# Tamilnadu Board Class 9 Maths Solutions Chapter 2 Real Numbers Ex 2.3

## Tamilnadu State Board Class 9 Maths Solutions Chapter 2 Real Numbers Ex 2.3

Question 1.
Represent the following irrational numbers on the number line.
(i) √3
(ii) $$\sqrt { 4.7 }$$
(iii) $$\sqrt { 6.5 }$$
Solution:
(i) √3 (i) Draw a line and mark a point A on it.
(ii) Mark a point B such that AB = 3 cm.
(iii) Mark a point C on this line such that BC = 1 unit.
(iv) Find the midpoint of AC by drawing perpendicular bisector of AC and let it be O.
(v) With O as center and OC = OA as radius, draw a semicircle.
(vi) Draw a line BD, which is perpendicular to AB at B.
(vii) Now BD = √3, which can be marked in the number line as the value of BE = BD = √3

(ii) $$\sqrt { 4.7 }$$ (i) Draw a line and mark a point A on it.
(ii) Mark a point B such that AB = 4.7 cm.
(iii) Mark a point C on this line such that BC = 1 unit.
(iv) Find the midpoint of AC by drawing perpendicular bisector of AC and let it be O.
(v) With O as center and OC = OA as radius, draw a semicircle.
(vi) Draw a line BD, which is perpendicular to AB at B.
(vii) Now BD = $$\sqrt { 4.7 }$$, which can be marked in the number line as the value of BE = BD = $$\sqrt { 4.7 }$$

(iii) $$\sqrt { 6.5 }$$ (i) Draw a line and mark a point A on it.
(ii) Mark a point B such that AB = 6.5 cm.
(iii) Mark a point C on this line such that BC = 1 unit.
(iv) Find the midpoint of AC by drawing perpendicular bisector of AC and let it be O.
(v) With O as center and OC = OA as radius, draw a semicircle.
(vi) Draw a line BD, which is perpendicular to AB at B.
(vii) Now BD = $$\sqrt { 6.5 }$$, which can be marked in the number line as the value of BE = BD = $$\sqrt { 6.5 }$$.

Question 2.
Find any two irrational numbers between
(i) 0.3010011000111…. and 0.3020020002….
(ii) $$\frac { 6 }{ 7 }$$ and $$\frac { 12 }{ 13 }$$
(iii) √2 and √3
Solution:
(i) 0.3010011000111…. and 0.3020020002….
Two irrational numbers 0.301202200222 …., 0.301303300333…..

(ii) $$\frac { 6 }{ 7 }$$ and $$\frac { 12 }{ 13 }$$
$$\frac { 6 }{ 7 }$$ = 0.857142…
$$\frac { 12 }{ 13 }$$ = 0.923076
Two irrational numbers between 0.8616611666111……, 0.8717711777111…..

(iii) √2 and √3 √2 = 1.414…… √3 = 1.732….
∴ Two irrational numbers between 1.5155…., 1.6166…….

Question 3.
Find any two rational numbers between 2.2360679….. and 2.236505500….
Solution:
Any two rational numbers are 2.2362, 2.2363