The DAV Class 5 Maths Book Solutions Pdf and **DAV Class 5 Maths Chapter 4 Worksheet 13** Solutions of Fractional Numbers offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 4 Worksheet 13 Solutions

Question 1.

Solve the following word problems.

(a) A piece of ribbon is 5\(\frac{3}{5}\) metres long. If it is cut into 14 equal pieces, what is the length of each piece?

Solution:

Length of ribbon = 5\(\frac{3}{5}\) metre = \(\frac{28}{5}\) metre

No. of pieces = 14

Length of each piece = \(\frac{28}{5}\) ÷ 14

= \(\frac{28}{5}\) × \(\frac{1}{14}\)

= \(\frac{2}{5}\) metre

Length of each piece is \(\frac{2}{5}\) metre.

(b) The product of two fractions is 9. If one of the fraction is 2\(\frac{1}{7}\), find the other fraction.

Solution:

Product of two fractions = 9

One fraction = 2\(\frac{1}{7}\) = \(\frac{15}{7}\)

Other fraction = Product of two fractions ÷ one fraction

= 9 ÷ 2\(\frac{1}{7}\)

= 9 ÷ \(\frac{15}{7}\)

= 9 × \(\frac{7}{15}\)

= \(\frac{21}{5}\)

= 4\(\frac{1}{5}\)

Other fraction is 4\(\frac{1}{5}\)

(c) It takes \(\frac{1}{2}\) minute to cook one dosa. How many dosas can be cooked in \(\frac{1}{4}\) hour?

Solution:

Time taken to cook one dosa = \(\frac{1}{2}\) min.

\(\frac{1}{4}\) h = \(\frac{1}{4}\) × 60 min. = 15 min.

In \(\frac{1}{2}\) minute no. of dosa cooked = 1

In 15 minute no. of dosa cooked = \(\frac{1}{2}\) ÷ 15

= \(\frac{2}{1}\) × 15

= 30 dosas

30 dosas can be cooked in \(\frac{1}{4}\) hour.

(d) Sheetal has 1\(\frac{3}{4}\) kg of sweets. She distributes \(\frac{1}{4}\) kg to each of her friends and finishes all the sweets. To how many friends did she distribute the sweets?

Solution:

Total quantity of sweets Sheetal has 1\(\frac{3}{4}\) kg = \(\frac{7}{4}\) kg

Distributes sweets to each of her friend = \(\frac{1}{4}\) kg

No. of friends, she distributes = Total quantity of sweets sweet each friend got

= \(\frac{7}{4} \div \frac{1}{4}\)

= \(\frac{7}{4} \times \frac{4}{1}\)

= 7

She distributes sweets to 7 friends.

(e) A pile of class-V mathematics books has a thickness of 14\(\frac{2}{5}\) cm. If each book is 1\(\frac{1}{5}\) cm thick, find how many column books make up the pile.

Solution:

Total thickness of Mathematics books = 14\(\frac{2}{5}\) cm = \(\frac{72}{5}\) cm

Thickness of one book = 1\(\frac{1}{5}\) cm = \(\frac{6}{5}\) cm

No. of books = Total thickness ÷ thickness of one book

= \(\frac{72}{5} \div \frac{6}{5}\)

= \(\frac{72}{5} \times \frac{5}{6}\)

= 12 books.

12 books make up the pile.

### DAV Class 5 Maths Chapter 4 Value Based Questions

It was lunch time. Teena and Meena gathered for lunch. They were to eat home-made pizza first. As they were about to start eating, they noticed that their friend Reema had not brought lunch and was hungry. So they decided to equally share the pizza with her. All of them were happy to share the food and enjoyed their lunch.

Question 1.

What fraction of pizza did each friend get?

Solution:

1 pizza is divided into part = 3

3 friends divided = 1 pizza

each friend get = 1 ÷ 3 = \(\frac{1}{3}\) part

Question 2.

What are things that you like to share with you friends?

Solution:

Things that we like to share with our friends are.

- Lunch
- Books
- Stationery
- Gifts (like stickers)

Word Problem

Example 1.

Rahul has \(\frac{3}{4}\) metre long rope. He was to cut it into three equal pieces. What is the length of each piece?

Solution:

Length of rope = \(\frac{3}{4}\) m

No. of pieces = 3

Length of each piece = \(\frac{3}{4}\) ÷ 3

= \(\frac{3}{4} \times \frac{1}{3}\)

= \(\frac{1}{4}\)

Length of each piece is \(\frac{1}{4}\) metre.