DAV Class 7 Maths Chapter 12 Worksheet 2 Solutions

The DAV Maths Class 7 Solutions and DAV Class 7 Maths Chapter 12 Worksheet 2 Solutions of Data Handling offer comprehensive answers to textbook questions.

DAV Class 7 Maths Ch 12 WS 2 Solutions

Question 1.
Find the median of the following data.
11, 39, 43, 45, 25, 46, 43, 42, 37.
Answer:
Let us arrange the given data in ascending order,
11, 25, 37, 39, 42, 43, 43, 45, 46
Here number of observations = 9 (odd)
∴ Median = \(\frac{9+1}{2}\) = 5th observation = 42
Hence the median = 42.

Question 2.
Find the median of.
(i) 85, 42, 56, 69, 51, 81, 72, 92, 67
(ii) 15, 47, 48, 81, 17, 27, 9, 3, 10, 75
Answer:
(i) Let us arrange the given data in ascending order,
42, 51, 56, 67, 69, 72, 81, 85, 92
Number of observations = 9 (odd)
Median = \(\frac{9+1}{2}\) = 5th observation = 69
Hence the median = 69.

(ii) Let us arrange the given observations in ascending order,
3, 9, 10,15,17, 27, 47, 48, 75, 81
Number of observations = 10 (even)
∴ Median = \(\frac{\frac{10^{\text {th }}}{2} \text { observation }+\left(\frac{10}{2}+1\right)^{\text {th }} \text { observation }}{2}\)
= \(\frac{5^{\text {th }} \text { observation }+6^{\text {th }} \text { observation }}{2}=\frac{17+27}{2}=\frac{44}{2}\) = 22
Hence the median = 22.

DAV Class 7 Maths Chapter 12 Worksheet 2 Solutions

Question 3.
The following number of goals were scored by a team in a series of 10 matches:
2, 3, 5, 4, 0, 1, 3, 3, 3, 4
Find the median of these scores.
Answer:
Arranging the given scores in increasing order
0,1, 2, 3, 3, 3, 3, 4, 4, 5
Number of scores = 10 (even)
DAV Class 7 Maths Chapter 12 Worksheet 2 Solutions 1
Hence the median = 3.

Question 4.
The weight (in kg) of 11 students of class -VII (in April 2015) is 42, 52, 48, 52, 55, 58, 53, 54, 46, 49, 57
Find the median of these weights. In July 2015, one student of weight 58 kg, left the school and a new student of weight 68 kg joined the class. Find new median.
Answer:
Arranging the given observations in increasing order,
42, 46, 48, 49, 52, 52, 53, 54, 55, 57, 58
The number of observations = 11 (odd)
Median = \(\frac{11+1}{2}=\frac{12}{2}\) = 6th observation = 52
Hence the median = 52

One student of weight 58 kg left the school and a new student of weight 68 kg joined the school.
∴ Arranging again the observations in ascending order
42, 46, 48, 49, 52, 52, 53, 54, 55, 57, 68
∴ Median will remain same as 58 kg is replaced by 68 kg at 11th place.
Hence the new median = 52.