The DAV Class 6 Maths Book Solutions and DAV Class 6 Maths Chapter 14 Worksheet 2 Solutions of Constructions offer comprehensive answers to textbook questions.
DAV Class 6 Maths Ch 14 WS 2 Solutions
Question 1.
Draw an angle of any measure and name it. Using compasses and ruler, draw another angle equal to ∠A.
Answer:
Step 1: Draw an ∠BAC.
Step 2: With centre A and suitable radius, draw an arc which meets AC and AB at D and E respectively.
Step 3: Now draw a ray QR.
Step 4: Taking Q as centre and radius equal to AD, draw an arc which meets QR at S.
Step 5: Taking S as centre and radius equal to DE, draw an arc which cuts the first arc at T.
Step 6: Join QT and produce it to P.
Hence, ∠PQR is the required angle equal to ∠A.
Question 2.
Draw an ∠XYZ equal to 90°. Using the compasses and ruler, draw YO the bisector of ∠XYZ. Measure ∠XYO and ∠ZYO. Are they equal?
Answer:
Step 1: Draw ∠XYZ = 90°
Step 2: Taking Y as centre and with suitable radius, draw an arc which meets YZ and XY at R and S respectively.
Step 3: Taking R and S as centres and radius equal to more than of SR, draw two arcs which intersects each other at T.
Step 4: Join YT and produce it to O.
Hence YO is the bisector of ∠XYZ such that ∠XYO = ∠ZYO = 45°
Question 3.
Draw ∠CAB = 150° using protractor. Using compasses, draw another angle equal to ∠CAB.
Answer:
Step 1: With the help of protractor draw ∠CAB = 150°. Draw an arc with centre A and suitable radius.
Step 2: Draw a ray PQ.
Step 3: Taking P as centre and radius equal to AD, draw an arc.
Step 4: This arc meets PQ at S.
Step 5: Taking centre S and radius equal to ED, draw an arc which meets the first arc at T.
Step 6: Join PT and produce it to R.
Hence ∠RPQ is the required angle such that ∠RPQ = ∠CAB = 150°