DAV Class 6 Maths Chapter 9 Brain Teasers Solutions

The DAV Maths Book Class 6 Solutions and DAV Class 6 Maths Chapter 9 Brain Teasers Solutions of Line Segments offer comprehensive answers to textbook questions.

DAV Class 6 Maths Ch 9 Brain Teasers Solutions

Question 1.
A. Tick (✓) the correct answer.
(a) In the given figure, the number of line segments are:
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 1
(i) 5
(ii) 10
(iii) 15
(iv) 20
Answer:
In the given figure, there are 10 line segments. They are AB, AC, AD, AE, BC, BD, BE, CD, CE and DE Thus, the (ii) option is correct.

(b) The number of diagonals in a pentagon are
(i) 2
(ii) 3
(iii) 4
(iv) 5
Answer:
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 2
A pentagon has five sides.
ABCDEA is a pentagon. AB, BC, CD, DE and EA are its five sides. AC, AD, BD, BE and CE are its diagonals. They are five in number. Thus, a pentagon has five diagonals.
So, correct answer is (iv).

(c) For the following figure
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 3
(i) AC + CB = AB
(ii) AB + AC = CB
(iii) AB + BC = CA
(iv) none
Answer:
AC + CB = AB is the correct option.

(d) A line segment
(i) extends in one direction only.
(ii) extends in both the directions.
(iii) has two end points.
(iv) has length and breadth.
Answer:
A line segment has two end points and has a definite length. It is a portion of a line. Thus, option (iii) is correct.

(e) One end point of a line segment AB is against the mark 2 and other at mark 9 of a scale. What is the length of segment AB?
(i) 6 cm
(ii) 7 cm
(iii) 9 cm
(iv) 11 cm
Answer:
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 4
AB is a line segment and OX is a scale. Point A is at 2 and Point B is at 9. So, length of segment AB = OB – OA = 9 – 2 = 7 cm.
Thus, option (ii) is correct.

DAV Class 6 Maths Chapter 9 Brain Teasers Solutions

B. Answer the following questions.
(a) For the given figure,
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 5
(i) AE + EC = _______
(ii) AC – EC = _______
(iii) BD – BE = _______
(iv) BD – DE = _______
Answer:
(i) AE + EC = AC
(ii) AC – EC = AE
(iii) BD – BE = DE
(iv) BD – DE = BE

(b) The length of an air conditioner remote is 10 cm and length of a television remote is 16 cm. Construct a line segment of length equal to the difference of their length.
Answer:
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 6
Step 1. Draw a length AB of 10 cm equal to the length of an air conditioner remote.
Step 2. Draw a length XY of 16 cm equal to the length of television remote.
Step 3. Using compass, draw a line segment AB, equal to 10 cm on XY
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 7
Step 4. XY – AB = 16 cm – 10 cm = 6 cm = BY
Here, BY is the difference of lengths XY and AB.

(c) Measure the length of your Papa’s mobile using compasses and construct the line segment of that length.
Answer:
Length of mobile phone = 4 cm
Using compass, draw a line segment PQ of 4 cm starting from P. Thus, PQ = 4 cm.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 8

(d) Rajan purchased a ribbon of length 20 cm to tie his project report. He used 14 cm ribbon. Construct a line segment of the same length as the difference of given length.
Answer:
Total length of the ribbon = 20 cm
Ribbon used to tie the project report = 14 cm
Difference of the length of ribbon = 20 cm – 14 cm = 6 cm
To construct a line segment of 6 cm, we draw a line segment of AB by using compass.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 9
Starting from point A, we draw another point B on the line l and length equal to 6 cm.

(e) How many line segments are there in the following figure?
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 10
Answer:
In the figure, AE, AB, BE, BC, CD, DE, DF and FA are the line segments. Thus, there are a total of 8 line segments.

Question 2.
How many line segments are there in the given figure? Name any four.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 11
Answer:
The given figure has 14 line segments.
AB, BD, FD, AF, BC, CD, EC, AH, HF, HG, GF, AG, BE, ED

DAV Class 6 Maths Chapter 9 Brain Teasers Solutions

Question 3.
Construct a line segment whose length is thrice the length of the given line segment.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 12
Answer:
Step 1: Draw any line l and take a point A on it.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 13
Step 2: Using compass and starting from A construct a line segment AB on l equal to the length of the given line segment XY.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 14
Step 3: Again using compass and starting from B (to the right) construct another line segment BC equal to the length of the given line segment.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 15
Step 4: Now starting from C, construct a line segment CD on l equal to the length of the given line segment XY.
Hence AB = AB + BC + CD = XY + XY + XY = 3 XY

Question 4.
You are given a triangle here. Construct a line segment whose length is equal to the sum total of all the three sides of this triangle.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 16
Answer:
Step 1: Draw any line l and take a point A on it.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 17
Step 2: Using compass and starting from A, draw a line segment AB on l equal to the length of PQuestion
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 18
Step 3: Now, with the help of compass, draw a line segment BC on l equal to the length of the side QR of the triangle PQR.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 19
Step 4: Using compass and starting from B, draw a line segment BC on l equal to the length of the side RP of the triangle PQR.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 20
Hence AD = PQ + QR + RP.

Question 5.
Find the perimeter of a square of side 2 cm and of an equilateral triangle of side 1.5 cm. Construct—
(a) a line segment whose length is the sum of their perimeters.
(b) a line segment whose length is difference of their perimeters.
Answer
To find perimeter of a square, draw line segments AB, BC, CD and DA of equal length of 2 cm each. Thus,
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 21
Perimeter of the square = AB + BC + CD + DA
= 2 cm + 2 cm + 2 cm + 2 cm
= 8 cm
Again, to find perimeter of an equilateral triangle we draw line and PR of equal length of 1.5 cm.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 22
Thus,
Perimeter of equilateral triangle = PQ + QR + RP
= 1.5 cm + 1.5 cm + 1.5 cm
= 4.5 cm

(a) Now, sum of perimeters = Perimeter of square + perimeter of equilateral triangle
= 8 cm + 4.5 cm
= 12.5 cm
To construct a line segment of length 12.5 cm.
Step 1. With the help of compass, draw a line l
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 23
Step 2. Mark a point A on the line.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 24
Step 3. From point A on the line, take another point B on the line such that the AB = 12.5 cm.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 25
Thus, AB = 12.5 cm is the sum of perimeters of square and triangle.

(b) Perimeter of square = 8 cm
Perimeter of equilateral triangle = 4.5 cm
So, their difference = 8 cm – 4.5 cm = 3.5 cm
Steps to construct a line segment of length 3.5 cm
(i) Using compass draw a line l.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 26
(ii) Mark a point A on the line l.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 27
(iii) With A as centre and length equal to 3.5 cm, mark another point B on the same line.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 28
Thus, AB = 3.5 cm.

DAV Class 6 Maths Chapter 1 HOTS

Question 1.
There are five points on a sheet of paper, such that no three are collinear. What is the number of line segments that can be drawn by joining the points in pairs?
Answer:
There are five different points P, Q, R, S and T such that no three are collinear.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 29
By joining them in pairs, we get, PQ, PR, PS, PT, QR, QS, QT, RS, RT and ST.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 30
There are a total of 10 line segments.

DAV Class 6 Maths Chapter 9 Brain Teasers Solutions

Question 2.
In each of the following cases, state whether you can draw line segments on the given surfaces.
(i) Face of a cube
(ii) The top of a solid cylinder
(iii) The surface of an apple
(iv) Curved surface of a cone.
Answer:
(i) Yes, a cube has 6 faces.
(ii) Yes, because top of a cylinder is a plane surface at circular end.
(iii) No, because apple is spherical in shape and error caused in actual measurement.
(iv) No, a line segment cannot be drawn on the curved surface of a cone.

Additional Questions

Question 1.
How many line segments are there in the given figure? Measure the lengths of each of the line segment with the help of ruler.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 31
Answer:
There are 5 line segments in the given figure.
Using ruler, we find that
AB = 3.2 cm, DC = 3.2 cm, AD = 2 cm, BC = 2 cm and AC = 3.5 cm.

Question 2.
Draw a line segment whose length is equal to the sum of the given line segments XY and ZW.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 32
Answer:
Step 1: Draw a line l and take any point A on it.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 33
Step 2: Using compass, starting from A, construct a line segment AB on l equal to the line-segment XY.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 34
Step 3: Starting from B(to the right) construct a, line-segment BC on l equal to the length of the line segment ZW.
Hence AC = XY + ZW.

Question 3.
Compare the following pairs of line segments and put >, = or < in the blanks:
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 35
Answer:
(a) XY > PQ
(b) AB < CD
(c) MN = OP
(d) RS > TM

Question 4.
Construct a line segment PQ = 5.5 cm. From this line segment cut off a line segment QR = 3 cm. Measure the length of the remaining line segment PR.
Answer:
Step 1 : Draw a line l and take any point P on it.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 36
Step 2: Using compass and starting from P, construct a line segment PQ = 5.5 cm.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 37
Step 3: Starting from Q (to the left) cut off a line segment QR = 3 cm from the line segment PQ.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 38
Hence the required line segment is PR whose length is 2.5 cm.

DAV Class 6 Maths Chapter 9 Brain Teasers Solutions

Question 5.
Measure the length and breadth of a playing card. Construct a line segment whose length is their
(a) Sum
(b) Difference
Answer:
(a) Length of the playing card = 8 cm
Breadth of the playing card = 4 cm
Sum of the length and breadth = 8 + 4 = 12 cm
Step 1 : Draw a line l and take any point A on it.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 39
Step 2: Using compass, starting from A, construct a line segment AB on l equal to the length of the playing card i.e. 8 cm.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 40
Step 3: Now starting from B (to the right) draw a line segment BC on l equal to the breadth of the playing cards i.e. 4 cm.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 41
Here AC is the segment which represents the sum of the length and breadth of the playing card.
∴ AC = AB + BC
= 8 cm + 4 cm
= 12 cm

(b) Step 1: Draw any line l and take any point P on it.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 42
Step 2: Using compass, starting from P, draw a line segment PQ on l equal to the length of the playing card.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 43
Step 3: Now starting from Q(to the left), draw a line segment QR on l equal to the breadth of the playing card.
DAV Class 6 Maths Chapter 9 Brain Teasers Solutions 44
Hence PR is the line segment whose length is equal to the difference of the length and breadth of the playing cards.
where PR = PQ – QR
= 8 cm – 4 cm
= 4 cm

DAV Class 6 Maths Chapter 9 Brain Teasers Solutions

Question 6.
The end point P of a line segment PQ is against 2 cm mark and the end point Q is against the mark indicating 9 cm on a ruler. What is the length of the line segment?
Answer:
P is against 2 cm mark.
Q is against 9 cm mark.
∴ Segment PQ = 9 cm – 2 cm = 7 cm
Hence the required length = 7 cm.

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

The DAV Books Solutions Class 5 Maths and DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions of Percentage offer comprehensive answers to textbook questions.

DAV Class 5 Maths Ch 12 Worksheet 3 Solutions

Question 1.
Convert the following fractions into percentages.
(a) \(\frac{4}{5}\)
Solution:
DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions Q1(a)

(b) \(\frac{6}{10}\)
Solution:
DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions Q1(b)

(c) \(\frac{3}{4}\)
Solution:
DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions Q1(c)

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

(d) \(\frac{9}{50}\)
Solution:
DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions Q1(d)

(e) 1\(\frac{2}{5}\)
Solution:
DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions Q1(e)

(f) 1\(\frac{1}{10}\)
Solution:
DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions Q1(f)

Question 2.
Convert the following into percentages.
(a) 6
Solution:
Method 1:
6 = 6 × \(\frac{100}{100}\)
= \(\frac{600}{100}\)
= 600%
Method 2:
6 = (6 × 100)% = 600%

(b) 15
Solution:
Method 1:
15 = 15 × \(\frac{100}{100}\)
= \(\frac{1500}{100}\)
= 1500%
Method 2:
15 = (15 × 100)% = 1500%

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

(c) 28
Solution:
Method 1:
28 = 28 × \(\frac{100}{100}\)
= \(\frac{2800}{100}\)
= 2800%
Method 2:
28 = (28 × 100)% = 2800%

(d) 13
Solution:
Method 1:
13 = 13 × \(\frac{100}{100}\)
= \(\frac{1300}{100}\)
= 1300%
Method 2:
13 = (13 × 100)% = 1300%

(e) 9
Solution:
Method 1:
9 = 9 × \(\frac{100}{100}\)
= \(\frac{900}{100}\)
= 900%
Method 2:
9 = (9 × 100)% = 900%

(f) 1
Solution:
Method 1:
1 = 1 × \(\frac{100}{100}\)
= \(\frac{100}{100}\)
= 100%
Method 2:
1 = (1 × 100)% = 100%

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

Question 3.
Convert the following decimals into percentages.
(a) 0.45
Solution:
Method 1:
0. 45 = \(\frac{45}{100}\) = 45%
Method 2:
0. 45 = (0.45 × 100)% = 45%

(b) 0.09
Solution:
Method 1:
0.09 = \(\frac{9}{100}\) = 9%
Method 2:
0.09 = (0.09 × 100)% = 9%

(c) 2.25
Solution:
Method 1:
2.25 = \(\frac{225}{100}\) = 225%
Method 2:
2.25 = (2.25 × 100)% = 225%

(d) 7.6
Solution:
Method 1:
7.6 = \(\frac{76}{10} \times \frac{10}{10}\)
= \(\frac{760}{100}\)
= 760%
Method 2:
7.6 = (7.6 × 100)% = 760%

(e) 0.01
Solution:
Method 1:
0.01 = \(\frac{1}{100}\) = 1%
Method 2:
0.01 = (0.01 × 100)% = 1%

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

(f) 0.135
Solution:
Method 1:
0.135 = \(\frac{135}{1000}\)
= \(\frac{135 \div 10}{1000 \div 10}\)
= 13.5%
Method 2:
0.135 = (0.135 × 100)% = 13.5%

Question 4.
Choose the correct number.
(a) 5% = 5, 0.5, 0.05, 0.005
Solution:
0.05

(b) 45% = 4.5, 0.45, 0.045, 0.0045
Solution:
0.45

(c) 125% = 0.125, 12.5, 1.25, 125
Solution:
1.25

Question 5.
Solve the following questions.
(a) Reema scored 40 marks out of 50 in her Mathematics test. Find the percentage of marks scored by her.
Solution:
Reema scored = 40 marks
Maximum marks = 50 marks
Percentage of marks = (\(\frac{40}{50}\) × 100)%
= (4 × 20)%
= 80%

(b) In a packet of 25 toffees, three toffees are mango bites. What is the percentage of mango bite toffees?
Solution:
Total toffees = 25
No. of mango bites = 3
% of mango bite toffees = (\(\frac{3}{25}\) × 100)% = 12%

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

(c) In the month of April, a school worked for only 24 days. What is the percentage of working days?
Solution:
Total no. of days in April = 30 days
Number of working days = 24 days
Percentage of working days = (\(\frac{24}{30}\) × 100)% = 80%

(d) In an orchard, there are 250 trees. 175 of them are apple trees. Find the percentage of apple trees.
Solution:
Total number of trees = 250
No. of apple trees = 175
Percentage of apple trees = (\(\frac{175}{250}\) × 100)% = 70%

DAV Class 5 Maths Chapter 12 Worksheet 3 Notes

Convert a fraction into a percentage.

Example 1.
Let us convert \(\frac{2}{5}\) into percentage.
Solution:
Method 1:
\(\frac{2}{5}=\frac{2}{5} \times \frac{20}{20}=\frac{40}{100}\) = 40%
Method 2:
\(\frac{2}{5}\) = (\(\frac{2}{5}\) × 100)%
= \(\frac{200}{5}\)%
= 40%

We can convert a fraction into a percentage by two methods:

  • Convert a fraction into an equivalent fraction with denominator 100.
  • Multiply the fraction by 100.

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

Convert a decimal number into a percentage.

Example 2.
Convert 0.2 into a percentage.
Solution:
Method 1:
0.2 = \(\frac{2}{10}\)
= \(\frac{2 \times 10}{10 \times 10}\)
= \(\frac{20}{100}\)
= 20%
Method 2:
0.2 = (0.2 × 100)% = 20%

We can convert decimals into percentages by two methods:

  • Convert decimal into an equivalent fraction with denominator 100.
  • Multiply the decimal by 100.

Convert a whole number into a percentage.

Example 3.
Convert 3 into a percentage.
Solution:
Method 1:
3 = \(\frac{3 \times 100}{100}\)
= \(\frac{300}{100}\)
= 300%
Method 2:
3 = (3 × 100)% = 300%

DAV Class 5 Maths Chapter 12 Worksheet 3 Solutions

We can convert whole numbers into percentages by 2 methods:

  • Convert whole numbers into equivalent fractions with denominator 100.
  • Multiply the whole number by 100.

The Proposal Summary Analysis and Explanation

The Proposal Summary Analysis and Explanation

Students can also check English Summary to revise with them during exam preparation.

The Proposal Summary Analysis and Explanation By Anton Chekhov

About the Poet Anton Chekhov

Poet Name Anton Chekhov
Born 29 January 1860, Taganrog, Russia
Died 15 July 1904, Badenweiler, Germany
Short stories The Chameleon, The Man in a Case, Ionych, Misery
Movies The Orchard, The Seagull, Uncle Vanya
Anton Chekhov - the proposal summary analysis and explanation class 10
Anton Chekhov

The Proposal Summary of the Lesson

Characters and places

  • Stepan Stepanovitch Chubukov – a landowner
  • Natalya Stepanovna – his daughter aged twenty – five
  • Ivan Vassilevitch Lomov – a neighbor of Chubukov, a landowner
  • Oxen Meadows – a debatable topic between Natalya and Lomov.
  • Burnt Marshland of Chubukov
  • Birchwoods – woods of Chubukov
  • Nastasya Mihailovna – younger aunt of Lomov
  • Dog Guess – dog of Lomov
  • Mironov – a person from whom dog Guess was purchased
  • Squeezer – dog of Chubukov.

Arrival of Lomov with some proposal : Stepan Stepanovitch Chubukov is sitting in his drawing-room. There enters Ivan Vassilevitch Lomov. He is well dressed. So Chubukov rises to greet him. He has come to request him for something. Chubukov thinks that he will ask for some money. But Lomov does not answer him clearly. Chubukov asks him to be clear in his aim. He requests that he has come to ask the hand of his daughter Natalaya Stepanovna in marriage. Chubukov becomes happy and embraces Lomov. He gives his blessings as well. Chubukov goes to call Natalaya. Lomov is alone. He starts thinking about himself, his age and heart palpitations, etc.

The Proposal Summary

Arrival of Natalaya and her discussion with Lomov : Natalaya arrives and both have a discussion. Lomov is excited and he tells that he has made up his mind to ask her to hear him out in brief. He tells that Lomov and the Chubukov have remained friendly. His Oxen Meadows touch her birchwoods. Immediately Natalaya interferes that they have been the owners of the Oxen Meadows. Lomov points out that they have been his and are in between the birchwoods and the Burnt Marsh.

Debate over Oxen Meadows : Ivan tells that she is mistaken over it. She can see from the documents that Oxen Meadows remained the subjects of dispute once but everyone knows that these belong to Lomov now. She must know that his aunt’s grandmother gave the free use of these Meadows to the peasants who belonged to her (Natalaya) father’s grandfather on the condition that they were to prepare bricks for the aunt.

Those peasants went on using it for the last forty years and became habitual to call them their own. But Natalaya calls it a silly idea. Lomov tells that he can show the documents. Natalaya’s view point—Natalaya tells that they have been using the land for nearly three hundred years. She cannot believe his story. These Meadows are worth perhaps 300 roubles and she will not tolerate this unfairness. She tells that she cannot understand about aunts, grandfather and grandmother but the Meadows belong to Chubukovs. She will not give anything of her.

Lomov tells that he is acting on principle. If she likes, he can present them. Natalaya tells that she can make a present of them herself. She has thought them a good neighbour and a fine friend. But he has been behaving as if they were gypsies. Lomov tells that he is not a land grabber. He will never allow anyone to blame like this but Oxen Meadows are his. Thus, there starts a heated debate between the two. There is much noise.

The Proposal Summary of the Lesson

Arrival of Chubukov and his views : Hearing their noise, Chubukov enters and asks why they have been shouting. Natalaya asks her father to tell Lomov that the Oxen Meadows belong to them. Lomov requests him to be a reasonable man. These Meadows were given by his aunt’s grandmother for the temporary and free use of his (Chubukov’s) grandfather’s peasants. They have been using for the last forty years and become accustomed to call them their own. Chubukov did not agree but he pointed out that the Meadows were in dispute.

Lomov told that he could prove that these were his. Calling him his dear one, Chubukov told that he could even give up the Meadows to the peasants than to him (Lomov). Lomov pointed out that he (Chubukov) had no right to give away somebody else’s property. Chubukov requested him to speak politely and calmly. These words enraged Lomov and he told that he was not fool to call his land theirs (Chubukov’s). He called him a grabber. Natalaya told that these Oxen Meadows won’t be given up.

Threatening by Lomov : Lomov threatened that he would go to the court and show them the reality.

Chubukov blamed the family of Chubukov for various reasons.

Lomov goes to the door and Chubukov warns him never to set foot in his house again. Natalaya calls Lomov a rascal and monster, etc. Chubukov called him a blind hen who had come to make a proposal. Chubukov told that he had come to propose to her.

Wailing of Natalaya : Hearing these words, Natalaya falls into an easy chair and wails. She calls to bring Lomov back immediately since she is dying. She starts wailing. Chubukov runs to bring Lomov back. There enters Lomov. Seeing him coming back, Chubukov tells Natalaya that she will talk to him herself. Then Chubukov leaves the house.

Talk of Lomov and Natalaya : Lomov tells that his heart is palpitating and soon Natalya feels sorry and tells that the Oxen Meadows have been the property of Lomov’s. She requests him to sit down and talk something else. Then Lomov tells that his dog Guess has gone lame. His leg must have been bitten by some other dog.

He purchased it for 125 roubles from Mironov. Natalaya tells that her father purchased Squeezer for 85 roubles. Lomov tells that her Squeezers is better than Guess but he is overshot i.e., a bad hunter. Even its lower jaw is shorter than the upper. Both discuss more facts about these dogs. Natalaya said that Squeezer is a hundred times better then the silly Guess. Immediately Lomov told not to discuss such facts as his heart was palpitating. There enters Chubukov and asks what has been the matter?

Natalaya asks her father which is the better one : Squeezer or Guess?

Chubukov’s pleading : Chubukov told that it was no use arguing and blaming. In between Lomov tells that his foot has gone to sleep. Natalaya too points out that her heart is under trouble. So many other talks go on but Lomov falls into an arm chair. A doctor is called for. Natalaya asks her father what has happened to Lomov. She too falls into an armchair and calls for a doctor.

Chubukov is deeply troubled. Natalaya wails and tells that Lomov is dead. Suddenly Lomov moves and drinks some water. Chubukov tells them to get married very soon. He puts Lomov’s hand into his daughter’s. She is smiling. He gives them his blessings. He asks them to kiss each other. They kiss each other. Natalaya says that she is happy. Chubukov tells that he is free from a heavy weight on his shoulders. Chubukov advises them to start their family. He blesses them.

ਵੱਡਾ ਕੌਣ Summary in punjabi

The Making of a Scientist Summary By Robert W Peterson Analysis and Explanation

The Making of a Scientist Summary By Robert W Peterson Analysis and Explanation

Students can also check the English Summary to revise with them during exam preparation.

The Making of a Scientist Summary Analysis and Explanation in English

About the Author
Robert W. Peterson (1925 Warren, Pennsylvania February 11, 2006) was an American newspaper writer who later became a freelance author of magazine articles and books, especially on the topics of sports and scouting. His 1970 chronicle of Negro league baseball titled ‘Only the Ball Was White’ was hailed by The New York Times as having “recaptured a lost era in baseball history and a rich facet of black life in America”. The baseball commissioner at the time, Bowie Kuhn, later credited Peterson’s book with having “focused greater attention on the accomplishments of Negro League players”, leading to their admission to the Baseball Hall of Fame.

Author Name Robert W. Peterson
Born 1925, United States
Died 11 February 2006, Salisbury, Pennsylvania, United States
Nationality American
Education Upsala College
Robert W. Peterson
Robert W. Peterson

The Making of a Scientist Summary of the Lesson

Richard H. Ebright published the theory of how cells work in an article in the Proceeding of the National Academy of Science at the age of twenty-two.

Richard H. Ebright grew up reading in Pennsylvania. There he was not able to do anything. He was not able to play football or baseball too. But he said that he could do one thing—collect things. So he collected things.

In kindergarten, Ebright collected butterflies. He also collected rocks, fossils, and coins. He would observe the sky at night too. He would live with his mother, who encouraged his interest in learning.

She would take him on trips, bought him a telescope, microscope, cameras, mounting materials, and other materials required for learning. He lost his father when he was in third grade. Her mother would call him Richie.

Her mother would discuss with him every night and give him mental exercise instead of physical exercise which he wanted to learn.

By the time he was in second grade, Ebright had collected all twenty-five species of butterflies found around his hometown. Richard said that this would have been end of his butterfly collection.

But her mother gave him a children’s book called “The Travels of Monarch X, “That book, which told how monarch butterflies migrate to Central America, opened the world of science to Richard”. At the end of book readers were invited to help study butterfly migrations.

They were asked to tag butterflies for research by Dr Frederick A. Urquhart of the University of Toronto, Canada. Anyone who found a tagged butterfly was asked to send the tag to Dr Urquhart. If you tried to catch them one by one, you won’t catch many.

So Richard raised a flock of butterflies. He would catch a female monarch, take her eggs, and raise them in his basement through their life cycle, from egg to caterpillar to pupa to adult butterfly. Then he would tag the butterflies wings’ and let them go.

For several years his basement was home to thousands of monarchs in different stages of development.

He got a hint of what a real science is when he entered a country science fair, and lost. He said that, it was a sad feeling to sit there and not get anything while everybody else had won something. His entry was slides of frog tissues, which he showed under a microscope.

He realized that winners had tried to do real experiments. And he decided that for the next year, he has to do something extraordinary than offers. So he asked to Dr Urquhart for suggestions and back came a stack of suggestions.

For his eighth grade project, Ebright tried to find the cause of a viral disease that kills nearly all monarch caterpillars every few years. Ebright thought the disease might be carried by a beetle. So he rose caterpillars in the presence of beetles. But he didn’t get any real result. But he went ahead and showed that he had tried the experiment.

The next year his science fair project was testing the theory that viceroy butterflies copy monarchs. The theory was that viceroys look like monarchs because monarchs don’t taste good to birds. Viceroys, on the other hand, do taste good to birds.

So the more they look like monarchs, the less likely they are to become a bird’s dinner. Ebright’s project was to see whether, in fact, birds would eat monarchs. He found that a starling would not eat ordinary bird food.

It eats all the monarchs it could get. (Ebright said later that research by other people showed that viceroys probably do copy the monarch.) This project was placed.first in the zoology division and third overall in the country science fair.

In his second year in high school, Richard Ebright began the research that led to his discovery of an unknown. insect hormone.

The Making of a Scientist Summary

ਨਕਲ ਕਰੋ ਪਰ ਕੀਹਦੀ? Summary In Punjabi

The Midnight Visitor Summary Analysis and Explanation By Robert Arthur

The Midnight Visitor Summary Analysis and Explanation By Robert Arthur

Students can also check the English Summary to revise with them during exam preparation.

The Midnight Visitor By Robert Arthur Summary Analysis and Explanation in English

About the Author 
Robert Jay Arthur Jr. (November 10, 1909 – May 2, 1969) was a writer of speculative fiction known for his work with The Mysterious Traveler radio series and for writing The Three Investigators, a series of young adult novels. Arthur was honoured twice by the Mystery Writers of America with an Edgar Award for Best Radio Drama. He also wrote scripts for television such as The Twilight Zone and Alfred Hitchcock’s TV show, Alfred Hitchcock Presents.

Author Name Robert Arthur Jr.
Born 10 November 1909, Corregidor Island, Cavite City, Philippines
Died 2 May 1969, Philadelphia, Pennsylvania, United States
Awards Edgar Award for Best Radio Drama
Education University of Michigan, William & Mary
Movies The Three Investigators and the Secret of Terror Castle

Robert Jay Arthur Jr - the midnight visitor summary class 10

Short Summary of The Lesson Midnight Visitor in English

‘The Midnight visitor’ is a detective story written by Robert Arthur. The presence of mind is the most important quality, a secret agent must-have. Ausable, the hero of the story, is one such secret agent. He expects to get some sensitive papers in his hotel room.

Suddenly he is attacked by one of his rivals who points a pistol at him and demands the papers. Ausable shows remarkable common sense and comes out of the situation.

Fowler is surprised to see a secret agent Ausable who is too fat to be a secret agent. Ausable tells him that he was going to get an important paper for which many men have risked their lives when both of them reach Ausable’s room.

Fowler is scared to see a man standing in the room. Max, who is tall and thin man and is holding an automatic pistol in his hand, had entered his room by using a key to take the report concerning a new missile.

Ausable, sensing the danger, fabricated a story about the non-existent balcony which Max believed to be true. Ausable complained that it was due to the balcony that somebody had entered his room the second time. After some time there was knocking at the door.

Ausable again befooled Max by saying that it was the police who wanted to come inside to provide him protection. Max wanted to run away to avoid the police and jumps to his death into that non-existent balcony.

The Midnight Visitor

FAQs on Summary of The Story The Midnight Visitor

Question 1.
what is the Theme Of The Midnight Visitor

Answer:
The central idea of this lesson is based on Ausable intelligence that how he created a story about a non exist balcony and he knew that who is on the door but he termed to say police

The Midnight Visitor Summary

Question 2.
What is the story of the midnight visitor?

Answer:
The story is about a witty secret agent named Ausable. … While they were talking, Ausable started with a story about how a guy had entered from the balcony last month below his room. While this talk was going on, a sudden knock was heard at the door.

ਉਠ ਕਿੱਥੇ ਗਿਆ Summary in punjabi

The Thief’s Story Summary Analysis and Explanation

The Thief’s Story Summary Analysis and Explanation

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The Thief’s Story Summary Analysis and Explanation By Ruskin Bond

About the Author Ruskin Bond
Ruskin Bond (born 19 May 1934) is an Indian author of British descent. He lives with his adopted family in Landour, Mussoorie, India. The Indian Council for Child Education has recognised his role in the growth of children’s literature in India. He was awarded the Sahitya Academy Award in 1992 for Our Trees Still Grow in Dehra, his novel in English. He was awarded the Padma Shri in 1999 and the Padma Bhushan in 2014.

Author Name Ruskin Bond
Born 19 May 1934 (age 86 years), Kasauli
Education Bishop Cotton School shimla (1950)
Awards Padma Shri, Padma Bhushan
Movies 7 Khoon Maaf, The Blue Umbrella, The Black Cat, Junoon, Ek Tha Rusty II
Ruskin Bond - The Thief’s Story SummaryAnalysis and Explanation
Ruskin Bond

The Thief’s Story Summary of the Lesson

Anil was a young writer. He was living his life very carelessly. He was writing for the magazines and earning the money to run his life. One day Anil was watching the wrestling match. Hari best knew how to make unknown person a friend. He used an old formula to flatter the person. Hari stayed with Anil.

Anil promised him that he would teach him how to write and add numbers. He also taught him how to cook tasty food. Daily Hari Singh went to buy daily needs and had profit of one rupee daily. Anil knew it but he did not mind it. Both were living together happily.

One month passed, Hari Singh did not perform his business. One day he saw Anil had brought a bundle of notes. He saw him to put them under the mattress. As Hari saw the bundle of notes, his evil spirit awakened in his mind and he decided to rob Anil that night. After taking dinner Anil slept peacefully.

Hari could not sleep, he woke up. He crept to the bed and slipped his hand under the mattress. He found the notes and ran away on the road. Hari Singh made up his mind that he would go directly to the railway station and would catch the Lucknow Express.

He thought that Anil would not catch him if he ran away from the city. Hari Singh reached the railway station, Lucknow Express was about to go.

Suddenly the good spirit called him. The inner voice told him not to betray the faith of Anil. The train was moving but Hari did not dare to catch it. He was remembering the innocent face of Anil. Hari Singh thought what Anil would think about him.

Anil would not worry about the money but he might feel bad that a man had broken his faith. There was conflict in the mind of Hari Singh. He did not want to loose faith of Anil because he knew that Anil was a simple man.

Moreover Anil was teaching him how to write and add numbers which could change his life. He could become a respected person in the society.

He left the railway station. He came to the maidan and sat on the bench. Just then heavy rain started. It was the month of November. Chill wind started blowing. He felt more uncomfortable as he had cheated an innocent person.

His shirt and Pyjamas stuck to his body because it were wet due to the rain.

Then he went to the Clock Tower to save himself from the rain. He sat there under the tower. Suddenly he remembered his notes. He searched for it and found that all the notes were wet. He crept again and secretly put back money under the mattress.

The next day Anil woke up, prepared tea for Hari and himself. He handed over fifty rupees note to Hari and told him that he would be regularly paid now. Hari took the note and found that it was still wet. He understood that Anil knew about the last night’s episode.

The Thief’s Story Summary

ਦੋਸਤੀ Summary in punjabi

Footprints without Feet Summary Analysis and Explanation

Footprints without Feet Summary Analysis and Explanation

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Footprints without Feet Summary Analysis and Explanation By Herbert George Wells

About the Author
Herbert George Wells (21 September 1866 – 13 August 1946) was an English writer. He was prolific in many genres, writing dozens of novels, short stories, and works of social commentary, satire, biography, and autobiography, and even two books on recreational war games. He is now best remembered for his science fiction novels and is often called the “father of science fiction”, along with Jules Verne and Hugo Gernsback.

Author Name Herbert George Wells
Born 21 September 1866, Bromley High Street, London, United Kingdom
Died 13 August 1946, The Regent’s Park, London, United Kingdom
Short stories The Country of the Blind, The Red Room, The Star
Movies War of the Worlds, The Time Machine, The Invisible Man
Herbert George Wells - footprints without feet summary analysis and explanation
Herbert George Wells

Footprints without Feet Summary of the Lesson

Griffin was an eccentric scientist. He had discovered a rare drug which could make the human body transparent.

He had carried out an experiment after experiment to prove that the human body could become invisible. At last, he succeeded. He made his body as transparent as a glass by swallowing certain drugs and removing his clothes.

He was not liked by his landlord. He decided to take revenge on him. One day he set his landlord’s house on fire. Then he drank his rare drug and put off his clothes. Now, he could see everyone but none could see him.

He was safe from being caught. But he was without clothes and it was very cold. He passed the night in a London store. He stole goods and money from the store.

Then he went to a village called Iping. He stayed at an inn. He stole money from Clergyman’s desk. A policeman named Jeffers was called. A strange fight took place. Griffin took off his bandages, his glasses and his hat. Now he looked helpless. People were horrified of Griffin. He got free and ran away.

Footprints without Feet Summary

ਭਾਰਤ ਦਾ ਲਾਲ Summary In Punjabi

The Sermon at Benares Summary Analysis and Explanation

The Sermon at Benares Summary Analysis and Explanation

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The Sermon at Benares Summary Analysis and Explanation By Buddha

About the Poet Buddha

Poet Name Buddha
Born 8 April 563 BC, Lumbini, Nepal
Died Kushinagar
Full Name Siddhartha Gautama
Nationality Nepali
Buddha - The Sermon at Benares Summary class 10
Buddha

The Sermon at Benares Summary of the Lesson

Gautam Buddha was born in 563 BC in a royal family. He died in 483 B.C. He was known as Prince Siddhartha Gautam. At the age of twelve, he was sent away for schooling. He studied all the sacred Hindu scriptures. At the age of sixteen, he married a princess, had a son and lived for ten years as befitted royalty.

At the age of twenty-five years, he came across a sick man, an aged man, a funeral procession and finally a monk begging for alms. These sights moved him so much that he decided to leave his family.

He at once became a beggar and went out into the world to seek enlightenment concerning the sorrows he had witnessed. He wandered for seven years in search of wisdom and truth. Finally, he sat down under a peepal tree where he vowed to stay until enlightenment came.

Enlightened after seven days, he renamed the tree as the ‘Bodhi Tree’. ‘Bodhi Tree’ means the tree of wisdom. He became known as the Buddha which means ‘enlightenment’ or ‘the awakened’. He began to teach and to share his new understanding. He gave his first sermon at Benares.

His first sermon at Benares reflects his wisdom about one inscrutable kind of suffering i.e. Death. Here Buddha tells about the universality of death which is inevitable and can not be escaped.

Once the only son of Kisa Gotami died, she wanted him to be alive. On someone’s advice she approached Buddha with a request to give her a medicine so that her only son could be alive again. After a deep thought, the Buddha asked her to bring a handful of mustard seeds.

But it must be from that house where no one had died. Kisa Gotami went from door to door to get the mustard-seeds. She found mustard-seeds in every home but she could not find a house where nobody had died. Now she realised that death was common to all.

The Buddha said in his sermon that our life is brief. It is mixed with pain. After birth, one has to die. Death spares none. We should not grieve as grieving cannot bring peace to the mind. It rather brings pain to the body. Those who want peace should not lament or complain. Those who have overcome all sorrows will become free from sorrow and are blessed. They will be in peace.

The Sermon at Benares Summary

ਰੇਲ-ਗੱਡੀ ਆਈ Summary in punjabi

A Triumph of Surgery Summary Analysis and Explanation

A Triumph of Surgery Summary Analysis and Explanation

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A Triumph of Surgery Summary in English Analysis and Explanation By James Alfred Wight

About the Author 
James Alfred Wight (3 October 1916 – 23 February 1995), known by the pen name James Herriot, was a British veterinary surgeon and writer, who used his many years of experiences as a veterinary surgeon to write a series of books each consisting of stories about animals and their owners. He is best known for these semi-autobiographical works, beginning with If Only They Could Talk in 1970, which spawned a series of movies and television series.

Poet Name James Herriot
Born 3 October 1916, Sunderland, United Kingdom
Died 23 February 1995, Thirlby, United Kingdom
Spouse Joan Catherine Anderson Danbury (m. 1941–1995)
Movies All Creatures Great and Small, It Shouldn’t Happen to a Vet
James Herriot - A Triumph of Surgery Class 10 Summary
James Herriot

Summary of The Lesson A Triumph of Surgery

James Herriot is the author of ‘A Triumph of Surgery’. He writes mainly about pets and their care.

The theme of The Story A Triumph of Surgery is Mr. Pumphery was a rich and emotional lady who has a cute pet called Tricki. She loved him so much that she overfed him. Tricki had put on a lot of weight which made him lethargic. When doctor Herriot saw the fat dog like a bloated sausage he was shocked.

He made a plan and told Mrs. Pumphrey that Tricki needed treatment for an ailment which was possible only in the hospital. The doctor knew that Mrs. Pumphrey would not be able to keep the dog on a proper diet. The doctor took the dog to his house rather than a hospital.

When the greedy dog went to the author’s house. He had to remain hungry if he was slow to approach for food. He was given food at fixed intervals. Soon he shed off a lot of his body weight and became quite active.

When Tricki was at home he was pampered by Mrs. Pumphrey. He had a luxurious life when he was served with cream cake, chocolate, and Horlicks. But when he came to the doctor he became all right. When Mrs. Pumphrey saw her active dog she thanked the doctor and felt that it was a triumph of surgery.

ਦੀਪੂ ਨੇ ਛੁੱਟੀ ਲਈ Summary in punjabi

A Question of Trust Summary Analysis and Explanation

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A Question of Trust Summary Analysis and Explanation By Victor Canning

About the Author
Victor Canning (16 June 1911 – 21 February 1986) was a prolific British writer of novels and thrillers who flourished in the 1950s, 1960s and 1970s. He was personally reticent, writing no memoirs and giving relatively few newspaper interviews.

Author Name Victor Canning
Born 16 June 1911, Plymouth, United Kingdom
Died 21 February 1986, Cirencester, United Kingdom
Spouse Adria Irving-Bell (m. 1976–1986), Diana Bird (m. 1974–1976), Phyllis McEwen (m. 1935–1973)
Movies Venetian Bird, Golden Salamander, Shark
Victor Canning - a question of trust summary class 10
Victor Canning

A Question of Trust Summary of the Lesson

‘A Question of Trust’ is a very thrilling and interesting story written by the author Victor Canning. The story is full of paradoxes. Horace Danby had a good reputation in the society. He was about fifty and unmarried.

He made locks and had two helpers. He loved rare and expensive books. Horace robbed a safe every year. He was now out on committing a robbery.

For two weeks Horace had studied the house of Shotover Grange. He had to burgle this house. Horace Danby entered the house. Horace had allergy from flower; he started sneezing. Then he heard a voice. The voice told him that he could cure the sneeze. It was the voice of a woman.

She stood in the doorway. She was young and pretty. His first thought was to run. The lady told him that she would telephone the police. She would tell them about him. Horace Danby told her to let him go and forget she ever saw him. The lady put one condition for letting Horace go.

She told him that she promised her husband to take her jewel to the bank. She had, however, left jewels in the safe. She told him that she wanted to wear the jewels in a party that night. She came down to get them. But she had forgotten the numbers to open the safe.

So she needed his help and Horace opened the safe for her. After two days a policeman has arrested him for the jewel robbery at Shotover Grange. Danby’s fingerprint were found all over the room. He had opened the safe without gloves.

He said to the police that the landlady of the house asked him to open the safe. But the lady was 60 years old woman. She said Danby’s story was a nonsense.

Horace is now in prison. He often thinks of the charming and clever young lady. She was in the same profession. She had simply tricked him. Danby gets angry when anyone talks about “honour among thieves”.

ਸਾਡਾ ਦੇਸ Summary in punjabi