The DAV Books Solutions Class 5 Maths and DAV Class 5 Maths Chapter 13 Worksheet 2 Solutions of Simple Interest offer comprehensive answers to textbook questions.
DAV Class 5 Maths Ch 13 Worksheet 2 Solutions
Question 1.
Find the simple interest at the end of one year for the following:
(a) ₹ 400 at 5% interest per annum.
Solution:
5% = \(\frac{5}{100}\) means ₹ 5 interest for every ₹ 100 deposited.
Simple interest on ₹ 1 for one year = ₹ \(\frac{5}{100}\)
Simple interest on ₹ 400 for one year = \(\frac{5}{100}\) × 400 = ₹ 20
(b) ₹ 1,800 at 12% interest per annum.
Solution:
12% = \(\frac{12}{100}\) means ₹ 12 interest for every ₹ 100 deposited
Simple interest on ₹ 1 for one year = ₹ \(\frac{12}{100}\)
Simple interest on ₹ 1,800 for one year = \(\frac{12}{100}\) × 1800 = ₹ 216
(c) ₹ 2,500 at 4\(\frac{1}{2}\)% interest per annum.
Solution:
4\(\frac{1}{2}\)% = \(\frac{9}{2}\)% = \(\frac{9}{200}\) means ₹ 9 interest for every ₹ 200 deposited
Simple interest on ₹ 1 for one year = ₹ \(\frac{9}{200}\)
Simple interest on ₹ 2,500 for one year = ₹ \(\frac{9}{200}\) × 2500
= ₹ \(\frac{225}{2}\)
= ₹ 112.5
(d) ₹ 3,200 at 6\(\frac{1}{2}\)% interest per annum.
Solution:
6\(\frac{1}{2}\)% = \(\frac{13}{2}\)% = \(\frac{13}{200}\) means ₹ 13 interest for every ₹ 200 deposited
Simple interest on ₹ 1 for one year = ₹ \(\frac{13}{200}\)
Simple interest on ₹ 3,200 for one year = ₹ \(\frac{13}{200}\) × 3200 = ₹ 208
Question 2.
Complete the table by calculating the simple interest.
Solution:
(a) P = ₹ 600, R = 7% per annum, T = 2 years
Simple Interest = P × R × T
= 600 × \(\frac{7}{100}\) × 2
= ₹ 84
(b) P = ₹ 500, R = 8\(\frac{1}{2}\)% = \(\frac{17}{2}\)% = \(\frac{17}{200}\) per annum, T = 2 years
Simple Interest = P × R × T
= 500 × \(\frac{17}{200}\) × 2
= ₹ 85
(c) P = ₹ 3,000, R = 12% = \(\frac{12}{100}\) per annum, T = 3\(\frac{1}{2}\) years = \(\frac{7}{2}\) years
Simple interest = P × R × T
= 3,000 × \(\frac{12}{100} \times \frac{7}{2}\)
= ₹ 1,260
(d) P = ₹ 2,500, R = 7\(\frac{1}{2}\)% = \(\frac{15}{2}\)% = \(\frac{15}{200}\) per annum, T = 2\(\frac{1}{2}\) years = \(\frac{5}{2}\) years
Simple interest = P × R × T
= 2,500 × \(\frac{15}{200} \times \frac{5}{2}\)
= \(\frac{1875}{4}\)
= ₹ 468.75
Question 3.
Solve the following questions:
(a) A man deposited ₹ 4,500 in a bank which paid him an interest of 11% per annum. How much simple interest will he get at the end of five years?
Solution:
Principal = ₹ 4,500
Rate of interest = 11% per annum = \(\frac{11}{100}\) per annum
Time = 5 years
SI = P × R × T
= \(\frac{4500 \times 11 \times 5}{100}\)
= ₹ 2475
He will get a simple interest of ₹ 2475 at the end of five years.
(b) Rahul borrowed ₹ 650 from Sohan at 8% interest per annum. Find the simple interest Rahul has to pay Sohan after 4\(\frac{1}{2}\) years.
Solution:
Principal = ₹ 650
Rate of interest = 8% per annum = \(\frac{8}{100}\) per annum
Time = 4\(\frac{1}{2}\) years = \(\frac{9}{2}\) years
SI = P × R × T
= 650 × \(\frac{8}{100} \times \frac{9}{2}\)
= \(\frac{13 \times 4 \times 9}{2}\)
= ₹ 234
Rahul has to pay simple interest of ₹ 234 to Sohan after 4\(\frac{1}{2}\) years.
(c) Ramlal borrowed ₹ 3,000 from Arun to purchase a tractor. Arun charged him an interest of 4\(\frac{1}{2}\)% per annum. How much simple interest will Ramlal pay to Arun after three years?
Solution:
Principal = ₹ 3,000
Rate of interest = 4\(\frac{1}{2}\)% = \(\frac{9}{2}\)% = \(\frac{9}{200}\) per annum
Time = 3 years
SI = P × R × T
= 3,000 × \(\frac{9}{200}\) × 3
= 15 × 27
= ₹ 405
Ramlal has to pay a simple interest of ₹ 405 to Arun after three years.
DAV Class 5 Maths Chapter 13 Worksheet 2 Notes
Simple Interest
The calculation of simple interest depends on three factors:
- Principal
- Rate of Interest
- Time
Example 1.
Calculate the simple interest on ₹ 600 at 12% interest per year.
Solution:
Simple interest on ₹ 100 for one year = ₹ 12
Simple interest on ₹ 1 for one year = ₹ \(\frac{12}{100}\)
Simple interest on ₹ 600 for one year = ₹ \(\frac{12}{100}\) × 600 = ₹ 72
So, the interest at the end of one year will be ₹ 72.
Simple Interest = Principal × Rate of Interest × Time
SI = P × R × T
Example 2.
Mr. Sushil deposited ₹ 900 in a bank at 3\(\frac{1}{2}\)% rate of interest per annum. Calculate the simple interest he will get after 2\(\frac{1}{2}\) years.
Solution:
Principal = ₹ 900
Rate of interest = 3\(\frac{1}{2}\)% per annum
= \(\frac{7}{2}\)% per annum 2
= \(\frac{7}{200}\) per annum
Time = 2\(\frac{1}{2}\) years = \(\frac{5}{2}\) years
Simple Interest = P × R × T
= 900 × \(\frac{7}{200} \times \frac{5}{2}\)
= \(\frac{315}{4}\)
= ₹ 78.75