The DAV Class 8 Maths Book Solutions Pdf and **DAV Class 8 Maths Chapter 5 Brain Teasers** Solutions of Compound Interest offer comprehensive answers to textbook questions.

## DAV Class 8 Maths Ch 5 Brain Teasers Solutions

Question 1A.

Tick (✓) the correct option.

(i) If the selling price of an article is twice the cost price, the profit percent is _______

(a) 50%

(b) 100%

(c) 150%

(d) 200%

Solution:

(b) 100%

Let the C.P. of the article be x.

Then, S.P. = 2x.

∴ Profit = S.P. – C.P.

= 2x – x = x

Profit % = \(\frac{\text { Profit }}{\text { C.P. }}\) × 100

= \(\frac{x}{x}\) × 100

= 100%

(ii) A jeans is marked for ₹ 2,590, but is sold for ₹ 2,331, then discount % is _______

(a) 20%

(b) 15%

(c) 10%

(d) 5%

Solution:

(c) 10%

M.P. = ₹ 2,590

S.P. = ₹ 2331

Discount = M.P. – S.P.

= ₹ 2,590 – ₹ 2331 = ₹ 259

Discount % = \(\frac{\text { Discount }}{\text { M.P. }}\) × 100

= \(\frac{259}{2590}\) × 100 = 10 %

(iii) If selling price of five pens is equal to the cost price of four pens, then the gain or loss% is _______

(a) 20% gain

(b) 20% loss

(c) 25% loss

(d) 25% gain

Solution:

(b) 20% loss

Let the C.P. of 1 pen be x.

So the C.P. of 4 pens = 4x

and C.P. of 5 pens = 5x.

S.P. of 5 pens = 4x

Loss = C.P. – S.P.

= 5x – 4x = x

∴ Loss% = \(\frac{\text { Loss }}{\mathrm{CP}}\) × 100

= \(\frac{x}{5 x}\) × 100 = 20%.

(iv) Selling price of a saree is ₹ 864 including 8% VAT. The original price of the saree is

(a) ₹ 842

(b) ₹ 800

(c) ₹ 801.50

(d) ₹ 820

Solution:

(b) ₹ 800

Let the original price of the saree be x.

So, x + 8% of x = 864

⇒ x + \(\frac{8}{100}\) × x = 864

⇒ \(\frac{100 x+8 x}{100}\) = 864

⇒ \(\frac{108 x}{100}\) = 864

∴ x = \(\frac{864 \times 100}{108}\) = ₹ 800.

Thus, the original price of the saree = ₹ 800.

(v) Discount is always calculated on _______

(a) cost price

(b) marked price

(c) selling price

(d) VAT

Solution:

(b) marked price

Question 1B.

Answer the following questions.

(i) After giving a discount of 8% on the marked price, an article was sold for ₹ 414. Find the marked price of the article.

(ii) A fan is sold for ₹ 650. The gain is one-fourth of the cost price of the fan. Find the gain per cent.

(iii) A shopkeeper buys pencils at 10 for ₹ 10 and sells them at 8 for ₹ 10. Find the profit per cent.

(iv) Find the rate of VAT if an article marked at ₹ 5,000 is sold for ₹ 5,200?

(v) A person pays ₹ 2,800 for a cooler marked at ₹ 3,500. Find the discount per cent offered.

Solution:

(i) Discount = 8%

S.P. = ₹ 144

M.P. = ?

∵ M.P. = \(\frac{\text { S.P. } \times 100}{100-\text { Discount } \%}\)

= \(\frac{414 \times 100}{100-8}\)

= \(\frac{414 \times 100}{92}\)

= ₹ 450.

(ii) S.P. = ₹ 650

Let C.P. of the fan be x.

So, gain = \(\frac{1}{4}\) x

Now, gain = S.P. – C.P.

⇒ \(\frac{x}{4}\) = 650 – x

⇒ x + \(\frac{x}{4}\) = 650

⇒ \(\frac{5 x}{4}\) = 650

⇒ x = \(\frac{650 \times 4}{5}\) = ₹ 520

Thus, gain = \(\frac{1}{4}\) × 520 = ₹ 130.

Gain % = \(\frac{\text { Gain } \times 100}{\text { C.P. }}\)

= \(\frac{130 \times 100}{520}\) = 25%

(iii) C.P. of 10 pencils = ₹ 10

= C.P. of 8 pencils = ₹ 8

And, SP. of 8 pencils = ₹ 10.

Gain = S.P. – C.P.

= 10 – 8 = ₹ 2.

Gain % = \(\frac{\text { Gain }}{\text { C.P. }}\) × 100

= \(\frac{2}{8}\) × 100 = 25%

(iv) MP. = ₹ 5000

S.P. = ₹ 5200

VAT = S.P. – MP.

= ₹ 5000 – ₹ 5200 = ₹ 200

Rate of VAT = \(\frac{200}{5000}\) × 100 = 4%.

(v) M.P. = ₹ 3500

S.P. =₹ 2800

Discount = M.P. – S.P.

= 3500 – 2800 = ₹ 700

Discount % = \(\frac{\text { Discount }}{\text { M.P. }}\) × 100

= \(\frac{700}{3500}\) × 100 = 20%

Question 2.

Rajan purchased a purse at 25% discount on its marked price but sold it at the marked price. Find the gain per cent of Rajan on his transaction.

Solution:

Let the marked price be ₹ x.

Discount = \(\frac{25}{100}\) × x

= ₹ \(\frac{x}{4}\)

C.P. of the purse = x – \(\frac{x}{4}\)

= ₹ \(\frac{3 x}{4}\)

S.P. = M.P. = ₹ x

Gain = S.P. – C.P.

= x – \(\frac{3 x}{4}\)

= ₹ \(\frac{x}{4}\)

Gain % = \(\frac{\text { Gain }}{\text { C.P. }}\) × 100

= \(\frac{\frac{x}{4}}{\frac{3 x}{4}}\) × 100

= \(\frac{100}{3}\)

= 33\(\frac{1}{3}\)

Hence, the gain on the transaction = 33\(\frac{1}{3}\) %.

Question 3.

Jasleen marks her goods at 30% above the cost price and allows a discount of 25% on the marked price. Find her gain or loss per cent.

Solution:

Let the C.P. be ₹ x

∴ Marked price = x + \(\frac{30}{100}\)

= ₹ \(\frac{13}{10}\) x

Discount = M.P. × \(\frac{25}{100}\)

= \(\frac{13 x}{10} \times \frac{25}{100}\)

= ₹ \(\frac{13 x}{40}\)

∴ S.P. = M.P. – Discount

= \(₹ \frac{13 x}{10}-₹ \frac{13 x}{40}\)

= ₹ \(\frac{39 x}{40}\)

Here C.P. > S.P.

Loss = C.P. – S.P.

= ₹ x – ₹ \(\frac{39 x}{40}\)

= ₹ \(\frac{x}{40}\)

Loss % = \(\frac{\text { Loss }}{\text { C.P. }}\) × 100

= \(\frac{\frac{x}{40}}{x}\) × 100

= \(\frac{5}{2}\)%

= \(2 \frac{1}{2}\)%

Hence, the loss % = 2 \(\frac{1}{2}\)%.

Question 4.

How much per cent above the cost price should a shopkeeper mark his goods so that after allowing a discount of 20% on the marked price, he gains 12%?

Solution:

Let the M.P. be ₹ x.

Discount = \(\frac{20}{100}\) × x

= ₹ \(\frac{x}{5}\)

∴ Selling price = M.P. – Discount

= x – \(\frac{x}{5}\)

= ₹ \(\frac{4 x}{5}\)

Now S.P. = C.P. (1 + \(\frac{\text { Gain }}{100}\))

\(\frac{4 x}{5}=\text { C.P. }\left(1+\frac{12}{100}\right)\)

⇒ \(\frac{4 x}{5}=\text { C.P. } \times \frac{28}{25}\)

⇒ C.P. = \(\frac{4 x}{5} \times \frac{25}{28}\)

= ₹ \(\frac{5 x}{7}\)

Difference between M.P. and C.P. = x – \(\frac{5 x}{7}\)

= ₹ \(\frac{2 x}{7}\)

∴ Percentage of difference = \(\frac{\frac{2 x}{7}}{\frac{5 x}{7}}\) × 100 = 40%

Hence, the shopkeeper should mark his good above 40% of his C.P.

Question 5.

Rohit marks his goods at 40% above the cost price but allows a discount of 5% for cash payment to his customers. What actual profit does he make, if he receives ₹ 1064 after allowing the discount?

Solution:

Let C.P. be ₹ x.

∴ M.P. = ₹ x + \(\frac{40 x}{100}\)

= ₹ \(\frac{7 x}{5}\)

Discount = \(\frac{7 x}{5} \times \frac{5}{100}\)

= ₹ \(\frac{7 x}{100}\)

∴ S.P. = M.P. – Discount

= ₹ \(\frac{7 x}{5}-\frac{7 x}{100}\)

= ₹ \(\frac{7 x}{100}\)

Now \(\frac{133}{100}\) x = 1064

x = 1064 × \(\frac{100}{133}\)

⇒ x = 8 × 100 = 80

∴ C.P. = ₹ 800

and S.P. = 1064

Profit = S.P. – C.P.

= ₹ 1064 – ₹ 800 = ₹ 264

Hence, the actual profit is ₹ 264.

Question 6.

Mr. Kumar went to shopping with his family to a Mall. Mrs. Kumar bought a saree for ₹ 12500, cloths for the kids for ₹ 9280 and a mobile for Mr. Kumar for ₹ 32638. If the VAT charged on their purchases is 7.5% , then what is the total amount that Mr. Kumar has paid?

Solution:

Cost price for a saree = ₹ 12,500

VAT = \(\frac{7.5}{100}\) × 12500

= ₹ 937.50

∴ Total cost including VAT = ₹ 12500 + ₹ 937.50 = ₹ 13437.50

Cost price for cloths for kids = ₹ 9,280

VAT = \(\frac{7.5}{100}\) × 9280

= ₹ 696

∴ Total cost including VAT = ₹ 9280 + ₹ 696 =₹ 9976

Cost of mobile for Mr. Kumar = ₹ 32638

VAT = \(\frac{7.5}{100}\) × 32638

= ₹ 2447.85 100

Total cost including VAT = ₹ 32638 + ₹ 2447.85 = ₹ 35085.85

∴ Total cost of all items including VAT paid by Mr. Kumar = ₹ 13437.50 + ₹ 9976 + ₹ 35085.85 = ₹ 58499.35.

### DAV Class 8 Maths Chapter 5 HOTS

Question 1.

The marked price of an article is ₹ 3,500 and rate of VAT is 8%. A shopkeeper allows a discount of 20% and still makes a profit of 10%. Find the original cost price of the article and the selling price including VAT.

Solution:

M.P. = ₹ 3500

VAT = 8%

Discount = 20%

Discount = 20 %

Let C.P. be x so that

S.P. = C.P. (1 + \(\frac{\text { gain\% }}{100}\))

= x (1 + \(\frac{10}{100}\))

= \(\frac{11 x}{10}\) ………………….(1)

S.P. = M.P. (1 – \(\frac{\text { Discount% }}{100}\))

= 3500 (1 – \(\frac{20}{100}\))

= 3500 × \(\left(\frac{100-20}{100}\right)\)

= 3500 × \(\frac{80}{100}\)

= ₹ 2800

∴ S.P. including VAT = 2800 + \(\frac{8}{100}\) × 2800

= 2800 + 224

= ₹ 3024 ………………..(2)

From (1) and (2)

Now, \(\frac{11 x}{10}\) = 3024

⇒ x = \(\frac{3024 \times 10}{11}\) ~ 2749.10

Additional Questions:

Question 1.

An article is sold for ₹ 96 at a profit equal to its C.P. in rupees. Find the cost price of the article.

Solution:

Let C.P. of the article be ₹ x.

∴ ₹ Profit = x × \(\frac{x}{100}\)

= ₹ \(\frac{x^2}{100}\)

∴ x + \(\frac{x^2}{100}\) = 96

⇒ \(\frac{x^2+100 x}{100}\) = 96

⇒ x<sup>2</sup> + 100x = 9600

⇒ x<sup>2</sup> + 100x – 9600 = 0

⇒ x<sup></sup> + 160x – 60x – 9600 = 0

⇒ x (x + 160) – 60 (x + 160) = 0

⇒ (x + 160) (x – 60) = 0

⇒ x = 60 and x = – 160 (neglected as cost can never be negative)

Hence, the cost price of the article is ₹ 60.

Question 2.

An article is sold for ₹ 24 at a loss percent equal to its C.P. in rupees. Find the C.P. of the article.

Solution:

Let the C.P. of the article be ₹ x.

∴ Loss = x × \(\frac{x}{100}\)

= ₹ \(\frac{x^2}{100}\)

S.P. = C.P. – Loss

= x – \(\frac{x^2}{100}\)

Then, x – \(\frac{x^2}{100}\) = 24

⇒ \(\frac{100 x-x^2}{100}\) = 24

⇒ 100x – x^{2} = 2400

⇒ x^{2} – 100x + 2400 = 0

⇒ x^{2} – 60x – 40x + 2400 = 0

⇒ x (x – 60) – 40 (x – 60) = 0

⇒ (x – 60) (x – 40) = 0

⇒ x = 60 and x = 40

Hence, the cost price of the article is ₹ 60 or ₹ 40.

Question 3.

An article is sold for ₹ 3120 at a loss of 4%. What will be the gain or loss per cent, if it is sold for ₹ 3640?

Solution:

S.P. = ₹ 3120

Loss = 4%

∴ S.P. = C.P. (1 – \(\frac{\text { Loss }}{100}\))

3120 = C.P. (1 – \(\frac{4}{100}\))

3120 = C.P. \(\frac{24}{25}\)

C.P. = \(\frac{3120 \times 25}{24}\)

= ₹ 3250

But new S.P. = ₹ 3640

Here S.P. > C.P.

∴ Gain = S.P. – C.P.

= ₹ 3640 – ₹ 3250 = ₹ 390

∴ Gain % = \(\frac{\text { Gain }}{\text { C.P. }}\) × 100

= \(\frac{390}{3250}\) × 100 = 12%

Hence, the gain = 12%.

Question 4.

Find a single discount equivalent to two successive discounts of 25% and 4%.

Solution:

Let M.P. be ₹ 100.

∴ S.P. = (100 – 25)% of (100 – 4)% of 100

= \(\frac{75}{100} \times \frac{96}{100}\) × 100 = ₹ 72

∴ Single discount is (100 – 72)% = 28%

Hence, the required single discount is 28%.

Question 5.

A shopkeeper fixed the marked price of an item 35% above its cost price. Find the discount percent so as to gain 8%.

Solution:

Let C.P. be ₹ x.

∴ M.P. = x + \(\frac{35}{100}\) x = ₹ \(\frac{27 x}{20}\)

S.P.= C.P. + (1 + \(\frac{\text { Gain }}{100}\))

= x (1 + \(\frac{8}{100}\))

= ₹ \(\frac{27}{25}\) x

Discount = M.P. – S.P.

= \(\frac{27 x}{20}-\frac{27}{25} x\)

= ₹ \(\frac{27 x}{100}\) x%

Discount % = \(\frac{\text { Discount }}{\text { M.P. }}\) × 100

= \(\frac{\frac{27 x}{100}}{\frac{27 x}{20}}\) × 100 = 20 %

Hence, the required discount is 20%.

Question 6.

When a discount of 15% is allowed on the marked price of an article, it is sold for ? 2975.

(i) Calculate the marked price.

(ii) Given that the marked price is 40% above the cost price, find the cost price.

(iii) Find the gain per cent obtained on selling the article.

Solution:

(i) Discount = 15%

S.P. = ₹ 2975

Let M.P. be ₹ x.

∴ Discount = \(\frac{15}{100}\) × x

= ₹ \(\frac{3 x}{20}\)

S.P. = M.P. – Discount

⇒ 2975 = x – \(\frac{3 x}{20}\)

⇒ 2975 = \(\frac{17 x}{20}\)

⇒ x = \(\frac{2975 \times 20}{17}\)

= ₹ 3500

Hence, M.P. = ₹ 3500

(ii) Let C.P. be ₹ x

∴ M.P. = x + \(\frac{40}{100}\) x

⇒ 3500 = \(\frac{140}{100}\) x

∴ x = \(\frac{3500 \times 100}{140}\)

= ₹ 2500

Hence, the cost price = ₹ 2500.

(iii) C.P. = ₹ 2500

and S.P. = ₹ 2975

∴ Gain = ₹ 2975 – ₹ 2500 = ₹ 475

Gain % = \(\frac{\text { Gain }}{\text { C.P. }}\) × 100

= \(\frac{475}{2500}\) × 100 = 19%

Hence, the required gain per cent = 19%.

Question 7.

A dealer purchased a washing machine for ₹ 15320. He allows a discount of 12% on its marked price and gains 10% on it. Find the marked price of the machine.

Solution:

Let M.P. be ₹ x.

∴ Discount = \(\frac{12}{100}\) × x

= ₹ \(\frac{3 x}{25}\)

S.P. = M.P. – Discount

= x – \(\frac{3 x}{25}\)

= ₹ \(\frac{22 x}{25}\)

C.P. = ₹ 15320

Gain = 10% of ₹ 15320

= \(\frac{10}{100}\) × 15320 = ₹ 1532

∴ S.P. = ₹ 15320 + ₹ 1532 = ₹ 16852

∴ \(\frac{22 x}{25}\) = 16852

⇒ x = \(\frac{16852 \times 25}{22}\) = ₹ 19150

Hence, the required marked price is ₹ 19150.

Question 8.

A trader buys goods at 19% off the list price. He wants to get a profit of 20% after allowing a discount of 10%. At what price above the list price should he mark the goods?

Solution:

Let list price be 100 and M.P. be x% above the list price.

∴ M.P. = ₹ (100 + x)

∴ C.P. = 100 – 19 = ₹ 81

Profit = 20%

∴ S.P. = C.P. (1 + \(\frac{\text { Profit }}{100}\))

= 81 (1 + \(\frac{20}{100}\))

= 81 × \(\frac{6}{5}\)

= ₹ \(\frac{486}{5}\)

Now discount = 10%

∴ S.P. = (100 + x) (1 – \(\frac{10}{100}\))

= \(\frac{9}{10}\) (100 + x)

∴ \(\frac{9}{10}\) (100 + x) = \(\frac{486}{5}\)

⇒ 100 + x = \(\frac{486}{5} \times \frac{10}{9}\)

⇒ 100 + x = 108

⇒ 100 + x = 108

∴ x = 108 – 100 = 8

Hence, the trader should mark his goods 8% above the list price.

Question 9.

A manufacturer allows 4% discount on the marked price of each item. What price must he mark on a dinning table which costs ₹ 400 to assemble so as to make a profit of 20%?

Solution:

Let M.P. of the dinning table be ₹ x.

∴ Discount = \(\frac{4}{100}\) × x

= ₹ \(\frac{x}{25}\)

∴ S.P. = M.P. – Discount

= x – \(\frac{x}{25}\)

= ₹ \(\frac{24}{25}\) x

Now C.P. = ₹ 400

and Profit = 20%

∴ S.P. = 400 (1 + \(\frac{20}{100}\))

= 400 × \(\frac{120}{100}\)

= ₹ 480

∴ \(\frac{24}{25}\) x = 480

∴ x = \(\frac{480 \times 25}{24}\) = ₹ 500

Hence, the M.P. of the dinning set = ₹ 500.

Question 10.

A man spends 10% of the cost price as overheads and marks his goods 20% above the total cost price. He allows 10% discount. What is his profit on the article which he sold for ₹ 594?

Solution:

Let C.P. be ₹ x.

Hence, the required profit = 18.8%.

Question 11.

How much a shopkeeper must mark his goods so that after allowing a discount of 25% on the marked price, he gains 20%, if the cost price of the goods is ₹ 20,000?

Solution:

Let the M.P. be ₹ x.

Discount = 25% on M.P.

= \(\frac{25}{100}\) × x

= ₹ \(\frac{x}{4}\)

∴ S.P. = M.P. – Discount

= x – \(\frac{x}{4}\)

= ₹ \(\frac{3 x}{4}\)

C.P. = ₹ 20,000

and Gain = 20%

∴ S.P. = C.P. (1 + \(\frac{\text { Gain }}{100}\))

\(\frac{3 x}{4}\) = 20000 (1 + \(\frac{20}{100}\))

\(\frac{3 x}{4}\) = 20000 × \(\frac{6}{5}\)

x = 20000 × \(\frac{6}{5} \times \frac{4}{3}\)

= ₹ 32000

Hence, the required marked price is ₹ 32000.

Question 12.

If M.P. = ₹ 650 and discount = 10%, then S.P. is:

(a) ₹ 640

(b) ₹ 550

(c) ₹ 560

(d) ₹ 585

Solution:

M.P. = ₹ 650

Discount = \(\frac{10}{100}\) × 650 = ₹ 65

∴ S.P. = M.P. – Discount

= ₹ 650 – ₹ 65 = ₹ 585

Hence, (d) is correct.

Question 13.

Kamal bought a wrist watch for ₹ 2200 and sold it for ₹ 1980. His loss % is:

(a) 10%

(b) 20%

(c) 11%

(d) 15%.

Solution:

C.P. = ₹ 2200

S.P. = ₹ 1980

Loss = C.P. – S.P. = ₹ 2200 – ₹ 1980

= ₹ 220

∴ Loss % = \(\frac{220 \times 100}{2200}\) = 10%

Hence, (a) is correct.

Question 14.

Ankit sold two jeans for ₹ 990 each. On one he gains 10% and on the other he loses 10%. Find his gain or loss per cent in the whole transaction.

Solution:

Let C.P. of first jeans be ₹ x.

Gain = \(\frac{10}{100}\) × x

= ₹ \(\frac{x}{10}\)

∴ S.P. = ₹ (x + \(\frac{x}{10}\))

= ₹ \(\frac{11 x}{10}\)

∴ \(\frac{11 x}{10}\) = 990

⇒ x = \(\frac{990 \times 10}{11}\)

= ₹ 900

Let C.P. of the other jeans be ₹ y.

Loss = \(\frac{10}{100}\) × y

= ₹ \(\frac{y}{10}\)

∴ S.P. = ₹ (y – \(\frac{y}{10}\))

= ₹ \(\frac{9 y}{10}\)

∴ \(\frac{9 y}{10}\) = 990

⇒ y = \(\frac{990 \times 100}{9}\)

= ₹ 1100

∴ Total C.P. of the two jeans = ₹ x + ₹ y

= ₹ 900 + ₹ 1100

= ₹ 2000

and Total S.P. = 2 × 990

= ₹ 1980

∴ Loss = C.P – S.P

= ₹ 2000 – ₹ 1980

= ₹ 20

∴ Loss % = \(\frac{20 \times 100}{2000}\) = 1%

Hence the loss % = 1 %.

Question 15.

The marked price of a double bed is ₹ 9575. A shopkeeper allows a discount of 12% on its marked price and still gains 10%. Find the cost price of the double bed.

Solution:

M.P. = ₹ 9575

Discount = 12% of M.P.

= \(\frac{12}{100}\) × 9575

= ₹ 1149

∴ S.P. = M.P. – Discount

= ₹ 9575 – ₹ 1149 = ₹ 8426

Gain = 10%

∴ S.P. = C.P. (1 + \(\frac{\text { Gain }}{100}\))

8426 = C.P. (1 + \(\frac{10}{100}\))

8426 = C.P.× \(\frac{11}{10}\)

C.P. = \(\frac{8426 \times 10}{11}\)

= ₹ 7660

Hence, the cost price of the double bed is ₹ 7660.

Question 16.

Meera bought an A.C. for ₹ 22000 including a VAT tax of 10%. Find the price of the A.C. before VAT was added.

Solution:

Let the price of the A.C. before the VAT added be ₹ x.

∴ VAT = \(\frac{10}{100}\) × x

= ₹ \(\frac{x}{10}\)

∴ Price of the A.C.including VAT = ₹ x + ₹ \(\frac{x}{10}\)

= ₹ \(\frac{11 x}{10}\)

∴ \(\frac{11 x}{10}\) = 22,000

= 22,000

⇒ x = 22,000 × \(\frac{10}{11}\)

= 2000 × 10 = ₹ 20,000

Hence, the required cost is ₹ 20,000.

Question 17.

Rohan bought some cricket balls at the rate of ₹ 250 for 4 balls and sold them at the rate of ₹ 340 for 5 balls. Find his gain or loss per cent.

Solution:

C.P. of 4 balls = ₹ 250

and S.P. of 5 balls = ₹ 340

∴ S.P. of 4 balls = ₹ 340 × \(\frac{4}{5}\)

= ₹ 272

∴ Gain = ₹ 272 – ₹ 250 = ₹ 22

∴ Gain % = \(\frac{22}{250}\) × 100 = 8.8%

Hence, the required gain = 8.8%.

Multiple Choice Questions:

Question 1.

If S.P. = ₹ 640 and profit = 28%, then C.P. is _________

(a) ₹ 450

(b) ₹ 500

(c) ₹ 550

(d) ₹ 575

Solution:

(b) ₹ 500

Question 2.

List price = ₹ 16925, Sales Tax = 6%, then the price including S.T. is _________

(a) ₹ 17940.50

(b) ₹ 17940

(c) ₹ 17950

(d) ₹ 17945

Solution:

(a) ₹ 17940.50

Question 3.

M.P. = ₹ 1375, S.T. = 4%, then the total cost is _________

(a) ₹ 1425

(b) ₹ 1430

(c) ₹ 1435

(d) ₹ 1420

Solution:

(b) ₹ 1430

Question 4.

C.P. = ₹ 5500, Rebate = 5%, S.T. = 8%, then the amount to be paid is _________

(a) ₹ 5640

(b) ₹ 5642

(c) ₹ 5645

(d) ₹ 5643

Solution:

(d) ₹ 5643

Question 5.

S.P. = ₹ 17985, S.T. = 9%, then the list price is _________

(a) ₹ 16500

(b) ₹ 16575

(c) ₹ 16600

(d) ₹ 16590

Solution:

(a) ₹ 16500