The DAV Books Solutions Class 5 Maths and **DAV Class 5 Maths Chapter 12 Worksheet 4** Solutions of Percentage offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 12 Worksheet 4 Solutions

Question 1.

Find the value of the following:

(a) 50% of 10

Solution:

50% of 10 = \(\frac{50}{100}\)% of 10

= \(\frac{50}{100}\) × 10

= 5

(b) 60% of 700

Solution:

60% of 700 = \(\frac{60}{100}\)% of 700

= \(\frac{60}{100}\) × 700

= 420

(c) 24% of 75

Solution:

24% of 75 = \(\frac{24}{100}\)% of 75

= \(\frac{24}{100}\) × 75

= 18

(d) 6\(\frac{1}{4}\)% of 800

Solution:

6\(\frac{1}{4}\)% of 800 = \(\frac{25}{4}\)% of 800

= \(\frac{25}{4 \times 100}\) × 800

= 50

(e) 16\(\frac{2}{3}\)% of 1200

Solution:

16\(\frac{2}{3}\)% of 1200 = \(\frac{50}{3}\)% of 1200

= \(\frac{50}{300}\) × 1200

= 200

(f) 33\(\frac{1}{3}\)% of 300

Solution:

33\(\frac{1}{3}\) % of 300 = \(\frac{100}{3}\)% of 300

= \(\frac{100}{3 \times 100}\) × 300

= 100

(g) 75% of 300

Solution:

75% of 300 = \(\frac{75}{100}\)% of 300

= \(\frac{75}{100}\) × 300

= 225

(h) 3\(\frac{3}{4}\)% of 80

Solution:

3\(\frac{3}{4}\)% of 80 = \(\frac{15}{4}\)% of 80

= \(\frac{15}{4 \times 100}\) × 80

= 3

Question 2.

Find the value of the following:

(a) 3% of ₹ 600

Solution:

3% of ₹ 600 = \(\frac{3}{100}\) of ₹ 600

= \(\frac{3}{100}\) × 600

= ₹ 18

(b) 1% of 100 kg

Solution:

1% of 100 kg = \(\frac{1}{100}\) of 100 kg

= \(\frac{1}{100}\) × 100

= 1 kg

(c) 20% of 5 kilometres

Solution:

20% of 5 kilometres = \(\frac{20}{100}\) of 5 km

= \(\frac{20}{100}\) × 5

= 1 km

(d) 90% of 500 marks

Solution:

90% of 500 marks = \(\frac{90}{100}\) of 500 marks

= \(\frac{90}{100}\) × 500

= 450 marks

(e) 150% of 20 litres

Solution:

150% of 20 litres = \(\frac{150}{100}\) of 20 l

= \(\frac{150}{100}\) × 20

= 30 l

(f) 8% of 200 grams

Solution:

8% of 200 grams = \(\frac{8}{100}\) of 200 gm

= \(\frac{8}{100}\) × 200

= 16 gm

(g) 12\(\frac{1}{2}\)% of 1 kilogram

Solution:

12\(\frac{1}{2}\)% of 1 kilogram = \(\frac{25}{2}\)% of 1 kg

= \(\frac{25}{200}\) × 1

= \(\frac{1 \times 1}{8}\)

= 0.125 kg or 125 gm

(h) \(\frac{3}{4}\)% of ₹ 8,800

Solution:

\(\frac{3}{4}\)% of ₹ 8,800 = \(\frac{3}{400}\) of ₹ 8,800

= \(\frac{3}{400}\) × 8800

= ₹ 66

Question 3.

Find which is more of the two:

(a) 15% of 200 or 20% of 100

Solution:

15% of 200 or 20% of 100

15% of 200 = \(\frac{15}{100}\) × 200 = 30

20% of 100 = \(\frac{20}{100}\) × 100 = 20

30 > 20

Thus, 15% of 200 > 20% of 100

(b) 34% of 250 or 18% of 150

Solution:

34% of 250 or 18% of 150

34% of 250 = \(\frac{34}{100}\) × 250 = 85

18% of 150 = \(\frac{18}{100}\) × 150 = 27

85 > 27

Thus, 34% of 250 > 18% of 150

Word Problems

Example 1.

Find 20% of 50.

Solution:

20% of 50 = \(\frac{20}{100}\) × 50

= \(\frac{20 \times 50}{100}\)

= \(\frac{1000}{100}\)

= 10

Example 2.

Find 33\(\frac{1}{3}\)% of 1,800 kg.

Solution:

33\(\frac{1}{3}\)% of 1,800 = \(\frac{100}{3}\)% of 1,800

= \(\frac{100}{3 \times 100}\) × 1800

= \(\frac{1800}{3}\)

= 600