Pdf – DAV Class 4 Maths Solutions

September 6, 2023August 25, 2023 by Raju

DAV Class 4 Maths Book Solutions Pdf: Have you been stuck in the middle of your exam preparation? If yes, then make use of our free Primary Mathematics DAV Maths Book Class 4 Solutions. This page has chapter-wise DAV Books Solutions Class 4 Maths in pdf format for easy access. Use this free tool and improve your subject knowledge & problem-solving skills.

Students can obtain the benefits of DAV Class 4 Maths Book Solutions here. Download DAV Class 4 Maths Book Solutions for free of cost.

DAV Public School Class 4 Maths Book Solutions – DAV Maths Book Class 4 Solutions

Practice all maths topics of the DAV Public School Class 4 Maths Book Pdf with this guide. Tap on the quick links to navigate to the respective chapter of DAV Class 4 Maths Worksheets and solve all the questions easily. After practicing the DAV Class 4 Maths topics, you can get an idea of the subject.

Also, Check:

DAV Books Solutions Class 4

DAV Class 4 Math Book Pdf Chapter 1 Numbers up to 999999

Class 4 DAV Maths Book Pdf Chapter 2 Addition and Subtraction

DAV Public School Class 4 Maths Book Pdf Chapter 3 Multiplication

DAV Class 4 Maths Book Solutions Pdf Chapter 4 Division

DAV 4th Class Maths Book Chapter 5 Length

Primary Mathematics Class 4 DAV Pdf Chapter 6 Weight

Class 4 Maths DAV School Chapter 7 Capacity

DAV Maths Book Class 4 Chapter 8 Time and Calendar

Class 4 Maths Book DAV Chapter 9 Fractions

DAV Maths Book Class 4 Pdf Chapter 10 Angles

DAV Class 4 Maths Worksheets Chapter 11 Perimeter

DAV Class 4th Maths Book Chapter 12 Area

DAV Class 4 Maths Book Pdf Chapter 13 Volume

DAV School Class 4 Maths Book Pdf Chapter 14 Fun with Patterns

Advantages of DAV Class 4 Maths Book Solutions

This section tells how important to practice the questions in the DAV Class 4 Maths Solutions. So, don’t skip these points while referring to the DAV Maths Class 4 Solutions. Below covered are the advantages of the answer key.

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Students can also find the chapter-wise DAV Books Solutions Class 4 Maths from this article for free.
The solutions provided here are as per the subject experts’ guidance.
A detailed explanation is provided for all questions in the DAV Class 4 Math Book Pdf. Also, you can practice more questions by checking the assessment tests, practice tests, and so on.

In a Nutshell

Hoping that the details covered here about DAV Class 4 Maths Book Solutions are useful for you. You can stay in touch with our site to learn more related articles in one place. If you have any queries, write below. For other subject solutions, check out our DAV Solutions @learncram.com website.

DAV Class 6 Maths Chapter 7 Worksheet 5 Solutions

August 25, 2023 by Raju

The DAV Class 6 Maths Solutions and DAV Class 6 Maths Chapter 7 Worksheet 5 Solutions of Linear Equations offer comprehensive answers to textbook questions.

DAV Class 6 Maths Ch 7 WS 5 Solutions

Solve and check the solutions in the following equations:

Question 1.
x + 7 = 9
Answer:
x + 7 = 9
⇒ x + 7 – 7 = 9 – 7 (Adding -7 to both sides)
x = 2
Check: x + 7 = 9
2 + 7 = 9
9 = 9 (Hence Verified)

Question 2.
\(\frac{x}{4}\) = 25 4
Answer:
\(\frac{x}{4}\) = 25
⇒ \(\frac{x}{4}\) × 4 = 25 × 4 (Multiplying both sides by 4)
x = 100
Check: \(\frac{x}{4}\) = 25
⇒ \(\frac{100}{4}\) =25
25 = 25 (Hence Verified)

Question 3.
9y = -135
Answer:
9y = -135
9y _ -135 ^9 9
∴ y = -15
Check: 9y = -135
⇒ 9 x -15 = -135
-135 = -135 (Hence Verified)

Question 4.
15 – x = 4
Answer:
15 – x = 4
⇒ -15 + 15 – x = -15 + 4 (Adding -15 to both sides)
-x = -11 (Dividing both sides by -1)
⇒ \(\frac{-x}{-1}=\frac{-11}{-1}\)
x = 11
Check: 15 – x = 4
15 – 11 = 4
4 = 4 (Hence Verified)

Question 5.
3(x – 3) = 15
Answer:
3(x – 3) = 15
⇒ \(\frac{3(x-3)}{3}=\frac{15}{3}\) (Dividing both sides by 3)
⇒ x – 3 = 5
⇒ x – 3 + 3 = 5 + 3 (Adding 3 to both sides)
x = 8
Check: 3(x – 3) = 15 3(8 – 3) = 15
⇒ 3 x 5 = 15
⇒ 15 = 15 (Hence Verified)

Question 6.
7y + 3 = 9
Answer:
7y + 3 = 9
⇒ 7y + 3 – 3 = 9 – 3 (Adding -3 to both sides)
⇒ 7y = 6
⇒ \(\frac{7 y}{7}=\frac{6}{7}\) (Dividing both sides by 7)
Check: 7y + 3 = 9
⇒ 7 × \(\frac{6}{7}\) + 3 = 9
⇒ 6 + 3 = 9
9 = 9 (Hence Verified)

DAV Class 6 Maths Chapter 8 Value Based Questions

Question 1.
In a school out of 250 students of Class- VI, x students visited an old age home. They entertained them with dance and music, they discussed about their families and children, helped them in cleaning their cupboards. But 75 children refused to visit.
(a) Find the number of students who visited the old age home.
(b) What value is shown by those students?
Answer:
(a) x + 75 = 250
∴ x = 250 – 75
x = 175
(b) Social, helpful, or respect for elders, etc.

Question 2.
During an earthquake, x students from Class-VI donated ₹ 25 each and 25 students from Class-V donated ₹ 50 each. If total amount collected is ? 2000.
(a) Find the number of students of Class- VI who donated.
(b) What value is depicted by students?
Answer:
(a) Amount donated by one student of
Class-V = ₹ 50
Amount donated by 25 students of Class-V = ₹ 50 x 25 = 1250
Amount donated by one student of Class-VI = ₹ 25
Amount donated by x students of Class VI =₹ 25x
Total amount = Amount donated by Class-V students + Amount donated by Class-VI students Total amount
= ₹ 2000
∴ 2000 = 1250 + 25x
or 750 = 25x
∴ 30 = x
Thus, the no. of students of Class VI = 30

(b) Social or helpful, etc.

DAV Class 6 Maths Chapter 7 Worksheet 4 Solutions

August 25, 2023 by Raju

The DAV Class 6 Maths Solutions and DAV Class 6 Maths Chapter 7 Worksheet 4 Solutions of Linear Equations offer comprehensive answers to textbook questions.

DAV Class 6 Maths Ch 7 WS 4 Solutions

Solve the following equations:

Question 1.
2x + 1 = 5
Answer:
2x + 1 = 5
2x + 1 – 1 = 5 – 1 (Subtracting 1 from both sides)
⇒ 2x = 4 ⇒ \(\frac{2 x}{2}=\frac{4}{2}\)
(Dividing both sides by 2)
x = 2

Question 2.
6y – 5 = 19
Answer:
6y – 5 = 19
⇒ 6y – 5 + 5 = 19 + 5 (Adding 5 to both sides)
⇒ 6y = 24
⇒ \(\frac{6 y}{6}=\frac{24}{6}\) (Dividing both sides by 6)
⇒ y = 4

Question 3.
3 + 4y = – 5
Answer:
3 + 4y = -5
⇒ -3 + 3 + 4y = -5 – 3 (Adding -3 to both sides)
⇒ 4y = -8
⇒ \(\frac{4 y}{4}=\frac{-8}{4}\) (Dividing both sides by 4)
y = -2

Question 4.
\(\frac{2}{3}\)p = 6
Answer:
\(\frac{2}{3}\)p = 6
⇒ \(\frac{2}{3}\)p × 3 = 6 × 3
⇒ 2p = 18
⇒ \(\frac{2 p}{2}=\frac{18}{2}\) (Dividing both sides by 2)
∴ p = 9

Question 5.
5y + 10 = 4y – 10
Answer:
5y + 10 = 4y – 10
⇒ 5y + 10 – 10 = 4y – 10 – 10 (Adding -10 both sides)
⇒ 5y = 4y – 20
⇒ 5y – 4y = -20
⇒ y = -20

Question 6.
\(\frac{1}{2}\)x + 3 = 5
Answer:
\(\frac{1}{2}\)x + 3 = 5
⇒ \(\frac{1}{2}\)x + 3 – 3 = 5 – 3 (Adding -3 to both sides)
⇒ \(\frac{1}{2}\)x = 2
⇒ \(\frac{1}{2}\)x × 2 = 2 × 2 (Multiply both sides by 2)
∴ x = 4

Question 7.
3(x + 1) = 6
Answer:
3(x + 1) = 6
⇒ \(\frac{3(x+1)}{3}=\frac{6}{3}\) (Dividing both sides by 3)
⇒ x + 1 = 2
⇒ x + 1 – 1 = 2 – 1 (Adding -1 to both sides)
⇒ x = 1

Question 8.
4(x – 2) = -8
Answer:
4(x – 2) = -8
⇒ \(\frac{4(x-2)}{4}=\frac{-8}{4}\)
(Dividing both sides by 4)
⇒ x – 2 = -2
⇒ x – 2 + 2 = -2 + 2 (Adding 2 to both sides)
∴ x = 0

Question 9.
3x + 8 = 5x + 2
Answer:
3x + 8 = 5x + 2
⇒ 3x + 8 – 8 = 5x + 2 – 8
(Adding -8 to both sides)
⇒ 3x = 5x – 6
⇒ 3x – 5x = -6 (Shifting 5x to LHS)
⇒ -2x = -6
⇒ \(\frac{-2 x}{-2}=\frac{-6}{-2}\) (Dividing both sides by -2)
x = 3

Question 10.
\(\frac{1}{3}\)x + 11 = 14
Answer:
\(\frac{1}{3}\)x + 11 = 14
⇒ \(\frac{1}{3}\)x + 11 – 11 = 14 – 11 (Adding -11 to both sides)
⇒ \(\frac{1}{3}\)x = 3
⇒ \(\frac{1}{3}\)x × 3 = 3 × 3 (Multiplying both sides by 3)
∴ x = 9

Question 11.
\(\frac{x-5}{4}\) = 3
Answer:
\(\frac{x-5}{4}\) = 3
\(\frac{x-5}{4}\) × 4 = 3 × 4 (Multiplying both sides by 4)
⇒ x – 5 = 12
⇒ x – 5 + 5 = 12 + 5 (Adding 5 to both sides)
∴ x = 17

Question 12.
\(\frac{z+3}{4}\) = 17
Answer:
\(\frac{z+3}{4}\) = 17
⇒ \(\frac{z+3}{4}\) × 4 = 17 × 4 (Multiplying both sides by 4)
⇒ z + 3 = 68
⇒ z + 3 – 3 = 68 – 3 (Adding -3 to both sides)
⇒ z = 6