DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

The DAV Class 8 Maths Book Solutions Pdf and DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions of Profit, Loss and Discount offer comprehensive answers to textbook questions.

DAV Class 8 Maths Ch 5 WS 1 Solutions

Question 1.
By selling a bedsheet for ₹ 640, a shopkeeper earns a profit of 28%. How much did it cost the shopkeeper?
Solution:
S.P. = ₹ 640
Profit = 28%
C.P. = ?
S.P. = C.P. (1 + \(\frac{\text { Profit }}{100}\))
⇒ 640 = C.P. (1 + \(\frac{28}{100}\))
⇒ 640 = C.P. × \(\frac{128}{100}\)
⇒ C.P. = \(\frac{640 \times 100}{128}\) = ₹ 500
Hence, the required cost price is ₹ 500.

DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

Question 2.
Rajan purchased 250 packets of blades at the rate of ₹ 8 per packet. He sold 70% of the packets at the rate of ₹ 11 per packet and the remaining packets at the rate of ₹ 9 per packet. Find the gain percent.
Solution:
Cost price of 250 packets = 250 × 8 = ₹ 2000
70 % of 250, i.e. 175 packets are sold for ₹ 11 per packet
∴ S.P. of 175 packets = 11 × 175 = ₹ 1925
The remaining packets are 250 – 175 = 75
∴ S.P. of 75 packets = 75 × 9 = ₹ 675
∴ Total S.P. = ₹ 1925 + ₹ 675 = ₹ 2600
∴ Gain = S.P. – C.P. = 2600 – 2000 = ₹ 600
∴ Gain % = \(\frac{\text { Gain }}{\text { C.P. }}\) × 100
= \(\frac{600}{2000}\) × 100 = 30%
Hence, the gain % is 30%.

Question 3.
Ankit sold two jeans for ₹ 990 each. On one, he gains 10% and on the other he lost 10%. Find his gain or loss per cent in the whole transaction.
Solution:
S.P. of two jeans = 2 × 990 = ₹ 1980
Now for 1st jeans,
S.P. = C.P. (1 + \(\frac{\text { Gain }}{100}\))
⇒ 990 = C.P. (1 + \(\frac{10}{100}\))
⇒ 990 = C.P. × \(\frac{110}{100}\)
⇒ C.P. = \(\frac{990 \times 100}{110}\) = ₹ 900

For 2nd jeans,
S.P. = C.P. (1 – \(\frac{\text { Loss }}{100}\))
990 = C.P. (1 – \(\frac{10}{100}\))
990 = C.P. × \(\frac{90}{100}\)
C.P. = \(\frac{990 \times 100}{90}\) = 1100.
∴ Total C.P. = ₹ 900 + ₹ 1100 = ₹ 2000
Now C.P. > S.P.
∴ Loss = ₹ 2000 – ₹ 1980 = ₹ 20
∴ Loss % = \(\frac{\text { Loss }}{\text { C.P. }}\) × 100
= \(\frac{20}{2000}\) × 100 = 1 %.
Hence the loss = 1 %.

DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

Question 4.
Nidhi purchased two sarees for ₹ 2150 each. She sold one saree at a loss of 8% and the other at a gain. If she had a gain of ₹ 1230 on the whole transaction, find the selling price of the second saree.
Solution:
C.P. for one saree = ₹ 2150
Loss = 8%
∴ S.P. = C.P. [1 – \(\frac{\text { Loss }}{100}\)]
= 2150 [1 – \(\frac{8}{100}\)]
= 2150 × \(\frac{92}{100}\) = 1978

Let gain on the other saree be ₹ x.
∴ S.P. for other saree = (₹ 2150 + ₹ x)
∴ Total S.P. for 2 sarees = ₹ 1978 + ₹ 2150 + ₹ x = ₹ (4128 + x)
Total C.P. for 2 sarees = 2 × 2150 = ₹ 4300
∴ Total gain on the whole transaction = S.P. – C.P.
= ₹ (4128 + x) – ₹ 4300 = ₹ (x – 172)
∴ x – 172 = 1230
⇒ x = 1230 + 172 = 1402
∴ S.P. for second saree = C.P. + Gain
= ₹ 2150 + ₹ 1402 = ₹ 3552.

Question 5.
By selling 35 greeting cards, a shopkeeper loses an amount equal to the selling price of 5 greeting cards. Find his loss per cent.
Solution:
Let S.P. for one greeting card be ₹ x.
∴ S.P. for 35 greeting cards = ₹ 35x
and Loss = ₹ 5x
∴ C.P. = S.P. + Loss
= ₹ 35x + ₹ 5x = ₹ 40x
∴ Loss % = \(\frac{\text { Loss }}{\text { C.P. }}\) x 100
= \(\frac{5 x}{40 x}\) x 100
= \(\frac{25}{2}\)
= 12 \(\frac{1}{2}\)%
Hence, the loss = 12\(\frac{1}{2}\)%.

DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

Question 6.
A man bought bananas at the rate of 10 for ₹ 15 and sold at the rate of one dozen bananas for ₹ 15. Find his gain or loss per cent.
Solution:
C.P. for 10 bananas = ₹ 15
∴ C.P. for 1 banana = ₹ \(\frac{15}{10}\) = ₹ 1.50
S.P. for 12 bananas = ₹ 15
∴ S.P. for 1 banana = ₹ \(\frac{15}{12}\) = ₹ 1.25
Here C.P. > S.P.
∴ Loss = C.P. – S.P
= 1.50 – 1.25 = ₹ 0.25
∴ Loss percent = \(\frac{\text { Loss } \times 100}{\text { C.P. }}\)
= \(\frac{0.25 \times 100}{1.50}\)
= \(\frac{50}{3}\)
= \(16 \frac{2}{3}\) %
Hence, the loss per cent is 16 \(\frac{2}{3}\) %.

DAV Class 8 Maths Chapter 5 Worksheet 1 Notes

Cost price (C.P) :
The price at which an article is purchased or manufactured is called its cost price (C.P.).

Selling price (S.P):
The price at which an article is sold is called its selling price (S.P.).

Profit = S.P. – C.P.
Profit % = \(\frac{\text { Profit }}{\text { C.P. }}\) × 100

Loss = C.P. – S.P.
Loss % = \(\frac{\text { Loss }}{\text { C.P. }}\) × 100
[Note: Profit and Loss are always calculated on the cost price of the article]

Direct formulae

(i) S.P. = C.P. (1 + \(\frac{\text { Profit }}{100}\))
(ii) S.P. = C.P. (1 – \(\frac{\text { Loss }}{100}\))

Market Price:
The price written on the article or tagged with a card is called its Market value.

Discount:
It is a certain percentage of rebate on the market price offered by the shopkeeper.
Discount = M.P. – S.P.

Discount % = \(\frac{\text { Discount }}{\text { M.P. }}\) × 100

Value Added Tax (VAT):
It is a new method of realising tax by the Government at every sale/purchase right from the manufacturer to the retailer. It is not in addition to the existing sales tax, but is the replacement of Sales Tax.

DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

Example 1.
Find the profit or loss per cent, if
(i) C.P. = ₹ 55 and S.P. = ₹ 72.60
(ii) C.P. = ₹ 112, overheads = ₹ 14 and S.F. = ₹ 49.50.
Solution:
(i) Here S.P. > C.P.
∴ Profit = S.P. – C.P.
= 72.60 – 55
= ₹ 17.60

∴ Profit % = \(\frac{\text { Profit }}{\text { C.P. }}\) × 100
=\(\frac{17.60}{55}\) × 100 = 32%.

(ii) C.P. = ₹ 112 and overheads = ₹ 14
∴ Net C.P. = 112 + 14 = 126
S.P. = ₹ 49.50
Here C.P. > S.P.
∴ Loss = C.P. – S.P.
= ₹ 126 – ₹ 94.50
= ₹ 31.50
∴ Loss % = \(\frac{\text { Loss } \times 100}{\text { C.P. }}\)
= \(\frac{31.50 \times 100}{126}\)
= 25%.

Example 2.
Find C.P. when a bicycle is sold for ₹ 1485 at a profit of 8%.
Solution:
Here S.P. = ₹ 1485;
Profit = 8%;
C.P. = ?
S.P. = C.P. [1 + \(\frac{\text { Profit }}{100}\)]
⇒ 1485 = C.P. [1 + \(\frac{8}{100}\)]
⇒ 1485 = C.P. × \(\frac{108}{100}\)
⇒ C.P. = \(\frac{1485 \times 100}{108}\) = ₹ 1375.

DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

Example 3.
If oranges are bought at 11 for ₹ 30 and sold 10 for 31. Find the loss or gain per cent.
Solution:
C.P. for 11 oranges = ₹ 30
∴ C.P. for 1 orange = ₹ \(\frac{30}{11}\)
SP. for 10 oranges = ₹ 31
S.P. for 1 orange = ₹ \(\frac{31}{10}\)
Here S.P. > C.P.
∴ Gain = S.P. – C.P.
= ₹ \(\frac{31}{10}\) – ₹ \(\frac{30}{11}\)
= ₹ \(\frac{41}{110}\)
∴ Gain % = \(\frac{\text { Gain }}{\text { C.P. }}\) × 100
= \(\frac{\frac{41}{110}}{\frac{30}{11}}\) × 100
= \(\frac{41}{3} \%=13 \frac{2}{3} \%\).

Example 4.
By selling a book for ₹ 115.20, a man loses 10%. At what price should he il it to gain 5%?
Solution:
S.P. = ₹ 115.20;
Loss = 10%
C.P. =?
∴ S.P. = C.P. (1 – \(\frac{\text { Loss }}{100}\))
115.20 = C.P. (1 – \(\frac{10}{100}\))
115.20 = C.P. × \(\frac{90}{100}\)
C.P. = \(\frac{115.20 \times 100}{90}\) = ₹ 128
Now C.P. = 128;
Gain = 5%;
S.P. = ?
∴ S.P. = C.P. (1 + \(\frac{\text { Gain }}{100}\))
= 128 (1 + \(\frac{5}{100}\))
= \(\frac{128 \times 105}{100}\)
= ₹ 134.40

DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

Example 5.
Find the rate of discount being given on a sweater whose price has been slahed down from ₹ 975 to ₹ 760.50.
Solution:
Discount = ₹ 975 – ₹ 760.50 = ₹ 214.50
Rate of discount = \(\frac{\text { Discount }}{\text { M.P. }}\) × 100
= \(\frac{214.50}{975}\) × 100 = 22%
Hence, the rate of discount given = 22%.

Example 6.
A shopkeeper fixed the market price of an item 35% above its cost price. Find the discount per cent so a to gain 8%.
Solution:
Let C.P. be ₹ x.
∴ M.P. = x + \(\frac{35}{100}\) x
= ₹ \(\frac{27}{20}\) x

S.P. = C.P. (1 + \(\frac{\text { Gain }}{100}\))
= x (1 + \(\frac{8}{100}\))
= ₹ \(\frac{27}{25}\) x

Discount = M.P. – S.P.
= \(\frac{27}{20}\) x – \(\frac{27}{25}\) x
= ₹ \(\frac{27 x}{100}\)

Discount % = \(\frac{\text { Discount }}{\text { M.P. }}\) × 100
= \(\frac{\frac{27 x}{100}}{\frac{27 x}{20}}\) × 100
= 20%
Hence, the discount is 20%.

DAV Class 8 Maths Chapter 5 Worksheet 1 Solutions

Example 7.
A shopkeeper bought a TV at a discount of 30% of the list price of ₹ 24000. He offers a discount of 10% of the listed price to his customer. If the VAT is 10%, find:
(i) The amount paid by the customer.
(ii) The VAT to be paid by the shopkeeper.
Solution:
List price = ₹ 24000
Discount = 30%
Selling price = 24000 – \(\frac{30}{100}\) × 24000
= ₹ 24000 – ₹ 7200
= ₹ 16800

Tax = \(\frac{10}{100}\) × 16800 = ₹ 1680

New S.P. to customer = 24000 – 24000 × \(\frac{10}{100}\)
= ₹ 24000 – ₹ 2400 = ₹ 21600

(i) Amount paid by customer = ₹ 21600 + ₹ 2160 = ₹ 23760
(ii) Total VAT to be paid by the shopkeeper = ₹ 2160 – ₹ 1680 = ₹ 480.