The DAV Class 7 Maths Solution and DAV Class 7 Maths Chapter 10 Worksheet 3 Solutions of Construction of Triangles offer comprehensive answers to textbook questions.
DAV Class 7 Maths Ch 10 WS 3 Solutions
Question 1.
Construct a ∆ABC in which BC = 4 cm, ∠B = 50° and ∠C = 70°
Answer:
Steps of Construction:
- Draw BC = 4 cm.
- Draw ∠B = 50° and ∠C = 70° to cut each other at A.
- ∆ABC is the required triangle.
Question 2.
Draw a ∆ABC in which BC = 8 cm, ∠B = 50° and ∠A = 50°.
Answer:
Steps of Construction:
- Draw BC = 8 cm.
- Draw ∠B = 50° and ∠C = 80° to meet at A.
Question 3.
Draw a triangle ABC with AB = 4.5 cm, ∠ABC = 35°, ∠ACB = 65°.
Answer:
Steps of Construction:
- Draw AB = 4.5 cm. c
- Draw ∠B = 35°
- Draw ∠A = 80°
[∵ ∠A = 180° — (35° + 65°) = 80°] - They meet at C.
- ∆ABC is the required triangle. A
Question 4.
Construct a ∆PQR with PQ = 7.5 cm, ∠RPQ = 45° ∠RQP = 45°. Measure the third angle. What kind of a triangle is it?
Answer:
Steps of Construction:
- Draw PQ = 7.5 cm.
- Draw an angle of 45° at P and at Q.
- The two angle lines meet at R.
- ∆PRQ is the required triangle.
- ∠PRQ = 90°
- ∆PQR is an isosceles right angled triangle.
Question 5.
Construct a ∆PQR with ∠P = 70°, ∠Q = 120° and side PQ = 5.2 cm. Is the construction possible?
Answer:
Steps of Construction:
- Draw PQ = 5.2 cm
- Draw ∠Q = 120° and ∠P = 70°
- The two angle lines do not meet any point.
[∵ 120° + 70° > 180° ⇒ 190° > 180°] - Therefore, the construction of ∆PQR is not possible.
Question 6.
Construct a ∆ABC in which BC
Answer:
Steps of Construction:
- Draw BC = 6 cm.
- Draw ∠B = 40° and ∠C = 110°.
- The two angle sides meet at A.
- ∆ABC is the required triangle.