## ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 12 Equation of a Straight Line MCQS

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 12 Equation of a Straight Line MCQS

Choose the correct answer from the given four options (1 to 13):

Question 1.

The slope of a line parallel to y-axis is

(a) 0

(b) 1

(c) -1

(d) not defined

Solution:

Question 2.

The slope of a line which makes an angle of 30° with the positive direction of x-axis is

(a) 1

(b) \(\frac { 1 }{ \sqrt { 3 } } \)

(c) √3

(d) \(– \frac { 1 }{ \sqrt { 3 } } \)

Solution:

Question 3.

The slope of the line passing through the points (0, -4) and (-6, 2) is

(a) 0

(b) 1

(c) -1

(d) 6

Solution:

Question 4.

The slope of the line passing through the points (3, -2) and (-7, -2) is

(a) 0

(b) 1

(c) \(– \frac { 1 }{ 10 } \)

(d) not defined

Solution:

Question 5.

The slope of the line passing through the points (3, -2) and (3, -4) is

(a) -2

(b) 0

(c) 1

(d) not defined

Solution:

Question 6.

The inclination of the line y = √3x – 5 is

(a) 30°

(b) 60°

(c) 45°

(d) 0°

Solution:

Question 7.

If the slope of the line passing through the points (2, 5) and (k, 3) is 2, then the value of k is

(a) -2

(b) -1

(c) 1

(d) 2

Solution:

Question 8.

The slope of a line parallel to the line passing through the points (0, 6) and (7, 3) is

(a) \(– \frac { 1 }{ 5 } \)

(b) \(\\ \frac { 1 }{ 5 } \)

(c) -5

(d) 5

Solution:

Question 9.

The slope of a line perpendicular to the line passing through the points (2, 5) and (-3, 6) is

(a) \(– \frac { 1 }{ 5 } \)

(b) \(\\ \frac { 1 }{ 5 } \)

(c) -5

(d) 5

Solution:

Question 10.

The slope of a line parallel to the line 2x + 3y – 7 = 0 is

(a) \(– \frac { 2 }{ 3 } \)

(b) \(\\ \frac { 2 }{ 3 } \)

(c) \(– \frac { 3 }{ 2 } \)

(d) \(\\ \frac { 3 }{ 2 } \)

Solution:

Question 11.

The slope of a line perpendicular to the line 3x = 4y + 11 is

(a) \(\\ \frac { 3 }{ 4 } \)

(b) \(– \frac { 3 }{ 4 } \)

(c) \(\\ \frac { 4 }{ 3 } \)

(d) \(– \frac { 4 }{ 3 } \)

Solution:

Question 12.

If the lines 2x + 3y = 5 and kx – 6y = 7 are parallel, then the value of k is

(a) 4

(b) -4

(c) \(\\ \frac { 1 }{ 4 } \)

(d) \(– \frac { 1 }{ 4 } \)

Solution:

Question 13.

If the line 3x – 4y + 7 = 0 and 2x + ky + 5 = 0 are perpendicular to each other, then the value of k is

(a) \(\\ \frac { 3 }{ 2 } \)

(b) \(– \frac { 3 }{ 2 } \)

(c) \(\\ \frac { 2 }{ 3 } \)

(d) \(– \frac { 2 }{ 3 } \)

Solution: