The DAV Books Solutions Class 5 Maths and **DAV Class 5 Maths Chapter 11 Worksheet 2** Solutions of Profit and Loss offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 11 Worksheet 2 Solutions

Question 1.

Solve the following questions.

(a) A vegetable seller bought potatoes for ₹ 200. He spent ₹ 20 on transport and then sold them for ₹ 290. Find the profit or loss.

Solution:

C.P. of potato = ₹ 200

Transport Charges = ₹ 20

Actual cost price of the potatoes = ₹ 220

Selling price of the potatoes = ₹ 290

Since the selling price is more than C.P. vegetable seller makes a profit.

Profit = S.P. – C.P.

= ₹ 290 – ₹ 220

= ₹ 70

Thus vegetable seller makes a profit of ₹ 70

(b) Mr Gupta bought a car for ₹ 40,000. He spent ₹ 8,000 for painting it. If he sold the car for ₹ 53,000 find the gain or loss.

Solution:

C.P. of car = ₹ 40,000

Money spent on painting = ₹ 8,000

Actual C.P. of car = ₹ 48,000

S.P. of the car = ₹ 53,000

Since, S.P. > C.P., he makes a profit

Gain = S.P. – C.P.

= ₹ 53,000 – ₹ 48,000

= ₹ 5,000

Thus, Mr Gupta gains a profit ₹ 5,000.

(c) Ramlal purchased a plot for ₹ 1,35,000. He constructed a boundary wall around it which cost him ₹ 25,500. If he sold the plot for ₹ 1,90,500. Find the gain or loss.

Solution:

C.P. of plot = ₹ 1,35,000

Cost of boundary wall = ₹ 25,500

Actual cost of plot = ₹ 1,60,500

S. P. of plot = ₹ 1,90,500

Since, S.P. > C.P., Ramlal make a profit

Gain = S.P. – C.P.

= ₹ 1,90,500 – ₹ 1,60,500

= ₹ 30,000

So, Ramlal gained a profit of ₹ 30,000.

(d) A merchant bought a sofa set for ₹ 18,000. He sold it to his friend for ₹ 15,750. If the merchant had spent ₹ 2,500 on transport, find his gain or loss.

Solution:

C.P. of sofa set = ₹ 18,000

S.P. of sofa set = ₹ 15,750

Transport charges = ₹ 2,500

Actual C.P. of sofa set = ₹ 18,000 + ₹ 2,500 = ₹ 20,500

Since, S.P. < C.P., so, the merchant has a loss

Loss = C.P. – S.P.

= ₹ 20,500 – ₹ 15,750

= ₹ 4,750

So, the merchant had a loss of ₹ 4,750.

(e) A property dealer purchased a house for ₹ 1,50,000. He spent ₹ 15,000 on repairing the house. After six months, he sold the house for ₹ 2,15,000. Find the gain or loss of the property dealer.

Solution:

C.P. of property = ₹ 1,50,000

Amount spent on repairing = ₹ 15,000

Actual cost of property = ₹ 1,65,000

S.P. of property = ₹ 2,15,000

Since, S.P. > C.P., property dealer makes a profit

Gain = S.P. – C.P.

= ₹ 2,15,000 – ₹ 1,65,000

= ₹ 50,000

So, the property dealer gained a profit of ₹ 50,000.

Word Problem

Example.

Rohit buys a chair for ₹ 400. He pays ₹ 50 as transport charges and sells it to Mr. Varan for ₹ 520. Find the profit or loss.

Solution:

C.P. of chair = ₹ 400

Transport charges = ₹ 50

Actual cost price of the chair = ₹ 450

Selling price of the chair = ₹ 520

Since S.P. is more than C.P. Rohit makes a profit.

Profit = S.P. – C.P.

= ₹ 520 – ₹ 450

= ₹ 70

Thus Rohit made a profit of ₹ 70.