# DAV Class 8 Maths Chapter 5 Worksheet 2 Solutions

The DAV Class 8 Maths Book Solutions Pdf and DAV Class 8 Maths Chapter 5 Worksheet 2 Solutions of Profit, Loss and Discount offer comprehensive answers to textbook questions.

## DAV Class 8 Maths Ch 5 WS 2 Solutions

Question 1.
The marked price of a pant is ₹ 1250 and the shopkeeper allows a discount of 8% on it. Find the discount and the selling price of the pant.
Solution:
M.P. = ₹ 1250
Discount = 8% of M.P.
∴ Discount offered = $$\frac{8}{100}$$ × 1250 = ₹ 100
∴ Selling price = M.P. – Discount
= ₹ 1250 – ₹ 100 = ₹ 1150
Hence, the selling price of the pant = ₹ 1150
and the discount = ₹ 100.

Question 2.
The marked price of a water cooler is ₹ 5400. The shopkeeper offers an off season discount of 20% on it. Find its selling price.
Solution:
M.P. = ₹ 5400
Discount = 20% of M.P.
= $$\frac{20}{100}$$ × 5400 = ₹ 1080
∴ Selling price = M.P. – Discount
= ₹ 5400 – ₹ 1080 = ₹ 4320
Hence, the selling price = ₹ 4320. Question 3.
An almirah of marked price ₹ 4000 is sold for ₹ 3700 after allowing certain discount. Find the rate of discount.
Solution:
M.P. = ₹ 4000
and S.P. = ₹ 3700
∴ Discount = M.P. – S.P.
= ₹ 4000 – ₹ 3700 = ₹ 300
∴ Rate of discount = $$\frac{\text { Discount }}{\text { M.P. }}$$ × 100
= $$\frac{300}{4000}$$ × 100
= $$\frac{15}{2}$$ % or 7$$\frac{1}{2}$$ %
Hence, the required rate of discount is 7$$\frac{1}{2}$$%.

Question 4.
Find the rate of discount being given on a ceiling fan whose selling price is ₹ 1175 after allowing a discount of ₹ 75 on its marked price.
Solution:
S.P. = ₹ 1175
and Discount = ₹ 75
∴ M.P. = S.P. + Discount
= ₹ 1175 + ₹ 75 = ₹ 1250
Discount = $$\frac{\text { Discount }}{\text { M.P. }}$$ × 100
= $$\frac{75}{1250}$$ × 100 = 6%
Hence, the required rate of discount = 6%.

Question 5.
Find the marked price of a washing machine which is sold at ₹ 8400 after allowing a discount of 16%.
Solution:
S.P. = ₹ 8400
and Discount = 16%
Let the M.P. be ₹ x.
∴ Discount = $$\frac{16}{100}$$ × x
= ₹ $$\frac{4x}{25}$$
∴ S.P. = M.P. – Discount
= x – $$\frac{4x}{25}$$
= ₹ $$\frac{21 x}{25}$$
∴ $$\frac{21 x}{25}$$ = 8400
⇒ x = 8400 × $$\frac{25}{21}$$
⇒ x = 400 × 25 = 10000
Hence, the marked price = ₹ 10,000. Question 6.
A dinner set was bought for ₹ 2464 after getting a discount of 12% on its marked price. Find the marked price of the dinner set.
Solution:
C.P. = ₹ 2464
Discount = 12% of M.P.
Let the M.P. be ₹ x
∴ Discount = $$\frac{12}{100}$$ × x
= ₹ $$\frac{3 x}{25}$$
∴ C.P. = M.P. – Discount
= x – $$\frac{3 x}{25}$$
= ₹ $$\frac{22 x}{25}$$
∴ $$\frac{22 x}{25}$$ = 2464
⇒ x = $$\frac{2464 \times 25}{22}$$
⇒ x = 112 × 25 = 2800
Hence the marked price is ₹ 2800.

Question 7.
The marked price of a computer is ₹ 22,000. After allowing a 10% discount, a dealer still makes a profit of 20% . Find the cost price of a computer.
Solution:
M.P. = ₹ 22000
Discount = 10% of M.P.
= $$\frac{10}{100}$$ × 22000 = ₹ 2200

∴ S.P. = M.P. – Discount
= ₹ 22000 – ₹ 2200 = ₹ 19800
Let C.P. be ₹ x.
Profit = 20% of C.P.
= $$\frac{20}{100}$$ × x = ₹ $$\frac{x}{5}$$

∴ S.P. = C.P. + Profit
= x + ₹ $$\frac{x}{5}$$ = ₹ $$\frac{6 x}{5}$$
∴ $$\frac{6 x}{5}$$ = 19800
⇒ x = 19800 × $$\frac{5}{6}$$
⇒ x = 3300 × 5 = ₹ 16500
Hence, the cost price is ₹ 16500. Question 8.
The marked price of a double bed is ₹ 9575. A shopkeeper allows a discount of 12% on its marked price and still gains 10%. Find the cost price of the double bed.
Solution:
M.P. = ₹ 9575
Discount = 12% of M.P.
= $$\frac{12}{100}$$ × 9575 = ₹ 1149
∴ S.P. = M.P. – Discount
= ₹ 9575 – ₹ 1149 = ₹ 8426
Gain = 10%
∴ S.P. = C.P. (1 + $$\frac{\text { Gain }}{100}$$)
⇒ 8426 = C.P. (1 + $$\frac{10}{100}$$)
⇒ 8426 = C.P. ($$\frac{11}{10}$$)
⇒ C.P. = $$\frac{8426 \times 10}{11}$$
= 766 × 10 = ₹ 7660
Hence the cost price of the double bed = ₹ 7660.

Question 9.
A dealer buys a bicycle for ₹ 1,250 and marks it at 40% above its cost price. If he allows 8% discount, find
(i) Selling price of the bicycle
(ii) Profit percentage
Solution:
(i) C.P. of bicycle = ₹ 1250
M.P. of bicycle = C.P. + 40% of C.P.
= 1250 + $$\frac{40}{100}$$ × 1250
= 1250 + 500 = ₹ 1750

S.P. = M.P. (1 – $$\frac{\text { Discount% }}{100}$$)
= 1750 (1 – $$\frac{8}{100}$$)
= 1750 $$\left(\frac{100-8}{100}\right)$$
= 1750 $$\left(\frac{92}{100}\right)$$
= $$\frac{161000}{100}$$ = ₹ 1610

(ii) Profit = S.P. – C.P.
= 1610 – 1250 = ₹ 360
Profit = $$\frac{\text { Profit }}{\text { C.P. }}$$ × 100
= $$\frac{360 \times 100}{1250}$$
= $$\frac{144}{5}$$ = 28.8%. Question 10.
Priti allows 8% discount on the marked price of the suits and still makes a profit of 15%. If her gain over the sale of a suit is ₹ 156, find the marked price of the suit.
Solution:
Let M.P. be ₹ x.
∴ Discount = $$\frac{8}{100}$$ × M.P.
= $$\frac{8}{100}$$ × x
= $$\frac{2 x}{25}$$

∴ S.P. = M.P. – Discount
= x – $$\frac{2 x}{25}$$
= ₹ $$\frac{23 x}{25}$$

∴ S.P. = C.P. (1 + $$\frac{\text { Gain }}{100}$$)
⇒ $$\frac{23 x}{25}$$ = C.P. (1 + $$\frac{15}{100}$$)
∴ $$\frac{23 x}{25}$$ = C.P. × $$\frac{23}{20}$$
⇒ C.P. = $$\frac{23 x}{25} \times \frac{20}{23}=₹ \frac{4 x}{5}$$

∴ Gain = S.P. – C.P.
= $$\frac{23 x}{25}-\frac{4 x}{5}=₹ \frac{3 x}{25}$$
∴ $$\frac{3 x}{25}$$ = 156
⇒ x = $$\frac{156 \times 25}{3}$$
⇒ 52 × 25 = ₹ 1300
Hence the marked price is ₹ 1300.