The DAV Books Solutions Class 5 Maths and DAV Class 5 Maths Chapter 12 Worksheet 4 Solutions of Percentage offer comprehensive answers to textbook questions.
DAV Class 5 Maths Ch 12 Worksheet 4 Solutions
Question 1.
Find the value of the following:
(a) 50% of 10
Solution:
50% of 10 = \(\frac{50}{100}\)% of 10
= \(\frac{50}{100}\) × 10
= 5
(b) 60% of 700
Solution:
60% of 700 = \(\frac{60}{100}\)% of 700
= \(\frac{60}{100}\) × 700
= 420
(c) 24% of 75
Solution:
24% of 75 = \(\frac{24}{100}\)% of 75
= \(\frac{24}{100}\) × 75
= 18
(d) 6\(\frac{1}{4}\)% of 800
Solution:
6\(\frac{1}{4}\)% of 800 = \(\frac{25}{4}\)% of 800
= \(\frac{25}{4 \times 100}\) × 800
= 50
(e) 16\(\frac{2}{3}\)% of 1200
Solution:
16\(\frac{2}{3}\)% of 1200 = \(\frac{50}{3}\)% of 1200
= \(\frac{50}{300}\) × 1200
= 200
(f) 33\(\frac{1}{3}\)% of 300
Solution:
33\(\frac{1}{3}\) % of 300 = \(\frac{100}{3}\)% of 300
= \(\frac{100}{3 \times 100}\) × 300
= 100
(g) 75% of 300
Solution:
75% of 300 = \(\frac{75}{100}\)% of 300
= \(\frac{75}{100}\) × 300
= 225
(h) 3\(\frac{3}{4}\)% of 80
Solution:
3\(\frac{3}{4}\)% of 80 = \(\frac{15}{4}\)% of 80
= \(\frac{15}{4 \times 100}\) × 80
= 3
Question 2.
Find the value of the following:
(a) 3% of ₹ 600
Solution:
3% of ₹ 600 = \(\frac{3}{100}\) of ₹ 600
= \(\frac{3}{100}\) × 600
= ₹ 18
(b) 1% of 100 kg
Solution:
1% of 100 kg = \(\frac{1}{100}\) of 100 kg
= \(\frac{1}{100}\) × 100
= 1 kg
(c) 20% of 5 kilometres
Solution:
20% of 5 kilometres = \(\frac{20}{100}\) of 5 km
= \(\frac{20}{100}\) × 5
= 1 km
(d) 90% of 500 marks
Solution:
90% of 500 marks = \(\frac{90}{100}\) of 500 marks
= \(\frac{90}{100}\) × 500
= 450 marks
(e) 150% of 20 litres
Solution:
150% of 20 litres = \(\frac{150}{100}\) of 20 l
= \(\frac{150}{100}\) × 20
= 30 l
(f) 8% of 200 grams
Solution:
8% of 200 grams = \(\frac{8}{100}\) of 200 gm
= \(\frac{8}{100}\) × 200
= 16 gm
(g) 12\(\frac{1}{2}\)% of 1 kilogram
Solution:
12\(\frac{1}{2}\)% of 1 kilogram = \(\frac{25}{2}\)% of 1 kg
= \(\frac{25}{200}\) × 1
= \(\frac{1 \times 1}{8}\)
= 0.125 kg or 125 gm
(h) \(\frac{3}{4}\)% of ₹ 8,800
Solution:
\(\frac{3}{4}\)% of ₹ 8,800 = \(\frac{3}{400}\) of ₹ 8,800
= \(\frac{3}{400}\) × 8800
= ₹ 66
Question 3.
Find which is more of the two:
(a) 15% of 200 or 20% of 100
Solution:
15% of 200 or 20% of 100
15% of 200 = \(\frac{15}{100}\) × 200 = 30
20% of 100 = \(\frac{20}{100}\) × 100 = 20
30 > 20
Thus, 15% of 200 > 20% of 100
(b) 34% of 250 or 18% of 150
Solution:
34% of 250 or 18% of 150
34% of 250 = \(\frac{34}{100}\) × 250 = 85
18% of 150 = \(\frac{18}{100}\) × 150 = 27
85 > 27
Thus, 34% of 250 > 18% of 150
Word Problems
Example 1.
Find 20% of 50.
Solution:
20% of 50 = \(\frac{20}{100}\) × 50
= \(\frac{20 \times 50}{100}\)
= \(\frac{1000}{100}\)
= 10
Example 2.
Find 33\(\frac{1}{3}\)% of 1,800 kg.
Solution:
33\(\frac{1}{3}\)% of 1,800 = \(\frac{100}{3}\)% of 1,800
= \(\frac{100}{3 \times 100}\) × 1800
= \(\frac{1800}{3}\)
= 600