The DAV Class 6 Maths Solutions and DAV Class 6 Maths Chapter 7 Worksheet 2 Solutions of Linear Equations offer comprehensive answers to textbook questions.
DAV Class 6 Maths Ch 7 WS 2 Solutions
Question 1.
Check whether the given variable can solve the equation. Write ‘Yes’ or ‘No’.
Equation | Value of the Variable | Yes/No |
(a) 10.y = 80 | y = 6 | |
(6) 6 + 5 = 9 | 6 = 4 | |
(c) p – 8 = 5 | p = -13 | |
(d) \(\frac{y}{3}\) = -1 | y = -3 | |
(e) 32 = 12 | z = 2 | |
(f) a – 4 = 5 | a = 1 | |
(g) a + 4 = 5 | a = -1 | |
(h) 2x + 1 = 7 | x = 3 | |
(i) 2x – 1 = -9 | x = 4 | |
(o) 3x = -15 | x = -5 |
Answer:
(a) 10y = 80, variable y = 6
Put y = 6
⇒ 10 × 6 = 80
⇒ 60 ≠ 80
y = 6 is not the required solution.
(b) 6 + 5 = 9, variable 6=4
Put 6 = 4
⇒ 4 + 5 = 9
⇒ 9 = 9
∴ 6 = 4 is the solution of the given equation.
(c) p – 8 = 5, variable p = -13
Put p = -13
⇒ -13 – 8 = 5
⇒ -21 ≠ 5
∴ p = -13 is not the solution of the given equation.
(d) \(\frac{y}{3}\) = -1, variable y = -3, put y = -3.
\(\frac{-3}{3}\) = -1
∴ y = -3 is the solution of the given equation.
(e) 3z = 12, variable z = 2
Put z = 2
⇒ 3 × 2 = 12
⇒ 6 ≠ 12
∴ 2 = 2 is not the required solution.
(f) a -4 = 5, variable a = 1
Put a = 1
⇒ 1 – 4= 5
⇒ -3 ≠ 5
∴ a = 1 is not the required solution.
(g) a + 4 = 5, variable a = -1
Put a = -1
⇒ -1 + 4 = 5
⇒ 3 ≠ 5
∴ a = -1 is not the required solution.
(h) 2x + 1 = 7, variable x = 3
Put x = 3,
2 × 3 + 1 = 7
⇒ 6 + 1 = 7
⇒ 7 = 7
∴x = 3 is the required solution.
(i) 2x – 1 = -9, variable x = 4
Put x = 4, 2 × 4 – 1 = -9
⇒ 8 – 1 = -9
⇒ 7 ≠-9
∴ x = 4 is not the required solution.
(j) 3x = -15, variable x = -5
Put x = -5
⇒ 3x – 5 = -15
⇒ -15 = -15
∴ x = —5 is the required solution.