The DAV Books Solutions Class 5 Maths and **DAV Class 5 Maths Chapter 13 Worksheet 3** Solutions of Simple Interest offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 13 Worksheet 3 Solutions

Question 1.

Find the amount for the following:

Solution:

(a) P = ₹ 1,500, I = ₹ 150

A = P + I

= ₹ 1500 + ₹ 150

= ₹ 1650

(b) P = ₹ 750, I = ₹ 35

A = P + I

= ₹ 750 + ₹ 35

= ₹ 785

(c) P = ₹ 15,000, I = ₹ 980

A = P + I

= ₹15,000 + ₹ 980

= ₹ 15,980

(d) P = ₹ 4500, I = ₹ 215

A = P + I

= ₹ 4,500 + ₹ 215

= ₹ 4,715

Question 2.

Fill in the blanks:

Solution:

(a) P = ₹ 800, SI = ?, A = ₹ 905

A = P + I

905 = 800 + I

905 – 800 = I

105 = I

I = ₹ 105

(b) SI = ₹ 75.50, A = ₹ 450, P = ?

A = SI + P

450 = 75.50 + P

450 – 75.50 = P

P = ₹ 374.50

(c) P = ₹ 25,000, SI = ?, A = ₹ 31,000

A = P + SI

31,000 = 25,000 + SI

31,000 – 25,000 = I

SI = ₹ 6,000

(d) SI = ₹ 515, A = ₹ 1,680, P = ?

A = P + SI

1,680 = P + 515

P = 1,680 – 515 = ₹ 1,165

Question 3.

Calculate the amount for the following:

(a) ₹ 4,000 at 9% per annum for 3 years.

Solution:

A = ?

P = ₹ 4,000

R = 9%

T = 3 years

SI = ?

SI = PRT

= 4,000 × 3 × \(\frac{9}{100}\)

= ₹ 1,080

A = P + SI

= ₹ 4,000 + ₹ 1,080

= ₹ 5,080

(b) ₹ 750 at 3\(\frac{1}{2}\)% per annum for 2 years.

Solution:

P = ₹ 750

R = 3\(\frac{1}{2}\)% = \(\frac{7}{2}\)% = \(\frac{7}{200}\)

T = 2 years

SI = ?

SI = PRT

= 750 × \(\frac{7}{200}\) × 2

= ₹ 52.5

A = P + SI

= ₹ 750 + ₹ 52.5

= ₹ 802.50

(c) ₹ 3,200 at 7\(\frac{1}{2}\)% per annum for 3\(\frac{1}{2}\) years.

Solution:

P = ₹ 3,200

R = 7\(\frac{1}{2}\)% = \(\frac{15}{2}\)% = \(\frac{15}{200}\)

T = 3\(\frac{1}{2}\) years = \(\frac{7}{2}\) years

SI = ?

SI = PRT

= 3,200 × \(\frac{15}{200} \times \frac{7}{2}\)

= ₹ 840

A = SI + P

= ₹ 840 + ₹ 3,200

= ₹ 4,040

(d) ₹ 900 at 5% per annum for 5\(\frac{1}{2}\) years.

Solution:

P = ₹ 900

R = 5%

T = 5\(\frac{1}{2}\) years = \(\frac{11}{2}\) years

SI = ?

SI = PRT

= 900 × \(\frac{5}{100} \times \frac{11}{2}\)

= ₹ 247.50

A = P + SI

= ₹ 900 + ₹ 247.50

= ₹ 1,147.50

Question 4.

Solve the following questions:

(a) Arun took a loan of ₹ 600 for 1\(\frac{1}{2}\) years with interest at the rate of 4% per annum. Find the interest he pays after 1\(\frac{1}{2}\) years . Also, calculate the amount he pays back after 1\(\frac{1}{2}\) years.

Solution:

Principal = ₹ 600

T = 1\(\frac{1}{2}\) years = \(\frac{3}{2}\) years

R = 4% = \(\frac{4}{100}\)

SI = P × R × T

= 600 × \(\frac{4}{100} \times \frac{3}{2}\)

= ₹ 36

A = ₹ 600 + ₹ 36 = ₹ 636

He pays interest of ₹ 36 and total amount ₹ 636 after 1\(\frac{1}{2}\) years.

(b) Amit deposited ₹ 4,800 in his account. The bank pays an interest of 6% per annum. What amount will Amit get back after three years?

Solution:

Principal = ₹ 4,800

R = 6% per annum

T = 3 years

SI = P × R × T

= 4,800 × \(\frac{6}{100}\) × 3

= ₹ 864

A = P + I

= ₹4,800 + ₹ 864

= ₹ 5,664

Amit will get back ₹ 5,664 after three years.

(c) A man borrowed ₹ 700 from his friend. He promised to return the amount after six months at an interest of 8% per annum. How much money will he pay back after six months?

Solution:

Principal = ₹ 700

R = 8%

T = 6 months = \(\frac{1}{2}\) year

SI = P × R × T

= 700 × \(\frac{8}{100} \times \frac{1}{2}\)

= ₹ 28

A = SI + P

= ₹ 700 + ₹ 28

= ₹ 728

He will pay back ₹ 728 after 6 months.

(d) Surender deposited ₹ 2,500 in a bank at 12% interest per annum. He withdraws his money after 2\(\frac{1}{2}\) years. Out of this amount, he buys an almirah for ₹ 3,000. How much money is left with him?

Solution:

P = ₹ 2,500

R = 12%

T = 2\(\frac{1}{2}\) = \(\frac{5}{2}\) years

SI = P × R × T

= 2,500 × \(\frac{12}{100} \times \frac{5}{2}\)

= ₹ 750

A = P + I

= ₹ 2,500 + ₹ 750

= ₹ 3,250

Cost of almirah = ₹ 3,000

Amount left = A – cost of almirah

= ₹ 3,250 – ₹ 3,000

= ₹ 250

₹ 250 is left with him.

### DAV Class 5 Maths Chapter 13 Value Based Questions

Nakul’s father Mr. Gupta got transferred from Delhi to Mumbai. Mr. Gupta had deposited ₹ 55000 in the Punjab National Bank two years before at 8% per annum. He closed the account and with the interest money he purchased gifts for his friends and family members. Nakul also got two pairs of jeans, two shirts, and a video game as a gift. Nakul with the permission of his parents gifted one jean and one shirt to Rahul, the son of the milkman. Rahul was very happy and thanked Nakul for the gift.

Question 1.

How much money did Mr Gupta get from the bank?

Solution:

Principal = ₹ 55,000

T = 2 years

R = 8% = \(\frac{8}{100}\) per annum

SI = PRT

= 55,000 × \(\frac{8}{100}\) × 2

= ₹ 8,800

A = P + I

= ₹ 55000 + ₹ 8800

= ₹ 63,800

Mr. Gupta got ₹ 63,800 from the bank.

Question 2.

How much money was spent by Mr Gupta on gifts?

Solution:

Interest = ₹ 8,800

With interest money, he purchased a gift. So he purchased a shirt and jeans for ₹ 8,800.

Question 3.

How do you feel when you gift/donate anything to the needy?

Solution:

When we gift/donate anything to the needy we feel happy and self-satisfied.

**DAV Class 5 Maths Chapter 13 Worksheet 3 Notes**

**Concept of Amount**

The amount we get back after a certain period of time is the sum of Principal and Interest.

- Amount = Principal + Interest
- Principal = Amount – Interest
- Interest = Amount – Principal

Example 1.

Sarita deposited ₹ 3,000 in a bank at 8% interest per annum. What amount will she get back after 3\(\frac{1}{2}\) years?

Solution:

Principal = ₹ 3,000

R = 8% = \(\frac{8}{100}\)

Time = 3\(\frac{1}{2}\) years = \(\frac{7}{2}\) years

SI = P × R × T

= 3,000 × \(\frac{8}{100} \times \frac{7}{2}\)

= ₹ 840

Amount received at the end of 3\(\frac{1}{2}\) years = P + Interest

= ₹ 3,000 + ₹ 840

= ₹ 3,840