# Maharashtra Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 27

## Maharashtra State Board Class 7 Maths Solutions Chapter 6 Indices Practice Set 27

Question 1.
Simplify:
i. 74 × 72
ii. (-11)5 × (-11)2
iii. $$\left(\frac{6}{7}\right)^{3} \times\left(\frac{6}{7}\right)^{5}$$
iv. $$\left(-\frac{3}{2}\right)^{5} \times\left(-\frac{3}{2}\right)^{3}$$
v. a16 × a7
vi. $$\left(\frac{\mathrm{P}}{5}\right)^{3} \times\left(\frac{\mathrm{P}}{5}\right)^{7}$$
Solution:
i. 74 × 72
= 74+2
= 76

ii. (-11)5 × (-11)2
= (-11)5+2
= (-11)7

iii. $$\left(\frac{6}{7}\right)^{3} \times\left(\frac{6}{7}\right)^{5}$$
$$=\left(\frac{6}{7}\right)^{3+5}=\left(\frac{6}{7}\right)^{8}$$

iv. $$\left(-\frac{3}{2}\right)^{5} \times\left(-\frac{3}{2}\right)^{3}$$
$$=\left(-\frac{3}{2}\right)^{5+3}=\left(-\frac{3}{2}\right)^{8}$$

v. a16 × a7
= a16+7
= a23

vi. $$\left(\frac{\mathrm{P}}{5}\right)^{3} \times\left(\frac{\mathrm{P}}{5}\right)^{7}$$
$$=\left(\frac{\mathrm{P}}{5}\right)^{3+7}=\left(\frac{\mathrm{P}}{5}\right)^{10}$$