The DAV Class 6 Maths Solutions and **DAV Class 6 Maths Chapter 7 Worksheet 2 **Solutions of Linear Equations offer comprehensive answers to textbook questions.

## DAV Class 6 Maths Ch 7 WS 2 Solutions

Question 1.

Check whether the given variable can solve the equation. Write ‘Yes’ or ‘No’.

Equation | Value of the Variable | Yes/No |

(a) 10.y = 80 | y = 6 | |

(6) 6 + 5 = 9 | 6 = 4 | |

(c) p – 8 = 5 | p = -13 | |

(d) \(\frac{y}{3}\) = -1 | y = -3 | |

(e) 32 = 12 | z = 2 | |

(f) a – 4 = 5 | a = 1 | |

(g) a + 4 = 5 | a = -1 | |

(h) 2x + 1 = 7 | x = 3 | |

(i) 2x – 1 = -9 | x = 4 | |

(o) 3x = -15 | x = -5 |

Answer:

(a) 10y = 80, variable y = 6

Put y = 6

⇒ 10 × 6 = 80

⇒ 60 ≠ 80

y = 6 is not the required solution.

(b) 6 + 5 = 9, variable 6=4

Put 6 = 4

⇒ 4 + 5 = 9

⇒ 9 = 9

∴ 6 = 4 is the solution of the given equation.

(c) p – 8 = 5, variable p = -13

Put p = -13

⇒ -13 – 8 = 5

⇒ -21 ≠ 5

∴ p = -13 is not the solution of the given equation.

(d) \(\frac{y}{3}\) = -1, variable y = -3, put y = -3.

\(\frac{-3}{3}\) = -1

∴ y = -3 is the solution of the given equation.

(e) 3z = 12, variable z = 2

Put z = 2

⇒ 3 × 2 = 12

⇒ 6 ≠ 12

∴ 2 = 2 is not the required solution.

(f) a -4 = 5, variable a = 1

Put a = 1

⇒ 1 – 4= 5

⇒ -3 ≠ 5

∴ a = 1 is not the required solution.

(g) a + 4 = 5, variable a = -1

Put a = -1

⇒ -1 + 4 = 5

⇒ 3 ≠ 5

∴ a = -1 is not the required solution.

(h) 2x + 1 = 7, variable x = 3

Put x = 3,

2 × 3 + 1 = 7

⇒ 6 + 1 = 7

⇒ 7 = 7

∴x = 3 is the required solution.

(i) 2x – 1 = -9, variable x = 4

Put x = 4, 2 × 4 – 1 = -9

⇒ 8 – 1 = -9

⇒ 7 ≠-9

∴ x = 4 is not the required solution.

(j) 3x = -15, variable x = -5

Put x = -5

⇒ 3x – 5 = -15

⇒ -15 = -15

∴ x = —5 is the required solution.