The DAV Maths Book Class 3 Solutions and **DAV Class 3 Maths Chapter 11 Worksheet 5** Solutions of Fractions offer comprehensive answers to textbook questions.

## DAV Class 3 Maths Ch 11 WS 5 Solutions

Question 1.

Find the difference.

(a) \(\frac{7}{9}-\frac{2}{9}\)

Solution:

\(\frac{7}{9}-\frac{2}{9}\)

= \(\frac{7-2}{9}\)

= \(\frac{5}{9}\)

(b) \(\frac{7}{10}-\frac{4}{10}\)

Solution:

\(\frac{7}{10}-\frac{4}{10}\)

= \(\frac{7-4}{10}\)

= \(\frac{3}{10}\)

(c) \(\frac{5}{8}-\frac{3}{8}\)

Solution:

\(\frac{5}{8}-\frac{3}{8}\)

= \(\frac{5-3}{8}\)

= \(\frac{2}{8}\)

(d) \(\frac{5}{7}-\frac{1}{7}\)

Solution:

\(\frac{5}{7}-\frac{1}{7}\)

= \(\frac{5-1}{7}\)

= \(\frac{4}{7}\)

(e) \(\frac{4}{5}-\frac{3}{5}\)

Solution:

\(\frac{4}{5}-\frac{3}{5}\)

= \(\frac{4-3}{5}\)

= \(\frac{1}{5}\)

(f) \(\frac{8}{9}-\frac{3}{9}\)

Solution:

\(\frac{8}{9}-\frac{3}{9}\)

= \(\frac{8-3}{9}\)

= \(\frac{5}{9}\)

Question 2.

Subtract the following fractions:

(a) \(\frac{2}{8}\) from \(\frac{6}{8}\)

Solution:

\(\frac{6}{8}-\frac{2}{8}\)

= \(\frac{6-2}{8}\)

= \(\frac{4}{8}\)

(b) \(\frac{8}{9}\) from \(\frac{9}{9}\)

Solution:

\(\frac{9}{9}-\frac{8}{9}\)

= \(\frac{9-8}{9}\)

= \(\frac{1}{9}\)

(c) \(\frac{3}{7}\) from \(\frac{6}{7}\)

Solution:

\(\frac{6}{7}-\frac{3}{7}\)

= \(\frac{6-3}{7}\)

= \(\frac{3}{7}\)

(d) \(\frac{3}{8}\) from \(\frac{7}{8}\)

Solution:

\(\frac{7}{8}-\frac{3}{8}\)

= \(\frac{7-3}{8}\)

= \(\frac{4}{8}\)

(e) \(\frac{1}{10}\) from \(\frac{9}{10}\)

Solution:

\(\frac{9}{10}-\frac{1}{10}\)

= \(\frac{9-1}{10}\)

= \(\frac{8}{10}\)

(f) \(\frac{2}{5}\) from \(\frac{4}{5}\)

Solution:

\(\frac{4}{5}-\frac{2}{5}\)

= \(\frac{4-2}{5}\)

= \(\frac{2}{5}\)

Question 3.

Colour squares to show the correct answer.

(a) \(\frac{3}{5}-\frac{1}{5}\) =

Solution:

\(\frac{2}{5}\) =

(b) \(\frac{1}{4}-\frac{1}{4}\) =

Solution:

0 =

(c) \(\frac{7}{9}-\frac{2}{9}\) =

Solution:

\(\frac{5}{9}\) =

(d) \(\frac{3}{3}-\frac{2}{3}\) =

Solution:

\(\frac{1}{3}\) =

(e) \(\frac{5}{10}-\frac{4}{10}\) =

Solution:

\(\frac{1}{10}\) =

(f) \(\frac{9}{9}-\frac{6}{9}\) =

Solution:

\(\frac{3}{9}\) =

### DAV Class 3 Maths Chapter 11 Value Based Questions

There was a fair …………………. by the police.

Question 1.

What fraction of the victims were rescued?

Solution:

Authorities sent victims to hospital = \(\frac{4}{7}\)

Fraction of victims sent to hospital by villagers = \(\frac{2}{7}\)

Fraction of victims were rescued = \(\frac{4}{7}\) + \(\frac{2}{7}\)

= \(\frac{6}{7}\)

Question 2.

If you were in that situation what would you have done?

Solution:

I would have moved to a safer place and ask others also to be calm.

Question 3.

What precautions can be taken while visiting a fair or a crowded place?

Solution:

While vising any fair or a crowded place, we should be calm and must know all emergency numbers in case any emergency occurs. We should always visit these places with our elders.

### DAV Class 3 Maths Chapter 11 Worksheet 5 Notes

E.g. Subtract \(\frac{1}{3}\) from \(\frac{7}{3}\)

Solution:

\(\frac{7}{3}\) – \(\frac{1}{3}\)

= \(\frac{7-1}{3}\)

= \(\frac{6}{3}\)

Subtract the numerators.

Keep the dcnominator as it is.