The DAV Class 6 Maths Solutions and DAV Class 6 Maths Chapter 7 Worksheet 5 Solutions of Linear Equations offer comprehensive answers to textbook questions.
DAV Class 6 Maths Ch 7 WS 5 Solutions
Solve and check the solutions in the following equations:
Question 1.
x + 7 = 9
Answer:
x + 7 = 9
⇒ x + 7 – 7 = 9 – 7 (Adding -7 to both sides)
x = 2
Check: x + 7 = 9
2 + 7 = 9
9 = 9 (Hence Verified)
Question 2.
\(\frac{x}{4}\) = 25 4
Answer:
\(\frac{x}{4}\) = 25
⇒ \(\frac{x}{4}\) × 4 = 25 × 4 (Multiplying both sides by 4)
x = 100
Check: \(\frac{x}{4}\) = 25
⇒ \(\frac{100}{4}\) =25
25 = 25 (Hence Verified)
Question 3.
9y = -135
Answer:
9y = -135
9y _ -135 ^9 9
∴ y = -15
Check: 9y = -135
⇒ 9 x -15 = -135
-135 = -135 (Hence Verified)
Question 4.
15 – x = 4
Answer:
15 – x = 4
⇒ -15 + 15 – x = -15 + 4 (Adding -15 to both sides)
-x = -11 (Dividing both sides by -1)
⇒ \(\frac{-x}{-1}=\frac{-11}{-1}\)
x = 11
Check: 15 – x = 4
15 – 11 = 4
4 = 4 (Hence Verified)
Question 5.
3(x – 3) = 15
Answer:
3(x – 3) = 15
⇒ \(\frac{3(x-3)}{3}=\frac{15}{3}\) (Dividing both sides by 3)
⇒ x – 3 = 5
⇒ x – 3 + 3 = 5 + 3 (Adding 3 to both sides)
x = 8
Check: 3(x – 3) = 15 3(8 – 3) = 15
⇒ 3 x 5 = 15
⇒ 15 = 15 (Hence Verified)
Question 6.
7y + 3 = 9
Answer:
7y + 3 = 9
⇒ 7y + 3 – 3 = 9 – 3 (Adding -3 to both sides)
⇒ 7y = 6
⇒ \(\frac{7 y}{7}=\frac{6}{7}\) (Dividing both sides by 7)
Check: 7y + 3 = 9
⇒ 7 × \(\frac{6}{7}\) + 3 = 9
⇒ 6 + 3 = 9
9 = 9 (Hence Verified)
DAV Class 6 Maths Chapter 8 Value Based Questions
Question 1.
In a school out of 250 students of Class- VI, x students visited an old age home. They entertained them with dance and music, they discussed about their families and children, helped them in cleaning their cupboards. But 75 children refused to visit.
(a) Find the number of students who visited the old age home.
(b) What value is shown by those students?
Answer:
(a) x + 75 = 250
∴ x = 250 – 75
x = 175
(b) Social, helpful, or respect for elders, etc.
Question 2.
During an earthquake, x students from Class-VI donated ₹ 25 each and 25 students from Class-V donated ₹ 50 each. If total amount collected is ? 2000.
(a) Find the number of students of Class- VI who donated.
(b) What value is depicted by students?
Answer:
(a) Amount donated by one student of
Class-V = ₹ 50
Amount donated by 25 students of Class-V = ₹ 50 x 25 = 1250
Amount donated by one student of Class-VI = ₹ 25
Amount donated by x students of Class VI =₹ 25x
Total amount = Amount donated by Class-V students + Amount donated by Class-VI students Total amount
= ₹ 2000
∴ 2000 = 1250 + 25x
or 750 = 25x
∴ 30 = x
Thus, the no. of students of Class VI = 30
(b) Social or helpful, etc.