# DAV Class 5 Maths Chapter 11 Brain Teasers Solutions

The DAV Books Solutions Class 5 Maths and DAV Class 5 Maths Chapter 11 Brain Teasers Solutions of Profit and Loss offer comprehensive answers to textbook questions.

## DAV Class 5 Maths Ch 11 Brain Teasers Solutions

Question 1.
(a) If selling price = ₹ 6,085, profit = ₹ 1,289 then cost price is-
(i) ₹ 7,374
(ii) ₹ 7,264
(iii) ₹ 4,796
(iv) ₹ 4,804
Solution:
S.P. = ₹ 6,085
Profit = ₹ 1,289
C.P. = S.P. – Profit
= ₹ 6,085 – ₹ 1,289
= ₹ 4,796
Option (iii)

(b) If there is a loss in a transaction, which of the following is true?
(i) S.P. > C.P.
(ii) S.P. < C.P.
(iii) S.P. = C.P.
(iv) None of these
Solution:
S.P. < C.P.
i.e. Option (ii) (c) If cost price = ₹ 4,273, profit = ₹ 729 then, selling price is-
(i) ₹ 4,996
(ii) ₹ 5,002
(iii) ₹ 4,902
(iv) ₹ 5,992
Solution:
C.P. = ₹ 4,273
Profit = ₹ 729
S.P. = ₹ 4,273 + ₹ 729 = ₹ 5,002
Option (ii)

(d) Which of the following is true?
(i) S.P. + L = C.P.
(ii) S.P. -L = C.P.
(iii) C.P. – G = S.P.
(iv) S.P. + G = C.P.
Solution:
S.P. + L = C.P.
i.e. Option (i)

(e) If C.P. = ₹ 2,500, Transport Charges = ₹ 75, Gain = ₹ 225 the S.P. is-
(i) ₹ 2,350
(ii) ₹ 2,800
(iii) ₹ 2,725
(iv) ₹ 2,275
Solution:
C.P. = ₹ 2,500
Transport Charges = + ₹ 75
Actual C.P. = ₹ 2,575
Gain = ₹ 225
so S.P. > C.P.
S.P. = ₹ 2575 + ₹ 225 = ₹ 2,800
Option (ii)

Question 2.
Fill in the blanks. Solution:
(a) C.P. = ₹ 750
Transport Charges = ₹ 30
Actual C.P. = ₹ 750 + ₹ 30 = ₹ 780
S.P. = ₹ 900
Since S.P. > C.P., Profit will occur
Profit = SP. – C.P.
= ₹ 900 – ₹ 780
= ₹ 120 (b) C.P. = ₹ 10,200
Transport Charges = ₹ 75
Actual C.P. = ₹ 10,200 + ₹ 75 = ₹ 10,275
S.P. = ₹ 10,075
Since C.P. > S.P., Loss will occur
Loss = C.P. – S.P.
= ₹ 10,275 – ₹ 10,075
= ₹ 200

Question 3.
Fill in the blanks. Solution:
(a) Cost Price = ₹ 410
Selling price = ?
Profit = ₹ 75
Selling price = C.P. + Profit
= ₹ 410 + ₹ 75
= ₹ 485

(b) Cost Price = ₹ 3,400
Loss = ₹ 250
Selling Price = C.P. – Loss
= ₹ 3,400 – ₹ 250
= ₹ 3,150

(c) Cost Price = ₹ 70,800
Selling Price = ₹ 75,000
Since S.P. > C.P., Profit will occur
Profit = ₹ 75,000 – ₹ 70,800 = ₹ 4,200

(d) Selling Price = ₹ 890
Profit = ₹ 110
Cost Price = S.P. – Profit
= ₹ 890 – ₹ 110
= ₹ 780

(e) Selling Price = ₹ 4,850
Loss = ₹ 1,050
C.P. = S.P. + Loss
= ₹ 4,850 + ₹ 1,050
= ₹ 5,900 Question 4.
Sushil bought six dozen bananas at ₹ 35 per dozen. He sold all the bananas for ₹ 300. Did he have a gain or loss and how much?
Solution:
C.P. of 1 dozen bananas = ₹ 35
C.P. of 6 dozen bananas = ₹ 210
S.P. of 6 dozen bananas = ₹ 300
Since S.P. > C.P. Sushil makes a profit
Profit = ₹ 300 – ₹ 210 = ₹ 90
A profit of ₹ 90 will occur.

Question 5.
A man purchased seven stools and eight tables. The cost of one stool was ₹ 150 and the cost of one table was ₹ 280. If he sold all the stools and tables for ₹ 3100, find his gain or loss.
Solution:
Cost of 1 stool = ₹ 150
Cost of 7 stools = 150 × 7 = ₹ 1050
Cost of 1 table = ₹ 280
Cost of 8 tables = 8 × ₹ 280 = ₹ 2240
Total cost price of 7 stool & 8 tables = ₹ 1050 + ₹ 2240 = ₹ 3,290
S.P. of all the stools and tables = ₹ 3,100
Since S.P. < C.P. So loss will occur to man.
Loss = C.P. – S.P.
= ₹ 3290 – ₹ 3,100
= ₹ 190

Question 6.
An engineer spent ₹ 24,500 to assemble a computer. He sold it at a profit of ₹ 8,250. At what price did he sell it?
Solution:
C.P. of computer = ₹ 24,500
Profit = + ₹ 8,250
S.P. = ?
S.P. = C.P. + Profit
= ₹ 24,500 + ₹ 8,250
= ₹ 32,750 Question 7.
A man sold a bag for ₹ 75, at a loss of ₹ 12. Find the cost price of the bag.
Solution:
S.P. of bag = ₹ 75
Loss = ₹ 12
C.P. should be greater than S.P.
Cost Price = S.P. + Loss
= ₹ 75 + ₹ 12
= ₹ 87

Question 8.
Three dozen oranges were sold for ₹ 120. If there was a loss of ₹ 9, find the cost price of one dozen oranges.
Solution:
S.P. of 3 dozen oranges = ₹ 120
S.P. of 1 dozen oranges = ₹ 120 ÷ 3 = ₹ 40
Loss = 9
So C.P. > S.P.
C.P. = S.P. + Loss
= ₹ 40 + ₹ 9
= ₹ 49

Question 9.
Fill in the blanks.
(a) If the cost price of an article is greater than the selling price, we have a _________
Solution:
Loss

(b) Selling price = Cost price – _________
Solution:
Loss

(c) Cost price = Selling price – _________
Solution:
Profit

(d) Cost price + _________ = Selling price.
Solution:
Profit

(e) Selling price + _________ = Cost Price.
Solution:
Loss

Question 1.
Solve the following questions.
(a) C.P. = ₹ 340, S.P. = ₹ 550, Profit = ?, Loss = ?
Solution:
C.P. = ₹ 340
S.P. = ₹ 550
Since S.P. > C.P. we have a profit
Profit = S.P. – C.P.
= ₹ 550 – ₹ 340
= ₹ 210 (b) C.P. = ₹ 50, S.P. = ₹ 49, Profit = ?, Loss = ?
Solution:
C.P. = ₹ 50
S.P. = ₹ 49
Since S.P. < C.P. we have a loss
Loss = C.P. – S.P.
= ₹ 50 – ₹ 49
= ₹ 1

(c) C.P. = ₹ 176, S.P. = ₹ 150, Profit = ?, Loss = ?
Solution:
C.P. = ₹ 176
S.P. = ₹ 150
Since C.P. > S.P. loss has occurred
Loss = C.P. – S.P.
= ₹ 176 – ₹ 150
= ₹ 26

(d) C.P. = ₹ 2,340, ₹ S.P. = ₹ 2,130, Profit = ?, Loss = ?
Solution:
C.P. = ₹ 2,340
S.P. = ₹ 2,130
Since C.P. > S.P. we have a loss
Loss = C.P. – S.P.
= ₹ 2,340 – ₹ 2,130
= ₹ 210

(e) C.P. = ₹ 46.50, S.P. = ₹ 41.75, Profit = ?, Loss = ?
Solution:
C.P. = ₹ 46.50
S.P. = ₹ 41.75
Since C.P. > S.P. we have a loss
Loss = C.P. – S.P.
= ₹ 46.50 – ₹ 41.75
= ₹ 4.75

Question 2.
Find the selling price of the following.
(a) A shopkeeper purchased a toy bus for ₹ 275 and sold it at a gain of ₹ 25. Find the selling price of the bus.
Solution:
C.P. of toy bus = ₹ 275
Gain = ₹ 25
Since gain occurs S.P. > C.P.
S.P. of bus = ₹ 275 + ₹ 25 = ₹ 300

(b) C.P. = ₹ 1120, Gain = ₹ 50, S.P. = ?
Solution:
C.P. = ₹ 1120
Gain = ₹ 50
Since gain occurs S.P. > C.P.
S.P. = ₹ 1120 + ₹ 50 = ₹ 1170 Question 3.
Deepak sold a tape recorder for ₹ 1,700. He made a profit of ₹ 170. Find the cost price of the tape recorder.
Solution:
Deepak has made a profit of ₹ 170.
So the cost price will be less than S.P.
Selling Price = ₹ 1700
Profit = – ₹ 170
Cost Price = ₹ 1700 – ₹ 170 = ₹ 1530
Thus, the C.P. of the tape recorder is ₹ 1530

Question 4.
Sahil sold a toothpaste for ₹ 95 at a loss of ₹ 12. Find the cost price of the toothpaste.
Solution:
Sahil has made a loss of ₹ 12.
So the cost price should be more than the selling price.
Selling Price = ₹ 95
Loss = ₹ 12
Cost Price = ₹ 95 + ₹ 12 = ₹ 107
Thus C.P. of toothpaste is ₹ 107

Question 5.
Find S.P. if C.P. = ₹ 3,500, transport charges = ₹ 75, Gain = ₹ 220.
Solution:
C.P. = ₹ 3,500
Transport Charges = ₹ 75
Actual C.P. = ₹ 3575
As gain occurs so S.P. > C.P.
S.P. = C.P. + Gain
= ₹ 3575 + ₹ 220
= ₹ 3795 Question 6.
Fill in the blanks.
(a) If the C.P. of the article is less than the selling price we have a _________
Solution:
Gain

(b) Cost Price = Selling Price + _________
Solution:
Loss

(c) Selling price – Gain = _________
Solution:
Cost Price

(d) Cost Price – _________ = Selling Price.
Solution:
Gain