DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

The DAV Maths Book Class 3 Solutions and DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions of Fractions offer comprehensive answers to textbook questions.

DAV Class 3 Maths Ch 11 WS 5 Solutions

Question 1.
Find the difference.

(a) \(\frac{7}{9}-\frac{2}{9}\)
Solution:
\(\frac{7}{9}-\frac{2}{9}\)
= \(\frac{7-2}{9}\)
= \(\frac{5}{9}\)

(b) \(\frac{7}{10}-\frac{4}{10}\)
Solution:
\(\frac{7}{10}-\frac{4}{10}\)
= \(\frac{7-4}{10}\)
= \(\frac{3}{10}\)

(c) \(\frac{5}{8}-\frac{3}{8}\)
Solution:
\(\frac{5}{8}-\frac{3}{8}\)
= \(\frac{5-3}{8}\)
= \(\frac{2}{8}\)

DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

(d) \(\frac{5}{7}-\frac{1}{7}\)
Solution:
\(\frac{5}{7}-\frac{1}{7}\)
= \(\frac{5-1}{7}\)
= \(\frac{4}{7}\)

(e) \(\frac{4}{5}-\frac{3}{5}\)
Solution:
\(\frac{4}{5}-\frac{3}{5}\)
= \(\frac{4-3}{5}\)
= \(\frac{1}{5}\)

(f) \(\frac{8}{9}-\frac{3}{9}\)
Solution:
\(\frac{8}{9}-\frac{3}{9}\)
= \(\frac{8-3}{9}\)
= \(\frac{5}{9}\)

DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

Question 2.
Subtract the following fractions:

(a) \(\frac{2}{8}\) from \(\frac{6}{8}\)
Solution:
\(\frac{6}{8}-\frac{2}{8}\)
= \(\frac{6-2}{8}\)
= \(\frac{4}{8}\)

(b) \(\frac{8}{9}\) from \(\frac{9}{9}\)
Solution:
\(\frac{9}{9}-\frac{8}{9}\)
= \(\frac{9-8}{9}\)
= \(\frac{1}{9}\)

(c) \(\frac{3}{7}\) from \(\frac{6}{7}\)
Solution:
\(\frac{6}{7}-\frac{3}{7}\)
= \(\frac{6-3}{7}\)
= \(\frac{3}{7}\)

DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

(d) \(\frac{3}{8}\) from \(\frac{7}{8}\)
Solution:
\(\frac{7}{8}-\frac{3}{8}\)
= \(\frac{7-3}{8}\)
= \(\frac{4}{8}\)

(e) \(\frac{1}{10}\) from \(\frac{9}{10}\)
Solution:
\(\frac{9}{10}-\frac{1}{10}\)
= \(\frac{9-1}{10}\)
= \(\frac{8}{10}\)

(f) \(\frac{2}{5}\) from \(\frac{4}{5}\)
Solution:
\(\frac{4}{5}-\frac{2}{5}\)
= \(\frac{4-2}{5}\)
= \(\frac{2}{5}\)

DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

Question 3.
Colour squares to show the correct answer.

(a) \(\frac{3}{5}-\frac{1}{5}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 1

Solution:

\(\frac{2}{5}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 2

(b) \(\frac{1}{4}-\frac{1}{4}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 3

Solution:

0 = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 4

(c) \(\frac{7}{9}-\frac{2}{9}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 5

Solution:

\(\frac{5}{9}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 6

DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

(d) \(\frac{3}{3}-\frac{2}{3}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 7

Solution:

\(\frac{1}{3}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 8

(e) \(\frac{5}{10}-\frac{4}{10}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 9

Solution:

\(\frac{1}{10}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 10

(f) \(\frac{9}{9}-\frac{6}{9}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 11

Solution:

\(\frac{3}{9}\) = DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions 12

DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

DAV Class 3 Maths Chapter 11 Value Based Questions

There was a fair …………………. by the police.

Question 1.
What fraction of the victims were rescued?
Solution:
Authorities sent victims to hospital = \(\frac{4}{7}\)
Fraction of victims sent to hospital by villagers = \(\frac{2}{7}\)
Fraction of victims were rescued = \(\frac{4}{7}\) + \(\frac{2}{7}\)
= \(\frac{6}{7}\)

Question 2.
If you were in that situation what would you have done?
Solution:
I would have moved to a safer place and ask others also to be calm.

Question 3.
What precautions can be taken while visiting a fair or a crowded place?
Solution:
While vising any fair or a crowded place, we should be calm and must know all emergency numbers in case any emergency occurs. We should always visit these places with our elders.

DAV Class 3 Maths Chapter 11 Worksheet 5 Solutions

DAV Class 3 Maths Chapter 11 Worksheet 5 Notes

E.g. Subtract \(\frac{1}{3}\) from \(\frac{7}{3}\)
Solution:
\(\frac{7}{3}\) – \(\frac{1}{3}\)
= \(\frac{7-1}{3}\)
= \(\frac{6}{3}\)

Subtract the numerators.
Keep the dcnominator as it is.