The DAV Maths Book Class 5 Solutions and **DAV Class 5 Maths Chapter 7 Worksheet 13** Solutions of Multiplication and Division of Decimal Numbers offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 7 Worksheet 13 Solutions

Question 1.

Solve the following word problems.

(a) 12 tins can hold 39.624 litres of oil. How much oil can one tin hold?

Solution:

Capacity of 12 tins = 39.624 l

Capacity of 1 tin = 39.624 ÷ 12

One tin can hold 3.052 l.

(b) Cost of 23 m of cloth is ₹ 608.50. Find the cost of one metre of cloth.

Solution:

Cost of 23 m of cloth = ₹ 608.50

Cost of 1 m of cloth = ₹ 608.50 ÷ 23

The cost of one metre of cloth is ₹ 26.45.

(c) I have a 7.5 m long ribbon. I want to cut it into 1.5 m long pieces. How many pieces will I get?

Solution:

Total length of ribbon = 7.5m

Length of one piece = 1.5m

He will get 5 pieces.

(d) 16.5 kg sugar is put in paper bags each containing 0.5 kg of it. How many bags are there?

Solution:

Total wt. of sugar = 16.5 kg

wt. of sugar in 1 paper bag = 0.5 kg

33 bags are there.

(e) I require 2.25 m cloth to stitch a skirt. How many skirts can be stitched with 20.25 m cloth?

Solution:

Total length of cloth = 20.25 m

Length of cloth required to stitch a skirt = 2.25 m

No. of skirts can be stitched with cloth

9 skirts can be stitched with 20.25 m cloth.

### DAV Class 5 Maths Chapter 7 Value Based Questions

Manju was excited when she woke up in the morning. It was her birthday! Her parents asked her what gift she would like to have. She told her mother that this time she wanted to distribute sweets to the poor children near the temple. Her parents were very happy with this thought. They bought 25.625 kg. sweets and distributed amongst 25 children near the temple. Manju and her parents were happy to see smiles on the children’s place.

Question 1.

How much sweets did each child get?

Solution:

No. of children = 25

Amount of sweets = 25.625 kg

Sweets each child get = 25.625 ÷ 25

Each child got 1.25 kg of sweets.

Question 2.

What quality of Manju is exhibited here?

Solution:

The kind and generous nature of Manju is exhibited here.

Question 3.

Suggest two different ways in which you can celebrate your birthday as Manju did.

Solution:

Two different ways are:

- Celebrating birthdays with old age in an old age home and giving small gifts to each of them.
- By giving small gifts to children living in orphanages.

By doing this we can make happy both children and old ages.

Word Problem

Example.

Rahim bought 27 balls for ₹ 56.97. Find the cost of one ball.

Solution:

Cost of 27 balls = ₹ 56.97

Cost of one ball = ₹ 56.97 ÷ 27

One ball costs ₹ 2.11