The DAV Class 6 Maths Solutions and **DAV Class 6 Maths Chapter 5 Worksheet 5 **Solutions of Percentage and its Applications offer comprehensive answers to textbook questions.

## DAV Class 6 Maths Ch 5 WS 5 Solutions

Question 1.

Find the simple interest on ₹ 1300 at the rate of 5% per annum for 146 days.

Solution:

Here, P = ₹ 1300,

R = 5% p.a.,

T= 146 days

= \(\frac{146}{365}\) =\(\frac{2}{5}\) years

∴ Simple interest S.I. = \(\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{T}}{100}\)

=

= ₹ 26

Hence, the required interest = ₹ 26.

Question 2.

Find the amount Meena gets on depositing ₹ 1500 at 8% per annum for 73 days.

Solution:

Here, P = ₹ 1500,

R = 8% p.a.,

T = 73 days

= \(\frac{73}{365}\) year

= \(\frac{1}{5}\) year

∴ Simple interest S.I. = \(\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{T}}{100}\)

= \(\frac{1500 \times 8 \times 1}{100 \times 5}\)

= ₹ 24

Amount = P + S.I

= ₹ 1500 + ₹ 24 = ₹ 1524

Hence the required amount deposited = ₹ 1524.

Question 3.

What amount will Reena get by investing ₹ 4500 at 4 \(\frac{1}{2}\) % per annum for the period from September 8 to November 20 of the year 2015?

Solution:

Here, P = 4500,

R = 4\(\frac{1}{2}\) % p.a.

= \(\frac{9}{2}\) p.a.

T = From September 8 to November 20

T = 23 days of Sept. + 31 days of Oct. + 19 days of November

T = \(\frac{73}{365}\) year

= \(\frac{1}{5}\) year

∴ Simple interest, S.I. = \(\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{T}}{100}\)

= \(\frac{4500 \times 9 \times 1}{100 \times 2 \times 5}\)

= ₹ 40.50

Amount = P + S.I.

= ₹ 4500 + ₹ 40.50 = ₹ 4540.50

Hence the required amount deposited = ₹ 4540.50.

Question 4.

Find the simple interest on 3500 at 4% per annum from 15 March to 18 August 2015.

Solution:

Here, P = ₹ 3500,

R = 4\(\frac{1}{2}\) % p.a.

= \(\frac{9}{2}\) p.a.

T = From 15 March to 8 August

T = 17 days of March + 30 days of April + 31 days of May + 30 days of June + 31 days of July + 7 days of August

∴ Simple interest, S.I. = \(\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{T}}{100}\)

= \(\frac{3500 \times 9 \times 146}{100 \times 2 \times 365}\)

= ₹ 63.

### DAV Class 6 Maths Chapter 5 Value Based Questions

Question 1.

An NGO (Non-Government Organisation) working for the flood relief fund collected a sum of ₹ 80000 from different societies of a locality. 65% of this amount was spent for buying grocery items. Rest of the amount was spent on clothes for the affected people. The flood affected victims were very thankful to the NGO members.

(a) What amount was spent on grocery items?

Solution:

Total amount collected = ₹ 80000

Spent on grocery items = 65 % of ₹ 80000

= \(\frac{65}{100}\) × ₹ 80000

= ₹ 52000

(b) Write any two more ways in which you can help the flood affected victims.

Solution:

Donating clothes, medicines.

Question 2.

During winter season, the Manav Seva Samiti decided to distribute blankets and shawls to some poor people of a locality. A total of 150 packets were distributed. 74% of the poor people received shawls and the others got blankets. The poor people were very happy with the shawls and blankets.

(a) How many blankets were distributed?

Solution:

Percentage of poor people who received shawls = 74%

∴ Percentage of poor people who received blankets = (100 – 74) = 26%

∴ No. of people, who received blanket = 26 % of 150

= \(\frac{26}{100}\) × 150

= 39

(b) Name two more items that you have donated to any poor person.

Solution:

Food packets, medicines.