# DAV Class 5 Maths Chapter 12 Worksheet 4 Solutions

The DAV Books Solutions Class 5 Maths and DAV Class 5 Maths Chapter 12 Worksheet 4 Solutions of Percentage offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 12 Worksheet 4 Solutions

Question 1.
Find the value of the following:
(a) 50% of 10
Solution:
50% of 10 = $$\frac{50}{100}$$% of 10
= $$\frac{50}{100}$$ × 10
= 5

(b) 60% of 700
Solution:
60% of 700 = $$\frac{60}{100}$$% of 700
= $$\frac{60}{100}$$ × 700
= 420

(c) 24% of 75
Solution:
24% of 75 = $$\frac{24}{100}$$% of 75
= $$\frac{24}{100}$$ × 75
= 18

(d) 6$$\frac{1}{4}$$% of 800
Solution:
6$$\frac{1}{4}$$% of 800 = $$\frac{25}{4}$$% of 800
= $$\frac{25}{4 \times 100}$$ × 800
= 50

(e) 16$$\frac{2}{3}$$% of 1200
Solution:
16$$\frac{2}{3}$$% of 1200 = $$\frac{50}{3}$$% of 1200
= $$\frac{50}{300}$$ × 1200
= 200

(f) 33$$\frac{1}{3}$$% of 300
Solution:
33$$\frac{1}{3}$$ % of 300 = $$\frac{100}{3}$$% of 300
= $$\frac{100}{3 \times 100}$$ × 300
= 100

(g) 75% of 300
Solution:
75% of 300 = $$\frac{75}{100}$$% of 300
= $$\frac{75}{100}$$ × 300
= 225

(h) 3$$\frac{3}{4}$$% of 80
Solution:
3$$\frac{3}{4}$$% of 80 = $$\frac{15}{4}$$% of 80
= $$\frac{15}{4 \times 100}$$ × 80
= 3

Question 2.
Find the value of the following:
(a) 3% of ₹ 600
Solution:
3% of ₹ 600 = $$\frac{3}{100}$$ of ₹ 600
= $$\frac{3}{100}$$ × 600
= ₹ 18

(b) 1% of 100 kg
Solution:
1% of 100 kg = $$\frac{1}{100}$$ of 100 kg
= $$\frac{1}{100}$$ × 100
= 1 kg

(c) 20% of 5 kilometres
Solution:
20% of 5 kilometres = $$\frac{20}{100}$$ of 5 km
= $$\frac{20}{100}$$ × 5
= 1 km

(d) 90% of 500 marks
Solution:
90% of 500 marks = $$\frac{90}{100}$$ of 500 marks
= $$\frac{90}{100}$$ × 500
= 450 marks

(e) 150% of 20 litres
Solution:
150% of 20 litres = $$\frac{150}{100}$$ of 20 l
= $$\frac{150}{100}$$ × 20
= 30 l

(f) 8% of 200 grams
Solution:
8% of 200 grams = $$\frac{8}{100}$$ of 200 gm
= $$\frac{8}{100}$$ × 200
= 16 gm

(g) 12$$\frac{1}{2}$$% of 1 kilogram
Solution:
12$$\frac{1}{2}$$% of 1 kilogram = $$\frac{25}{2}$$% of 1 kg
= $$\frac{25}{200}$$ × 1
= $$\frac{1 \times 1}{8}$$
= 0.125 kg or 125 gm

(h) $$\frac{3}{4}$$% of ₹ 8,800
Solution:
$$\frac{3}{4}$$% of ₹ 8,800 = $$\frac{3}{400}$$ of ₹ 8,800
= $$\frac{3}{400}$$ × 8800
= ₹ 66

Question 3.
Find which is more of the two:
(a) 15% of 200 or 20% of 100
Solution:
15% of 200 or 20% of 100
15% of 200 = $$\frac{15}{100}$$ × 200 = 30
20% of 100 = $$\frac{20}{100}$$ × 100 = 20
30 > 20
Thus, 15% of 200 > 20% of 100

(b) 34% of 250 or 18% of 150
Solution:
34% of 250 or 18% of 150
34% of 250 = $$\frac{34}{100}$$ × 250 = 85
18% of 150 = $$\frac{18}{100}$$ × 150 = 27
85 > 27
Thus, 34% of 250 > 18% of 150

Word Problems

Example 1.
Find 20% of 50.
Solution:
20% of 50 = $$\frac{20}{100}$$ × 50
= $$\frac{20 \times 50}{100}$$
= $$\frac{1000}{100}$$
= 10

Example 2.
Find 33$$\frac{1}{3}$$% of 1,800 kg.
Solution:
33$$\frac{1}{3}$$% of 1,800 = $$\frac{100}{3}$$% of 1,800
= $$\frac{100}{3 \times 100}$$ × 1800
= $$\frac{1800}{3}$$
= 600