The DAV Books Solutions Class 5 Maths and **DAV Class 5 Maths Chapter 13 Worksheet 2** Solutions of Simple Interest offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 13 Worksheet 2 Solutions

Question 1.

Find the simple interest at the end of one year for the following:

(a) ₹ 400 at 5% interest per annum.

Solution:

5% = \(\frac{5}{100}\) means ₹ 5 interest for every ₹ 100 deposited.

Simple interest on ₹ 1 for one year = ₹ \(\frac{5}{100}\)

Simple interest on ₹ 400 for one year = \(\frac{5}{100}\) × 400 = ₹ 20

(b) ₹ 1,800 at 12% interest per annum.

Solution:

12% = \(\frac{12}{100}\) means ₹ 12 interest for every ₹ 100 deposited

Simple interest on ₹ 1 for one year = ₹ \(\frac{12}{100}\)

Simple interest on ₹ 1,800 for one year = \(\frac{12}{100}\) × 1800 = ₹ 216

(c) ₹ 2,500 at 4\(\frac{1}{2}\)% interest per annum.

Solution:

4\(\frac{1}{2}\)% = \(\frac{9}{2}\)% = \(\frac{9}{200}\) means ₹ 9 interest for every ₹ 200 deposited

Simple interest on ₹ 1 for one year = ₹ \(\frac{9}{200}\)

Simple interest on ₹ 2,500 for one year = ₹ \(\frac{9}{200}\) × 2500

= ₹ \(\frac{225}{2}\)

= ₹ 112.5

(d) ₹ 3,200 at 6\(\frac{1}{2}\)% interest per annum.

Solution:

6\(\frac{1}{2}\)% = \(\frac{13}{2}\)% = \(\frac{13}{200}\) means ₹ 13 interest for every ₹ 200 deposited

Simple interest on ₹ 1 for one year = ₹ \(\frac{13}{200}\)

Simple interest on ₹ 3,200 for one year = ₹ \(\frac{13}{200}\) × 3200 = ₹ 208

Question 2.

Complete the table by calculating the simple interest.

Solution:

(a) P = ₹ 600, R = 7% per annum, T = 2 years

Simple Interest = P × R × T

= 600 × \(\frac{7}{100}\) × 2

= ₹ 84

(b) P = ₹ 500, R = 8\(\frac{1}{2}\)% = \(\frac{17}{2}\)% = \(\frac{17}{200}\) per annum, T = 2 years

Simple Interest = P × R × T

= 500 × \(\frac{17}{200}\) × 2

= ₹ 85

(c) P = ₹ 3,000, R = 12% = \(\frac{12}{100}\) per annum, T = 3\(\frac{1}{2}\) years = \(\frac{7}{2}\) years

Simple interest = P × R × T

= 3,000 × \(\frac{12}{100} \times \frac{7}{2}\)

= ₹ 1,260

(d) P = ₹ 2,500, R = 7\(\frac{1}{2}\)% = \(\frac{15}{2}\)% = \(\frac{15}{200}\) per annum, T = 2\(\frac{1}{2}\) years = \(\frac{5}{2}\) years

Simple interest = P × R × T

= 2,500 × \(\frac{15}{200} \times \frac{5}{2}\)

= \(\frac{1875}{4}\)

= ₹ 468.75

Question 3.

Solve the following questions:

(a) A man deposited ₹ 4,500 in a bank which paid him an interest of 11% per annum. How much simple interest will he get at the end of five years?

Solution:

Principal = ₹ 4,500

Rate of interest = 11% per annum = \(\frac{11}{100}\) per annum

Time = 5 years

SI = P × R × T

= \(\frac{4500 \times 11 \times 5}{100}\)

= ₹ 2475

He will get a simple interest of ₹ 2475 at the end of five years.

(b) Rahul borrowed ₹ 650 from Sohan at 8% interest per annum. Find the simple interest Rahul has to pay Sohan after 4\(\frac{1}{2}\) years.

Solution:

Principal = ₹ 650

Rate of interest = 8% per annum = \(\frac{8}{100}\) per annum

Time = 4\(\frac{1}{2}\) years = \(\frac{9}{2}\) years

SI = P × R × T

= 650 × \(\frac{8}{100} \times \frac{9}{2}\)

= \(\frac{13 \times 4 \times 9}{2}\)

= ₹ 234

Rahul has to pay simple interest of ₹ 234 to Sohan after 4\(\frac{1}{2}\) years.

(c) Ramlal borrowed ₹ 3,000 from Arun to purchase a tractor. Arun charged him an interest of 4\(\frac{1}{2}\)% per annum. How much simple interest will Ramlal pay to Arun after three years?

Solution:

Principal = ₹ 3,000

Rate of interest = 4\(\frac{1}{2}\)% = \(\frac{9}{2}\)% = \(\frac{9}{200}\) per annum

Time = 3 years

SI = P × R × T

= 3,000 × \(\frac{9}{200}\) × 3

= 15 × 27

= ₹ 405

Ramlal has to pay a simple interest of ₹ 405 to Arun after three years.

**DAV Class 5 Maths Chapter 13 Worksheet 2 Notes**

**Simple Interest**

The calculation of simple interest depends on three factors:

- Principal
- Rate of Interest
- Time

Example 1.

Calculate the simple interest on ₹ 600 at 12% interest per year.

Solution:

Simple interest on ₹ 100 for one year = ₹ 12

Simple interest on ₹ 1 for one year = ₹ \(\frac{12}{100}\)

Simple interest on ₹ 600 for one year = ₹ \(\frac{12}{100}\) × 600 = ₹ 72

So, the interest at the end of one year will be ₹ 72.

Simple Interest = Principal × Rate of Interest × Time

SI = P × R × T

Example 2.

Mr. Sushil deposited ₹ 900 in a bank at 3\(\frac{1}{2}\)% rate of interest per annum. Calculate the simple interest he will get after 2\(\frac{1}{2}\) years.

Solution:

Principal = ₹ 900

Rate of interest = 3\(\frac{1}{2}\)% per annum

= \(\frac{7}{2}\)% per annum 2

= \(\frac{7}{200}\) per annum

Time = 2\(\frac{1}{2}\) years = \(\frac{5}{2}\) years

Simple Interest = P × R × T

= 900 × \(\frac{7}{200} \times \frac{5}{2}\)

= \(\frac{315}{4}\)

= ₹ 78.75