DAV Class 4 Maths Chapter 13 Brain Teasers Solutions

The DAV Maths Class 4 Solutions and DAV Class 4 Maths Chapter 13 Brain Teasers Solutions of Volume offer comprehensive answers to textbook questions.

DAV Class 4 Maths Ch 13 Brain Teasers Solutions

Question 1.
Tick ( ✓) the correct answer.
(a) The best unit to measure volume is-
(i) Sphere
(ii) Cuboid
(iii) Cube
(iv) Square
Solution:
(iii) Cube

(b) Volume of a cube of edge 1 m is-
(i) 3 m
(ii) 1 m
(iii) 1 sq. m
(iv) 1 cu. m
Solution:
(iv) 1 cu. m

(c) The length of a cuboid is 10 cm, breadth is 8 cm and height is 2 cm less than breadth. Its volume will be-
(i) 160 cu. cm
(ii) 480 cu. cm
(iii) 480 cm
(iv) 160 cm
Solution:
(ii) 480 cu. cm

Volume of cuboid = l × b × h
l = 10 cm,
b = 8 cm,
h = 8 – 2 = 6 cm
= 10 cm × 8 cm × 6 cm
= 480 cu. cm
Hence, option (ii) is correct.

(d) Which of the following has the greatest volume?
(i) Football
(ii) Cricket ball
(iii) Table tennis ball
(iv) Golf ball
Solution:
(i) Football

(e) A cubical box of edge 10 cm is one – fourth filled with salt. The volume of salt in the box is-
(i) 1000 cu. cm
(ii) 300 cu. cm
(iii) 250 cu. cm
(iv) 250 sq. m
Solution:
(iii) 250 cu. cm

Volume of cuboidal box = edge × edge × edge.
= 10 cm × 10 cm × 10 cm
= 1000 cu. cm.
Volume of salt = \(\frac{1}{4}\) of volume of cubical box
= \(\frac{1}{4}\) × 1000
= 250 cu. cm.
Hence, option (iii) is correct.

Question 2.
Measure the sides of the following objects and find their volumes.
(a) Match box
(b) Your mathematics book
(c) Shoe box
(d) Dice
Solution:
Do yourself.

Question 3.
Find the volume of a box of length 9 cm, breadth 5 cm and height 3 cm.
Solution:
Volume of box = l × b × h
= 9 cm × 5 cm × 3 cm
= 135 cu. cm

Question 4.
Find the volume of a cubical box of edge 8 cm.
Solution:
Volume of cubical box = edge × edge × edge
= 8 cm × 8 cm × 8 cm
= 512 cu. cm

Question 5.
Which one has more volume?
A cuboid of length 7 cm, breadth 5 cm and height 4 cm or a cube of edge 6 cm.
Solution:
Volume of cuboid = 1 × b × h
= 7 cm × 5 cm × 4 cm
= 140 cu. cm

Volume of cube = edge × edge × edge
= 6 cm × 6 cm × 6 cm
= 216 cu. cm
Thus, cube has more volume.

Question 6.
The edge of a cubical box is 6 cm. Half of the box is filled with sand. What is the volume of the sand?
Solution:
Volume of cubical box = edge × edge × edge
= 6 cm × 6 cm × 6 cm
= 216 cu. cm

Volume of sand = \(\frac{1}{2}\) of volume of box
= \(\frac{1}{2}\) × 216 cu. cm
= 108 cu. cm
Thus, volume of sand is 108 cu. cm.

Additional Questions:

Question 1.
Find the volume of cubes whose edges are given below:

(a) 22 cm
Solution:
Volume of cube = Edge × Edge × Edge
= 22 cm × 22 cm × 22 cm
= 10648 cu. cm

(b) 17 cm
Solution:
Volume of cube = Edge × Edge × Edge
= 17 cm × 17 cm × 17 cm
= 4913 cu. cm

(d) 20 cm
Solution:
Volume of cube = Edge × Edge × Edge
= 20 cm × 20 cm × 20 cm
= 8000 cu. cm

Question 2.
Find the volume of cuboid.

(a) l = 5 cm, b = 30 cm h = 0.2 m
Solution:
Volume of cuboid = l × b × h
l = 5 cm,
b = 30 cm,
h = 0.2 × 100 = 20 cm
Volume of cuboid = 5 cm × 30 cm × 20 cm
= 3000 cu. cm

(b) l = 0.6 m, b = 40 cm h = 10 cm
Solution:
Volume of cuboid = l × b × h
l = 0.6 m = 0.6 × 100 = 60 cm,
b = 40 cm,
h = 10 cm
Volume of cuboid = 60 cm × 40 cm × 10 cm
= 24000 cu. cm

(c) l = 0.19 m b = 50 cm h = 7 cm
Solution:
Volume of cuboid = l × b × h
l = 0.19 m = 0.19 × 100 = 19 cm,
b = 50 cm,
h = 7 cm
Volume of cuboid = 19 cm × 50cm × 71 m
= 6650 cu. cm

Question 3.
Which one has move volume?
A cube with edge 9 cm or a cuboid having length 10 cm, breadth 0.07 m and height 14 cm.
Solution:
Volume of cube = edge × edge × edge
= 9 cm × 9 cm × 9 cm
= 729 cu. cm
Volume of cuboid = l × b × h
= 10 cm × 0.07 × 100 cm × 14 cm
= 10 cm × 7 cm × 14 cm
= 980 cu. cm
So cuboid has more volume

Question 4.
The length, breadth and height of cuboidal pole are 10 m, 22 cm and 15 cm respectively. What is the volume of the pole?
Solution:
Length of pole = 10 m
= 10 × 100 = 1000 cm
Breadth of pole = 22 cm
Height of pole = 15 cm
Volume of pole = l × b × h
= 1000 cm × 22 cm × 15 cm
= 330000 cu. cm

Question 5.
A cuboidal box has length 8 cm, breadth 3 cm and height 1.5 cm. It is half-filled with lemon syrup. What is the volume of syrup.
Solution:
Length of cuboidal box = 8 cm
Breadth of cuboidal box = 3 cm
Height of cuboidal box = 1.5 cm
Volume of box = l × b × h
= 8 cm × 3 cm × 1.5 cm
= 36 cu. cm
Volume of syrup = \(\frac{1}{2}\) volume of box
= \(\frac{1}{2}\) × 36 cu. cm
= 18 cu. cm
Thus, 18 cu. cm is the volume of syrup.